NEET 2018 Biology Question Paper with Answer and Solution

89 QuestionsEnglishWith Solutions

BiologyQ189 of 89 questions

Page 1 of 1 · English

1
BiologyMediumMCQNEET · 2018
Which of the following hormones can play a significant role in osteoporosis?
A
Estrogen and parathyroid hormone
B
Aldosterone and Prolactin
C
Parathyroid hormone and prolactin
D
Progesterone and Aldosterone

Solution

(A) Osteoporosis is a condition characterized by a decrease in bone mass and increased fragility of bones.
$1$. Estrogen is crucial for maintaining bone density in women; a decline in estrogen levels after menopause leads to increased bone resorption.
$2$. Parathyroid hormone $(PTH)$ regulates calcium levels in the blood. Excess $PTH$ stimulates osteoclasts to break down bone tissue to release calcium into the bloodstream,which can lead to bone loss.
Therefore,both estrogen and parathyroid hormone play a significant role in the development of osteoporosis.
2
BiologyMediumMCQNEET · 2018
Which of the following is an amino acid derived hormone?
A
Estriol
B
Epinephrine
C
Estradiol
D
Ecdysone

Solution

(B) Hormones are classified based on their chemical nature into peptide,steroid,iodothyronines,and amino acid derivatives.
$1$. $Estriol$ and $Estradiol$ are steroid hormones derived from cholesterol.
$2$. $Ecdysone$ is a steroid hormone found in insects.
$3$. $Epinephrine$ (also known as adrenaline) is an amino acid derivative,specifically synthesized from the amino acid $Tyrosine$.
Therefore,the correct option is $B$.
3
BiologyMediumMCQNEET · 2018
Which of the following structures or regions is incorrectly paired with its function?
A
Corpus callosum : band of fibers connecting left and right cerebral hemispheres
B
Medulla oblongata: Controls respiration and cardiovascular reflexes
C
Hypothalamus: Production of releasing hormones and regulation of temperature,hunger and thirst
D
Limbic system: Consists of fibre tracts that interconnect different regions of brain; controls movement.

Solution

(D) The $Limbic$ $system$ is a complex structure in the brain involved in the regulation of sexual behavior,expression of emotional reactions (e.g.,excitement,pleasure,rage,and fear),and motivation. It does not control voluntary movement; voluntary movement is primarily controlled by the motor cortex and the cerebellum. Therefore,the pairing in option $D$ is incorrect. All other options correctly describe the functions of the respective brain structures.
4
BiologyEasyMCQNEET · 2018
The transparent lens in the human eye is held in its place by:
A
Smooth muscles attached to the ciliary body
B
Ligaments attached to the ciliary body
C
Smooth muscles attached to the iris
D
Ligaments attached to the iris

Solution

(B) The human eye contains a transparent,crystalline lens.
This lens is held in its position by suspensory ligaments.
These ligaments are attached to the ciliary body,which is an extension of the choroid.
The ciliary body contains ciliary muscles that control the shape of the lens by adjusting the tension on these ligaments,thereby facilitating accommodation for near and far vision.
5
BiologyMediumMCQNEET · 2018
Which of the following gastric cells indirectly help in erythropoiesis?
A
Chief cells
B
Parietal cells
C
Goblet cells
D
Mucous cells

Solution

(B) The $Parietal$ cells (also known as $Oxyntic$ cells) present in the gastric glands secrete $Intrinsic$ $Factor$ ($Castle's$ $Intrinsic$ $Factor$).
This factor is essential for the absorption of $Vitamin$ $B_{12}$ in the ileum of the small intestine.
$Vitamin$ $B_{12}$ is a crucial co-factor required for the maturation of red blood cells $(RBCs)$ in the bone marrow.
Therefore,by facilitating the absorption of $Vitamin$ $B_{12}$,$Parietal$ cells indirectly support the process of erythropoiesis.
6
BiologyMediumMCQNEET · 2018
Match the items given in Column $I$ with those in Column $II$ and select the correct option given below:
Column $I$Column $II$
$(a)$ Fibrinogen$(i)$ Osmotic balance
$(b)$ Globulin$(ii)$ Blood clotting
$(c)$ Albumin$(iii)$ Defence mechanism
A
$a-ii, b-iii, c-i$
B
$a-iii, b-ii, c-i$
C
$a-i, b-iii, c-ii$
D
$a-i, b-ii, c-iii$

Solution

(A) The plasma proteins play specific roles in the human body:
$1$. Fibrinogen: These are proteins needed for clotting or coagulation of blood. Thus, $(a)$ matches with $(ii)$.
$2$. Globulin: These are primarily involved in the defence mechanisms of the body (e.g., immunoglobulins/antibodies). Thus, $(b)$ matches with $(iii)$.
$3$. Albumin: These proteins help in maintaining the osmotic balance of the blood. Thus, $(c)$ matches with $(i)$.
Therefore, the correct matching is $a-ii, b-iii, c-i$.
7
BiologyEasyMCQNEET · 2018
Which of the following is an occupational respiratory disorder?
A
Emphysema
B
Anthracis
C
Botulism
D
Silicosis

Solution

(D) Occupational respiratory disorders are conditions caused by the inhalation of harmful substances (such as dust, fumes, or gases) present in the workplace environment.
$Silicosis$ is a classic example of an occupational respiratory disorder caused by the inhalation of silica dust, which leads to inflammation and fibrosis of the lung tissue.
$Emphysema$ is primarily caused by cigarette smoking.
$Anthracis$ refers to a bacterial infection caused by $Bacillus$ \text{ anthracis}.
$Botulism$ is a rare but serious illness caused by a toxin that attacks the body's nerves.
8
BiologyMediumMCQNEET · 2018
Calcium is important in skeletal muscle contraction because it
A
Prevents the formation of bonds between the myosin cross bridge and the actin filament.
B
Binds to troponin to remove the masking of active sites on actin.
C
Detaches the myosin head from the actin filament.
D
Activates the myosin $ATPase$ by binding to it.

