Standard electrode potential for the cell with cell reaction $Zn_{(s)} + Cu^{2+}_{(aq)} \rightarrow Zn^{2+}_{(aq)} + Cu_{(s)}$ is $1.1 \ V$. Calculate the standard Gibbs energy change for the cell reaction. (Given $F = 96487 \ C \ mol^{-1}$)
- A$-200.27 \ kJ \ mol^{-1}$
- B$-212.27 \ kJ \ mol^{-1}$
- C$-212.27 \ J \ mol^{-1}$
- D$-200.27 \ J \ mol^{-1}$
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