ChemistryQ51–55 of 105 questions
Page 2 of 2 · English
51
ChemistryMCQNEET · 2022
In gene therapy of adenosine deaminase $\text{(ADA)}$ deficiency,the patient requires periodic infusion of genetically engineered lymphocytes because:
A
Gene isolated from marrow cells producing $\text{ADA}$ is introduced into cells at embryonic stages.
B
Lymphocytes from patient's blood are grown in culture,outside the body.
C
Retroviral vector is introduced into these lymphocytes.
D
Genetically engineered lymphocytes are not immortal cells.
Solution
(D) In the gene therapy for $\text{ADA}$ deficiency,functional $\text{ADA}$ $\text{cDNA}$ is introduced into the patient's lymphocytes using a retroviral vector.
These genetically engineered lymphocytes are then reintroduced into the patient.
However,these lymphocytes are not immortal,meaning they have a finite lifespan and eventually die.
Therefore,the patient requires periodic infusions of these genetically engineered cells to maintain the production of the $\text{ADA}$ enzyme.
These genetically engineered lymphocytes are then reintroduced into the patient.
However,these lymphocytes are not immortal,meaning they have a finite lifespan and eventually die.
Therefore,the patient requires periodic infusions of these genetically engineered cells to maintain the production of the $\text{ADA}$ enzyme.
0 likesView Solution
52
ChemistryMCQNEET · 2022
Western Ghats have a large number of plant and animal species that are not found anywhere else. Which of the following terms is used to denote such species?
A
Keystone species
B
Endemic species
C
Vulnerable species
D
Threatened species
Solution
(B) Species that are confined to a specific geographic region and are not found anywhere else in the world are known as $Endemic$ species.
Western Ghats are a biodiversity hotspot known for a high degree of endemism,meaning many of its flora and fauna are unique to that region.
$Keystone$ species are those that have a disproportionately large effect on their environment relative to their abundance.
$Vulnerable$ and $Threatened$ species refer to the conservation status of organisms based on their risk of extinction,not their geographic distribution.
Western Ghats are a biodiversity hotspot known for a high degree of endemism,meaning many of its flora and fauna are unique to that region.
$Keystone$ species are those that have a disproportionately large effect on their environment relative to their abundance.
$Vulnerable$ and $Threatened$ species refer to the conservation status of organisms based on their risk of extinction,not their geographic distribution.
0 likesView Solution
53
ChemistryMCQNEET · 2022
When electromagnetic radiation of wavelength $300 \ nm$ falls on the surface of a metal,electrons are emitted with the kinetic energy of $1.68 \times 10^5 \ J \ mol^{-1}$. What is the minimum energy needed to remove an electron from the metal? $(h = 6.626 \times 10^{-34} \ J \ s, c = 3 \times 10^8 \ m \ s^{-1}, N_A = 6.022 \times 10^{23} \ mol^{-1})$
A
$2.31 \times 10^6 \ J \ mol^{-1}$
B
$3.84 \times 10^4 \ J \ mol^{-1}$
C
$3.84 \times 10^{-19} \ J \ mol^{-1}$
D
$2.31 \times 10^5 \ J \ mol^{-1}$
Solution
(D) The energy of one photon is given by $E = \frac{hc}{\lambda}$.
Substituting the values: $E = \frac{(6.626 \times 10^{-34} \ J \ s)(3 \times 10^8 \ m \ s^{-1})}{300 \times 10^{-9} \ m} = 6.626 \times 10^{-19} \ J$.
For $1 \ mol$ of photons,the total energy is $E_{total} = E \times N_A = 6.626 \times 10^{-19} \times 6.022 \times 10^{23} \approx 3.99 \times 10^5 \ J \ mol^{-1}$.
According to the photoelectric effect equation,$E_{total} = \Phi + K.E.$,where $\Phi$ is the work function (minimum energy).
$\Phi = E_{total} - K.E. = 3.99 \times 10^5 \ J \ mol^{-1} - 1.68 \times 10^5 \ J \ mol^{-1} = 2.31 \times 10^5 \ J \ mol^{-1}$.
Substituting the values: $E = \frac{(6.626 \times 10^{-34} \ J \ s)(3 \times 10^8 \ m \ s^{-1})}{300 \times 10^{-9} \ m} = 6.626 \times 10^{-19} \ J$.
For $1 \ mol$ of photons,the total energy is $E_{total} = E \times N_A = 6.626 \times 10^{-19} \times 6.022 \times 10^{23} \approx 3.99 \times 10^5 \ J \ mol^{-1}$.
According to the photoelectric effect equation,$E_{total} = \Phi + K.E.$,where $\Phi$ is the work function (minimum energy).
$\Phi = E_{total} - K.E. = 3.99 \times 10^5 \ J \ mol^{-1} - 1.68 \times 10^5 \ J \ mol^{-1} = 2.31 \times 10^5 \ J \ mol^{-1}$.