Solution

(B) During skeletal muscle contraction,the binding of $Ca^{2+}$ ions to the $Troponin$ complex is a critical step.
In a relaxed state,the active sites on the actin filament are masked by the $Tropomyosin$ protein.
When $Ca^{2+}$ ions are released from the sarcoplasmic reticulum,they bind to $Troponin$.
This binding causes a conformational change in the $Troponin-Tropomyosin$ complex,which shifts the $Tropomyosin$ away from the active sites on the actin filament.
This exposure allows the myosin heads to bind to the actin,forming cross-bridges and initiating muscle contraction.
9
BiologyEasyMCQNEET · 2018
Nissl bodies are mainly composed of
A
Nucleic acids and $SER$
B
Proteins and lipids
C
Free ribosomes and $RER$
D
$DNA$ and $RNA$

Solution

(C) Nissl bodies (also known as Nissl substance or chromatophilic substance) are large granular bodies found in neurons.
They are primarily composed of rough endoplasmic reticulum $(RER)$ and free ribosomes.
These structures are the sites of protein synthesis within the nerve cell,which is essential for the maintenance and repair of the neuron.
10
BiologyMediumMCQNEET · 2018
Which of these statements is incorrect?
A
Glycolysis operates as long as it is supplied with $NAD^+$ that can pick up hydrogen atoms.
B
Enzymes of $TCA$ cycle are present in the mitochondrial matrix.
C
Oxidative phosphorylation takes place in the outer mitochondrial membrane.
D
Glycolysis occurs in the cytosol.

Solution

(C) The correct answer is $C$.
$1$. Glycolysis requires $NAD^+$ to act as an electron acceptor to form $NADH + H^+$.
$2$. The enzymes of the $TCA$ cycle (Krebs cycle) are located in the mitochondrial matrix.
$3$. Oxidative phosphorylation (the electron transport system) takes place in the inner mitochondrial membrane,not the outer membrane.
$4$. Glycolysis occurs in the cytosol of the cell.
11
BiologyMediumMCQNEET · 2018
Select the incorrect match:
A
Polytene chromosomes - Oocytes of amphibians
B
Lampbrush chromosomes - Diplotene bivalents
C
Submetacentric chromosomes - $L$-shaped chromosomes
D
Allosomes - Sex chromosomes

Solution

(A) Polytene chromosomes are giant chromosomes found in the salivary glands of Drosophila (fruit fly) larvae and some other dipteran insects,not in the oocytes of amphibians.
Lampbrush chromosomes are observed in the diplotene stage of meiotic prophase-$I$ in the oocytes of many vertebrates,including amphibians.
Submetacentric chromosomes have a centromere slightly away from the center,resulting in unequal arms,which gives them an $L$-shape during anaphase.
Allosomes are the chromosomes that determine the sex of an organism,commonly known as sex chromosomes.
Therefore,the incorrect match is Polytene chromosomes - Oocytes of amphibians.
12
BiologyEasyMCQNEET · 2018
Which of the following terms describes human dentition?
A
Pleurodont,Diphyodont,Heterodont
B
Thecodont,Diphyodont,homodont
C
Pleurodont,monophyodont,homodont
D
Thecodont,Diphyodont,Heterodont

Solution

(D) Human dentition is characterized by three main features:
$1$. $Thecodont$: The teeth are embedded in the sockets of the jaw bone.
$2$. $Diphyodont$: Two sets of teeth are formed during the life of an individual,a set of temporary milk or deciduous teeth replaced by a set of permanent or adult teeth.
$3$. $Heterodont$: An adult human has different types of teeth,namely incisors $(I)$,canines $(C)$,premolars $(PM)$,and molars $(M)$,which serve different functions.
13
BiologyMediumMCQNEET · 2018
Which of the following events does not occur in the rough endoplasmic reticulum $(RER)$?
A
Phospholipid synthesis
B
Protein folding
C
Cleavage of signal peptide
D
Protein glycosylation

Solution

(A) The rough endoplasmic reticulum $(RER)$ is primarily involved in the synthesis,folding,and modification of proteins destined for secretion or for use in membranes.
$1$. Protein folding occurs in the lumen of the $RER$ with the help of chaperone proteins.
$2$. Cleavage of the signal peptide occurs as the nascent polypeptide enters the $RER$ lumen.
$3$. Protein glycosylation (specifically $N$-linked glycosylation) begins in the $RER$.
$4$. Phospholipid synthesis primarily occurs in the smooth endoplasmic reticulum $(SER)$,not the $RER$. Therefore,phospholipid synthesis is the event that does not occur in the $RER$.
14
BiologyEasyMCQNEET · 2018
Many ribosomes may associate with a single $mRNA$ to form multiple copies of a polypeptide simultaneously. Such strings of ribosomes are termed as
A
Nucleosome
B
Polysome
C
Plastidome
D
Polyhedral bodies

Solution

(B) In protein synthesis,a single $mRNA$ molecule can be translated by multiple ribosomes simultaneously.
This structure,where several ribosomes are attached to a single $mRNA$ strand,is known as a $Polysome$ or $Polyribosome$.
This mechanism allows the cell to produce multiple copies of the same polypeptide chain efficiently from a single $mRNA$ template.
15
BiologyMediumMCQNEET · 2018
Ciliates differ from all other protozoans in
A
Using flagella for locomotion
B
Having two types of nuclei
C
Using pseudopodia for capturing prey
D
Having a contractile vacuole for removing excess water

Solution

(B) Ciliates,such as $Paramecium$,are unique among protozoans because they possess two types of nuclei: a large macronucleus and a small micronucleus.
The macronucleus controls vegetative functions,while the micronucleus is involved in reproduction and genetic exchange.
Other protozoans like amoeboids,flagellates,and sporozoans do not exhibit this specific nuclear dimorphism.
16
BiologyMediumMCQNEET · 2018
Identify the vertebrate group of animals characterized by crop and gizzard in its digestive system.
A
Osteichthyes
B
Amphibia
C
Aves
D
Reptilia

Solution

(C) The digestive tract of birds $(Aves)$ has additional chambers,the crop and the gizzard.
$1$. The crop is a specialized pouch used for the storage of food.
$2$. The gizzard is a thick-walled,muscular organ used for grinding food,which compensates for the lack of teeth in birds.
Therefore,the correct group is $Aves$.
17
BiologyMediumMCQNEET · 2018
Which one of these animals is not a homeotherm?
A
Psittacula
B
Macropus
C
Camelus
D
Chelone

Solution

(D) Homeotherms (or endotherms) are animals that can maintain a constant body temperature regardless of the environmental temperature. Birds $(Aves)$ and mammals $(Mammalia)$ are homeotherms.
$Psittacula$ (Parrot) is a bird.
$Macropus$ (Kangaroo) is a mammal.
$Camelus$ (Camel) is a mammal.
$Chelone$ (Green sea turtle) belongs to the class $Reptilia$. Reptiles are poikilotherms (ectotherms),meaning they cannot maintain a constant body temperature and their body temperature fluctuates with the environment.
Therefore,$Chelone$ is not a homeotherm.
18
BiologyMediumMCQNEET · 2018
Which of the following features is used to identify a male cockroach from a female cockroach?
A
Presence of anal cerci
B
Presence of a boat-shaped sternum on the $9th$ abdominal segment
C
Forewings with darker tegmina
D
Presence of caudal styles

Solution

(D) In male cockroaches,the $9th$ abdominal segment bears a pair of short,thread-like anal styles (caudal styles).
These structures are absent in female cockroaches.
Anal cerci are present in both male and female cockroaches.
The $7th$ sternum is boat-shaped in females,not males.
Therefore,the presence of caudal styles is the diagnostic feature used to distinguish a male cockroach from a female.
19
BiologyMediumMCQNEET · 2018
Which of the following animals does $not$ undergo metamorphosis?
A
Starfish
B
Earthworm
C
Moth
D
Tunicate

Solution

(B) Metamorphosis is a biological process by which an animal physically develops after birth or hatching,involving a conspicuous and relatively abrupt change in the animal's body structure through cell growth and differentiation.
$A$. Starfish undergo indirect development involving a larval stage (e.g.,bipinnaria larva),which is a form of metamorphosis.
$B$. Earthworms exhibit direct development. They hatch from cocoons as miniature versions of the adult,meaning they do not undergo a larval stage or metamorphosis.
$C$. Moths undergo complete metamorphosis,which includes four stages: egg,larva (caterpillar),pupa,and adult.
$D$. Tunicates (Urochordates) undergo retrogressive metamorphosis,where the free-swimming larva possesses a notochord,which is lost in the sessile adult form.
Therefore,the correct answer is $B$.
20
BiologyMediumMCQNEET · 2018
Which of the following organisms are known as chief producers in the oceans?
A
Euglenoids
B
Dinoflagellates
C
Diatoms
D
Cyanobacteria

Solution

(C) Diatoms are microscopic,photosynthetic organisms belonging to the kingdom $Protista$ (class $Bacillariophyceae$).
They are found in both fresh water and marine environments.
In the oceans,they are the primary source of food for many aquatic organisms and are responsible for a significant portion of global photosynthesis.
Due to their massive abundance and photosynthetic activity,they are famously known as the 'chief producers' in the oceans.
21
BiologyMediumMCQNEET · 2018
Which of the following options correctly represents the lung conditions in asthma and emphysema,respectively?
A
Inflammation of bronchioles; Decreased respiratory surface
B
Decreased respiratory surface; Inflammation of bronchioles
C
Increased respiratory surface; Inflammation of bronchioles
D
Increased number of bronchioles; Increased respiratory surface

Solution

(A) Asthma is a respiratory disorder characterized by difficulty in breathing due to inflammation of the bronchi and bronchioles.
Emphysema is a chronic disorder in which alveolar walls are damaged due to which respiratory surface is decreased.
Thus,asthma involves inflammation of bronchioles,and emphysema involves a decreased respiratory surface.
22
BiologyMediumMCQNEET · 2018
Match the items given in Column-$I$ with those in Column-$II$ and select the correct option given below:
Column-$I$Column-$II$
$(a)$ Tricuspid valve$(i)$ Between left atrium and left ventricle
$(b)$ Bicuspid valve$(ii)$ Between right ventricle and pulmonary artery
$(c)$ Semilunar valve$(iii)$ Between right atrium and right ventricle
A
$a-ii, b-i, c-iii$
B
$a-iii, b-i, c-ii$
C
$a-i, b-ii, c-iii$
D
$a-i, b-iii, c-ii$