0 likesView Solution
54
ChemistryDifficultMCQNEET · 2022
Given below are two statements:
Statement $I$: $Cr^{2+}$ is oxidising and $Mn^{3+}$ is reducing in nature.
Statement $II$: $Sc^{3+}$ compounds are repelled by the applied magnetic field.
In the light of the above statements,choose the most appropriate answer from the options given below:
Statement $I$: $Cr^{2+}$ is oxidising and $Mn^{3+}$ is reducing in nature.
Statement $II$: $Sc^{3+}$ compounds are repelled by the applied magnetic field.
In the light of the above statements,choose the most appropriate answer from the options given below:
A
Both Statement $I$ and Statement $II$ are correct
B
Both Statement $I$ and Statement $II$ are incorrect
C
Statement $I$ is correct but Statement $II$ is incorrect
D
Statement $I$ is incorrect but Statement $II$ is correct
Solution
(D) Statement $I$ is incorrect because $Cr^{2+}$ $(3d^4)$ is a reducing agent as it changes to $Cr^{3+}$ ($3d^3$,stable $t_{2g}^3$ configuration),and $Mn^{3+}$ $(3d^4)$ is an oxidising agent as it changes to $Mn^{2+}$ ($3d^5$,stable half-filled $d^5$ configuration).
Statement $II$ is correct because $Sc^{3+}$ has a $3d^0$ configuration,meaning it has no unpaired electrons. Therefore,it is diamagnetic and is repelled by an applied magnetic field.
Statement $II$ is correct because $Sc^{3+}$ has a $3d^0$ configuration,meaning it has no unpaired electrons. Therefore,it is diamagnetic and is repelled by an applied magnetic field.
0 likesView Solution
55
ChemistryMediumMCQNEET · 2022
Standard electrode potential for the cell with cell reaction $Zn_{(s)} + Cu^{2+}_{(aq)} \rightarrow Zn^{2+}_{(aq)} + Cu_{(s)}$ is $1.1 \ V$. Calculate the standard Gibbs energy change for the cell reaction. (Given $F = 96487 \ C \ mol^{-1}$)
A
$-200.27 \ kJ \ mol^{-1}$
B
$-212.27 \ kJ \ mol^{-1}$
C
$-212.27 \ J \ mol^{-1}$
D
$-200.27 \ J \ mol^{-1}$
Solution
(B) The formula for standard Gibbs energy change is $\Delta G^{\circ} = -nFE^{\circ}_{cell}$.
Here,$n = 2$ (number of electrons transferred in the reaction).
$E^{\circ}_{cell} = 1.1 \ V$.
$F = 96487 \ C \ mol^{-1}$.
Substituting the values: $\Delta G^{\circ} = -2 \times 96487 \times 1.1 \ C \cdot V \ mol^{-1}$.
$\Delta G^{\circ} = -212271.4 \ J \ mol^{-1}$.
Converting to $kJ \ mol^{-1}$: $\Delta G^{\circ} = \frac{-212271.4}{1000} \approx -212.27 \ kJ \ mol^{-1}$.
Here,$n = 2$ (number of electrons transferred in the reaction).
$E^{\circ}_{cell} = 1.1 \ V$.
$F = 96487 \ C \ mol^{-1}$.
Substituting the values: $\Delta G^{\circ} = -2 \times 96487 \times 1.1 \ C \cdot V \ mol^{-1}$.
$\Delta G^{\circ} = -212271.4 \ J \ mol^{-1}$.
Converting to $kJ \ mol^{-1}$: $\Delta G^{\circ} = \frac{-212271.4}{1000} \approx -212.27 \ kJ \ mol^{-1}$.
0 likesView Solution
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real NEET style covering Chemistry with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D Chemistry papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Run live NEET mock exams with unlimited students, 360° analytics & white-label branding.
See DemoFrequently Asked Questions
How many Chemistry questions are in NEET 2022?
There are 105 Chemistry questions from the NEET 2022 paper on Vedclass, each with a detailed step-by-step solution in English.
Are NEET 2022 Chemistry solutions available in English?
Yes. All solutions on this page are in English. You can also switch to English or Hindi using the language buttons above the questions.
Can I practice NEET 2022 Chemistry as a timed test?
Yes. Use the Vedclass Test Series to attempt a full NEET mock test covering Chemistry with time limits and instant score analysis.
Can teachers create Chemistry papers from NEET previous year questions?
Yes. The Vedclass Exam Paper Generator lets teachers mix NEET Chemistry questions and generate Set A/B/C/D papers in minutes.
For Teachers & Institutes
Build a Custom Chemistry Paper
Pick NEET 2022 Chemistry questions, set difficulty, and generate Set A/B/C/D in 2 minutes.