Solution

(B) The correct matches are as follows:
$1$. $(a)$ Tricuspid valve: This valve is located between the right atrium and the right ventricle, preventing the backflow of blood into the atrium during ventricular systole.
$2$. $(b)$ Bicuspid valve (Mitral valve): This valve is located between the left atrium and the left ventricle.
$3$. $(c)$ Semilunar valve: These valves are located at the openings of the right ventricle into the pulmonary artery and the left ventricle into the aorta, preventing backflow into the ventricles.
Therefore, the correct matching is: $(a-iii, b-i, c-ii)$.
23
BiologyMediumMCQNEET · 2018
Match the items given in Column $I$ with those in Column $II$ and select the correct option given below:
Column $I$ Column $II$
$(a)$ Tidal volume $(i)$ $2500-3000\,mL$
$(b)$ Inspiratory Reserve volume $(ii)$ $1100-1200\,mL$
$(c)$ Expiratory Reserve volume $(iii)$ $500-550\,mL$
$(d)$ Residual volume $(iv)$ $1000-1100\,mL$
A
$a-iv, b-iii, c-ii, d-i$
B
$a-iii, b-i, c-iv, d-ii$
C
$a-i, b-iv, c-ii, d-iii$
D
$a-iii, b-ii, c-i, d-iv$

Solution

(B) The correct matching is based on standard respiratory volumes:
$(a)$ Tidal volume $(TV)$: The volume of air inspired or expired during a normal respiration is approximately $500\,mL$ $(iii)$.
$(b)$ Inspiratory Reserve volume $(IRV)$: Additional volume of air, a person can inspire by a forcible inspiration, is $2500-3000\,mL$ $(i)$.
$(c)$ Expiratory Reserve volume $(ERV)$: Additional volume of air, a person can expire by a forcible expiration, is $1000-1100\,mL$ $(iv)$.
$(d)$ Residual volume $(RV)$: Volume of air remaining in the lungs even after a forcible expiration, is $1100-1200\,mL$ $(ii)$.
Thus, the correct sequence is $a-iii, b-i, c-iv, d-ii$.
24
BiologyMediumMCQNEET · 2018
Match the items given in Column $I$ with those in Column $II$ and select the correct option given below:
Column $I$Column $II$
$(a)$ Glycosuria$(i)$ Accumulation of uric acid in joints
$(b)$ Gout$(ii)$ Mass of crystallised salts within the kidney
$(c)$ Renal calculi$(iii)$ Inflammation in glomeruli
$(d)$ Glomerular nephritis$(iv)$ Presence of glucose in urine
A
$a-iv, b-i, c-ii, d-iii$
B
$a-iii, b-ii, c-iv, d-i$
C
$a-ii, b-iii, c-i, d-iv$
D
$a-i, b-ii, c-iii, d-iv$

Solution

$(A)$ Glycosuria is the presence of glucose in the urine, which is a common symptom of diabetes mellitus. Thus, $a-iv$.
$(b)$ Gout is caused by the accumulation of uric acid crystals in the joints, leading to inflammation and pain. Thus, $b-i$.
$(c)$ Renal calculi are stones or masses of crystallised salts (like oxalates) formed within the kidney. Thus, $c-ii$.
$(d)$ Glomerular nephritis is the inflammation of the glomeruli of the kidney. Thus, $d-iii$.
Therefore, the correct matching is $a-iv, b-i, c-ii, d-iii$.
25
BiologyMediumMCQNEET · 2018
Match the items given in Column $I$ with those in Column $II$ and select the correct option given below:
Column $I$ (Function) Column $II$ (Part of Excretory System)
$(a)$ Ultrafiltration $(i)$ Henle's loop
$(b)$ Concentration of urine $(ii)$ Ureter
$(c)$ Transport of urine $(iii)$ Urinary bladder
$(d)$ Storage of urine $(iv)$ Malpighian corpuscle
$(v)$ Proximal convoluted tubule
A
$a-v, b-iv, c-i, d-iii$
B
$a-iv, b-v, c-ii, d-iii$
C
$a-v, b-iv, c-i, d-ii$
D
$a-iv, b-i, c-ii, d-iii$

Solution

(D) The correct matching is as follows:
$(a)$ Ultrafiltration occurs in the Malpighian corpuscle (glomerulus + Bowman's capsule),which is $(iv)$.
$(b)$ Concentration of urine is primarily performed by the Henle's loop through the counter-current mechanism,which is $(i)$.
$(c)$ Transport of urine from the kidneys to the urinary bladder is carried out by the ureter,which is $(ii)$.
$(d)$ Storage of urine occurs in the urinary bladder,which is $(iii)$.
Therefore,the correct sequence is $a-iv, b-i, c-ii, d-iii$.
26
BiologyMediumMCQNEET · 2018
Secondary xylem and phloem in dicot stem are produced by
A
Axillary meristems
B
Apical meristems
C
Phellogen
D
Vascular cambium

Solution

(D) In dicot stems,secondary growth occurs due to the activity of the vascular cambium.
During secondary growth,the cells of the vascular cambium divide periclinally to produce secondary xylem towards the inner side and secondary phloem towards the outer side.
$A$ - Axillary meristems are responsible for the formation of branches or flowers.
$B$ - Apical meristems are responsible for primary growth (increase in length).
$C$ - Phellogen (cork cambium) is responsible for the formation of periderm (cork and secondary cortex).
$D$ - Vascular cambium is the correct answer as it is responsible for secondary vascular tissues.
27
BiologyEasyMCQNEET · 2018
Pneumatophores occur in
A
Submerged hydrophytes
B
Halophytes
C
Carnivorous plants
D
Free-floating hydrophytes

Solution

(B) Pneumatophores are specialized root structures found in plants that grow in saline,swampy,or waterlogged areas,such as mangroves.
These roots grow vertically upward (negatively geotropic) out of the soil or water to facilitate gaseous exchange,as the soil in these environments is often oxygen-deficient.
Plants that grow in such saline,marshy areas are known as halophytes (e.g.,$Rhizophora$ and $Avicennia$).
Therefore,pneumatophores are characteristic of halophytes.
28
BiologyMediumMCQNEET · 2018
Plants having little or no secondary growth are
A
Cycads
B
Grasses
C
Conifers
D
Deciduous angiosperms

Solution

(B) Secondary growth is the increase in thickness or girth of the plant body and is caused by the activity of lateral meristems (vascular cambium and cork cambium).
Monocots,such as grasses,typically lack secondary growth because they do not possess a functional vascular cambium.
In contrast,gymnosperms (like Cycads and Conifers) and dicotyledonous angiosperms (like deciduous trees) exhibit significant secondary growth to support their perennial habit.
Therefore,grasses are the plants among the options that exhibit little or no secondary growth.
29
BiologyEasyMCQNEET · 2018
Casparian strips occur in
A
Pericycle
B
Epidermis
C
Cortex
D
Endodermis

Solution

(D) Casparian strips are water-impermeable deposits of suberin found in the radial and tangential walls of the endodermal cells of roots.
These strips play a crucial role in regulating the flow of water and solutes into the vascular cylinder by forcing water to move through the symplastic pathway rather than the apoplastic pathway.
Therefore,the correct location for Casparian strips is the endodermis.
30
BiologyMediumMCQNEET · 2018
Sweet potato is a modified
A
Rhizome
B
Adventitious root
C
Tap root
D
Stem

Solution

(B) Sweet potato $(Ipomoea \text{ } batatas)$ is a modified adventitious root.
These roots become swollen and fleshy to store food, primarily in the form of starch.
Unlike tap roots, which develop from the radicle, adventitious roots arise from parts of the plant other than the radicle, such as the stem or leaves.
Other examples of modified adventitious roots include $Cassava$ and $Dahlia$.
31
BiologyMediumMCQNEET · 2018
Which of the following statements is $correct$?
A
Stems are usually unbranched in both $Cycas$ and $Cedrus$.
B
$Selaginella$ is heterosporous, while $Salvinia$ is homosporous.
C
Horsetails are gymnosperms.
D
Ovules are not enclosed by ovary wall in gymnosperms.

Solution

(D) $1$. $Cycas$ has an unbranched stem, but $Cedrus$ has a branched stem. Thus, option $A$ is incorrect.
$2$. Both $Selaginella$ and $Salvinia$ are heterosporous. Thus, option $B$ is incorrect.
$3$. Horsetails (Equisetum) are pteridophytes, not gymnosperms. Thus, option $C$ is incorrect.
$4$. Gymnosperms are plants in which the ovules are not enclosed by any ovary wall and remain exposed, both before and after fertilization. Thus, option $D$ is correct.
32
BiologyEasyMCQNEET · 2018
Winged pollen grains are present in
A
$Pinus$
B
Mustard
C
Mango
D
$Cycas$

Solution

(A) Winged pollen grains are a characteristic feature of $Pinus$ (a gymnosperm).
These wings are formed by the expansion of the exine (outer layer of the pollen wall) and help in the dispersal of pollen grains by wind (anemophily).
$Cycas$,Mustard,and Mango do not possess winged pollen grains.
33
BiologyMediumMCQNEET · 2018
After karyogamy followed by meiosis,spores are produced exogenously in
A
Saccharomyces
B
Neurospora
C
Alternaria
D
Agaricus

Solution

(D) In $Agaricus$ (a member of Basidiomycetes),the sexual spores are called basidiospores.
These spores are produced exogenously on club-shaped structures called basidia.
Following karyogamy and meiosis within the basidium,the resulting nuclei migrate into outgrowths called sterigmata to form basidiospores externally.
In contrast,$Saccharomyces$ and $Neurospora$ are Ascomycetes,where spores (ascospores) are produced endogenously within an ascus.
$Alternaria$ belongs to Deuteromycetes and does not produce sexual spores.
34
BiologyMediumMCQNEET · 2018
Which one is $wrongly$ matched?
A
Uniflagellate gametes - $Polysiphonia$
B
Unicellular organism - $Chlorella$
C
Gemma cups - $Marchantia$
D
Biflagellate zoospores - Brown algae

Solution

(A) The correct answer is $A$.
$Polysiphonia$ is a red alga (Rhodophyceae).
Red algae are characterized by the complete absence of flagellated stages in their life cycle; they produce non-motile gametes.
Therefore,the statement 'Uniflagellate gametes - $Polysiphonia$' is incorrect.
$Chlorella$ is a well-known unicellular green alga.
$Marchantia$ is a liverwort that reproduces asexually via gemmae produced in gemma cups.
Brown algae (Phaeophyceae) typically produce biflagellate zoospores that are pear-shaped and have two laterally attached unequal flagella.
35
BiologyMediumMCQNEET · 2018
Match the items given in Column $I$ with those in Column $II$ and select the correct option given below:
Column $I$Column $II$
$(a)$ Herbarium$(i)$ It is a place having a collection of preserved plants and animals.
$(b)$ Key$(ii)$ $A$ list that enumerates methodically all the species found in an area with brief description aiding identification.
$(c)$ Museum$(iii)$ Is a place where dried and pressed plant specimens mounted on sheets are kept.
$(d)$ Catalogue$(iv)$ $A$ booklet containing a list of characters and their alternates which are helpful in identification of various taxa.
A
$a-iii, b-iv, c-i, d-ii$
B
$a-i, b-iv, c-iii, d-ii$
C
$a-ii, b-iv, c-iii, d-i$
D
$a-iii, b-ii, c-i, d-iv$

Solution

$(A)$ The correct matches are as follows:
$(a)$ Herbarium $(iii)$: It is a storehouse of collected plant specimens that are dried, pressed, and preserved on sheets.
$(b)$ Key $(iv)$: It is a taxonomical aid used for identification of plants and animals based on the similarities and dissimilarities. It contains a list of characters and their alternates called couplets.
$(c)$ Museum $(i)$: These are generally set up in educational institutes such as schools and colleges. Museums have collections of preserved plant and animal specimens for study and reference.
$(d)$ Catalogue $(ii)$: It is a list that enumerates methodically all the species found in an area with brief descriptions aiding identification.
Therefore, the correct sequence is $a-iii, b-iv, c-i, d-ii$.
36
BiologyEasyMCQNEET · 2018
In which of the following forms is iron absorbed by plants?
A
Both ferric and ferrous
B
Free element
C
Ferric
D
Ferrous

Solution

(C) Plants absorb iron primarily in the form of ferric ions $(Fe^{3+})$.
Although iron can exist in both ferrous $(Fe^{2+})$ and ferric $(Fe^{3+})$ states in the soil,the uptake mechanism in most plants is specifically adapted to absorb the ferric form.
37
BiologyEasyMCQNEET · 2018
Which of the following elements is responsible for maintaining turgor in cells?
A
Calcium
B
Magnesium
C
Potassium
D
Sodium

Solution

(C) $Potassium$ $(K^+)$ is the most abundant cation in the cell and plays a crucial role in maintaining the turgor pressure of cells.
It regulates the opening and closing of stomata by changing the osmotic potential of guard cells.
It is also involved in protein synthesis, activation of enzymes, and maintenance of the anion-cation balance in cells.
38
BiologyDifficultMCQNEET · 2018
What is the role of $NAD^+$ in cellular respiration?
A
It is the final electron acceptor for anaerobic respiration.
B
It functions as an enzyme.
C
It is a nucleotide source for $ATP$ synthesis.
D
It functions as an electron carrier.

Solution

(D) $NAD^+$ (Nicotinamide Adenine Dinucleotide) acts as a coenzyme in cellular respiration.
Its primary role is to accept high-energy electrons and hydrogen ions during metabolic pathways such as glycolysis,the link reaction,and the Krebs cycle.
By accepting these electrons,it gets reduced to $NADH$.
This $NADH$ then transports these electrons to the electron transport system $(ETS)$ located in the inner mitochondrial membrane,where they are used to generate $ATP$.
Therefore,$NAD^+$ functions as an electron carrier.
39
BiologyMediumMCQNEET · 2018
Oxygen is $not$ produced during photosynthesis by
A
$Green\,sulphur\,bacteria$
B
$Nostoc$
C
$Cycas$
D
$Chara$

Solution

(A) Photosynthesis is classified into two types: oxygenic and anoxygenic.
Oxygenic photosynthesis occurs in organisms that use $H_2O$ as an electron donor, releasing $O_2$ as a byproduct. This is characteristic of cyanobacteria (e.g., $Nostoc$), algae (e.g., $Chara$), and higher plants (e.g., $Cycas$).
Anoxygenic photosynthesis occurs in organisms that use other compounds like $H_2S$ as an electron donor instead of $H_2O$. Consequently, they do not produce $O_2$. $Green\,sulphur\,bacteria$ are examples of organisms that perform anoxygenic photosynthesis.
Therefore, the correct answer is $Green\,sulphur\,bacteria$.
40
BiologyMediumMCQNEET · 2018
The Golgi complex participates in
A
Activation of amino acid
B
Fatty acid breakdown
C
Respiration in bacteria
D
Formation of secretory vesicles

Solution

(D) The Golgi complex (or Golgi apparatus) is a membrane-bound organelle found in eukaryotic cells.
Its primary functions include the modification,sorting,and packaging of proteins and lipids synthesized in the endoplasmic reticulum.
These processed molecules are packaged into secretory vesicles,which then transport them to their final destinations,such as the plasma membrane,lysosomes,or the extracellular space.
Therefore,the formation of secretory vesicles is a key function of the Golgi complex.
41
BiologyMediumMCQNEET · 2018
Stomatal movement is not affected by
A
$CO_2$ concentration
B
$O_2$ concentration
C
Temperature
D
Light

Solution

(B) Stomatal movement is primarily regulated by environmental factors such as light,temperature,and the concentration of $CO_2$ inside the leaf.
Light triggers the opening of stomata by promoting the accumulation of potassium ions $(K^+)$ in guard cells,which lowers the water potential and causes water to enter the cells via osmosis.
$CO_2$ concentration acts as a feedback mechanism; high internal $CO_2$ levels typically induce stomatal closure to prevent excessive water loss while maintaining gas exchange efficiency.
Temperature influences the rate of transpiration and the metabolic activity of guard cells.
However,the concentration of $O_2$ does not have a direct regulatory effect on the opening or closing of stomata.
42
BiologyMediumMCQNEET · 2018
Stomata in grass leaf are
A
Barrel shaped
B
Dumb-bell shaped
C
Rectangular
D
Kidney shaped

Solution

(B) In most dicotyledonous plants,the guard cells of the stomata are kidney-shaped or bean-shaped.
However,in monocotyledonous plants like grasses,the guard cells are dumb-bell shaped.
The outer walls of these guard cells are thin,while the inner walls are highly thickened,which helps in the opening and closing of the stomata.
43
BiologyEasyMCQNEET · 2018
Which of the following is true for the nucleolus?
A
It is a site for active ribosomal $RNA$ synthesis.
B
Larger nucleoli are present in dividing cells.
C
It takes part in spindle formation.
D
It is a membrane-bound structure.

Solution

(A) The nucleolus is a spherical structure present in the nucleoplasm of the nucleus.
It is not a membrane-bound structure,meaning it lacks a limiting membrane.
Its primary function is the active synthesis of ribosomal $RNA$ $(rRNA)$.
Cells that are actively involved in protein synthesis contain larger and more numerous nucleoli.
Spindle formation is a function of the centrosome/microtubules,not the nucleolus.
Therefore,the statement that it is a site for active ribosomal $RNA$ synthesis is correct.
44
BiologyMediumMCQNEET · 2018
Which of the following is not a product of the light reaction of photosynthesis?
A
$NADH$
B
$ATP$
C
$NADPH$
D
$Oxygen$

Solution

(A) The light reaction of photosynthesis produces $ATP$,$NADPH$,and $Oxygen$ as end products.
$NADH$ is primarily produced during cellular respiration (e.g.,glycolysis and the Krebs cycle),not during the light-dependent reactions of photosynthesis.
45
BiologyEasyMCQNEET · 2018
The stage during which separation of the paired homologous chromosomes begins is
A
Zygotene
B
Diplotene
C
Pachytene
D
Diakinesis

Solution

(B) During the $Meiosis-I$ process,specifically in the $Prophase-I$ stage,homologous chromosomes undergo pairing (synapsis) during the $Zygotene$ phase.
In the subsequent phase,$Pachytene$,crossing over occurs.
In the $Diplotene$ phase,the synaptonemal complex dissolves,and the paired homologous chromosomes begin to separate from each other,except at the sites of crossovers,which are known as $Chiasmata$.
Therefore,the separation of paired homologous chromosomes begins in the $Diplotene$ stage.
46
BiologyEasyMCQNEET · 2018
The two functional groups characteristic of sugars are
A
carbonyl and hydroxyl
B
hydroxyl and methyl
C
carbonyl and phosphate
D
carbonyl and methyl

Solution

(A) Sugars (carbohydrates) are polyhydroxy aldehydes or polyhydroxy ketones.
This means they contain multiple hydroxyl $(-OH)$ groups and a single carbonyl $(C=O)$ group (either an aldehyde or a ketone group).
Therefore,the two functional groups characteristic of sugars are carbonyl and hydroxyl.
47
BiologyMediumMCQNEET · 2018
Which among the following is $not$ a prokaryote?
A
Oscillatoria
B
Saccharomyces
C
Nostoc
D
Mycobacterium

Solution

(B) An organism that does not possess a true nucleus (nucleus with nuclear membrane) and double membrane-bounded organelles is called a prokaryote.
Kingdom Monera consists of prokaryotes,such as bacteria (e.g.,$Mycobacterium$) and cyanobacteria (e.g.,$Nostoc$ and $Oscillatoria$).
In contrast,$Saccharomyces$ (yeast) belongs to the Kingdom Fungi. It possesses a true nucleus and membrane-bound organelles,making it a eukaryote.
48
BiologyMediumMCQNEET · 2018
The amnion of the mammalian embryo is derived from:
A
Ectoderm and endoderm
B
Ectoderm and mesoderm
C
Mesoderm and trophoblast
D
Endoderm and mesoderm

Solution

(B) The amnion is one of the four extra-embryonic membranes found in amniotes,including mammals.
It is formed by the folding of the somatopleure,which consists of the somatic layer of the extra-embryonic mesoderm and the overlying ectoderm.
Therefore,the amnion is derived from the ectoderm and the mesoderm.
49
BiologyMediumMCQNEET · 2018
Hormones secreted by the placenta to maintain pregnancy are
A
$hCG$,progestogens,estrogens,glucocorticoids
B
$hCG$,$hPL$,progestogens,Prolactin
C
$hCG$,$hPL$,progestogens,estrogens
D
$hCG$,$hPL$,estrogens,relaxin,oxytocin

Solution

(C) The placenta acts as an endocrine tissue and produces several hormones essential for maintaining pregnancy.
These hormones include Human Chorionic Gonadotropin $(hCG)$,Human Placental Lactogen $(hPL)$,progestogens (progesterone),and estrogens.
$hCG$ stimulates the corpus luteum to secrete progesterone until the placenta takes over this function.
$hPL$ is involved in growth of the fetus and metabolic changes in the mother.
Progesterone is essential for maintaining the endometrium,and estrogens are necessary for the development of the fetus and maternal tissues.
50
BiologyEasyMCQNEET · 2018
The contraceptive $SAHELI$:
A
is a post-coital contraceptive.
B
increases the concentration of estrogen and prevents ovulation in females.
C
is an $IUD$.
D
blocks estrogen receptors in the uterus,preventing eggs from getting implanted.

Solution

(D) $SAHELI$ is a non-steroidal oral contraceptive pill developed by the $CDRI$ (Central Drug Research Institute) in Lucknow,India.
It contains a compound called $Centchroman$.
Unlike hormonal pills that prevent ovulation,$SAHELI$ works by blocking estrogen receptors in the uterus.
By blocking these receptors,it prevents the implantation of the fertilized egg (blastocyst) in the uterine wall,thereby acting as an effective contraceptive.
It is taken once a week,making it a popular choice for birth control.
51
BiologyEasyMCQNEET · 2018
The difference between $Spermiogenesis$ and $Spermiation$ is:
A
In $Spermiogenesis$,spermatozoa from $Sertoli$ cells are released into the cavity of seminiferous tubules,while in $Spermiation$,spermatozoa are formed.
B
In $Spermiogenesis$,spermatids are formed,while in $Spermiation$,spermatozoa are formed.
C
In $Spermiogenesis$,spermatozoa are formed,while in $Spermiation$,spermatozoa are released from $Sertoli$ cells into the cavity of seminiferous tubules.
D
In $Spermiogenesis$,spermatozoa are formed,while in $Spermiation$,spermatids are formed.

Solution

(C) $Spermiogenesis$ is the process of transformation of non-motile spermatids into mature,motile spermatozoa.
$Spermiation$ is the process by which mature spermatozoa are released from the $Sertoli$ cells into the lumen (cavity) of the seminiferous tubules.
Therefore,$Spermiogenesis$ involves the formation of spermatozoa,and $Spermiation$ involves the release of these spermatozoa.
52
BiologyMediumMCQNEET · 2018
$A$ woman has an $X$-linked condition on one of her $X$ chromosomes. This chromosome can be inherited by
A
Both sons and daughters
B
Only daughters
C
Only grandchildren
D
Only sons

Solution

(A) woman has two $X$ chromosomes $(XX)$. If one of her $X$ chromosomes carries an $X$-linked condition,she can pass this specific chromosome to any of her offspring.
During meiosis,the woman produces eggs,each containing one $X$ chromosome. Half of her eggs will carry the $X$ chromosome with the condition,and the other half will carry the normal $X$ chromosome.
When these eggs are fertilized by sperm from a male $(XY)$:
$1$. If an egg with the affected $X$ chromosome is fertilized by a $Y$-bearing sperm,the resulting offspring will be a son $(XY)$ who inherits the condition.
$2$. If an egg with the affected $X$ chromosome is fertilized by an $X$-bearing sperm,the resulting offspring will be a daughter $(XX)$ who inherits the condition.
Therefore,the $X$-linked condition can be inherited by both sons and daughters.
53
BiologyMediumMCQNEET · 2018
According to Hugo de Vries,the mechanism of evolution is
A
Minor mutations
B
Saltation
C
Phenotypic variations
D
Multiple step mutations

Solution

(B) Hugo de Vries proposed the Mutation Theory of evolution.
He believed that evolution is a discontinuous process caused by large,sudden,and heritable changes in the genetic material,which he termed as mutations.
He specifically used the term $Saltation$ to describe these single-step large mutations that lead to speciation.
Therefore,according to Hugo de Vries,the mechanism of evolution is $Saltation$.
54
BiologyMediumMCQNEET · 2018
All of the following are part of an operon except:
A
a promoter
B
an operator
C
an enhancer
D
structural genes

Solution

(C) An operon is a functional unit of $DNA$ in bacteria and phages,consisting of a cluster of genes under the control of a single promoter.
An operon typically includes:
$1$. Structural genes: These code for the proteins or enzymes required for a metabolic pathway.
$2$. $A$ promoter: The site where $RNA$ polymerase binds to initiate transcription.
$3$. An operator: $A$ segment of $DNA$ that acts as a switch,where a repressor protein binds to prevent transcription.
Enhancers are regulatory $DNA$ sequences that increase the rate of transcription,but they are primarily associated with eukaryotic gene regulation,not prokaryotic operons.
55
BiologyDifficultMCQNEET · 2018
$AGGTATCGCAT$ is a sequence from the coding strand of a gene. What will be the corresponding sequence of the transcribed $mRNA$?
A
$AGGUAUCGCAU$
B
$UCCAUAGCGUA$
C
$ACCUAUGCGAU$
D
$UGGTUTCGCAT$

Solution

(A) The coding strand of a gene has the same sequence as the $mRNA$ except that $Thymine$ $(T)$ in $DNA$ is replaced by $Uracil$ $(U)$ in $RNA$.
Given coding strand sequence: $AGGTATCGCAT$.
Replacing $T$ with $U$ gives the $mRNA$ sequence: $AGGUAUCGCAU$.
Therefore,the correct option is $A$.
56
BiologyMediumMCQNEET · 2018
Match the items given in Column $I$ with those in Column $II$ and select the correct option given below:
Column $I$ Column $II$
$(a)$ Proliferative Phase $(i)$ Breakdown of endometrial lining
$(b)$ Secretory Phase $(ii)$ Follicular phase
$(c)$ Menstruation $(iii)$ Luteal Phase
A
$a-ii, b-iii, c-i$
B
$a-iii, b-ii, c-i$
C
$a-iii, b-i, c-ii$
D
$a-i, b-iii, c-ii$

Solution

(A) The menstrual cycle consists of different phases:
$1$. The Proliferative Phase is also known as the Follicular phase,where the endometrium regenerates under the influence of estrogen. Thus,$(a)$ matches with $(ii)$.
$2$. The Secretory Phase is also known as the Luteal phase,where the corpus luteum secretes progesterone to maintain the endometrium. Thus,$(b)$ matches with $(iii)$.
$3$. Menstruation is the phase characterized by the breakdown of the endometrial lining due to the decline in progesterone levels. Thus,$(c)$ matches with $(i)$.
Therefore,the correct matching is $a-ii, b-iii, c-i$.
57
BiologyMediumMCQNEET · 2018
In which disease does a mosquito-transmitted pathogen cause chronic inflammation of the lymphatic vessels?
A
Amoebiasis
B
Elephantiasis
C
Ringworm disease
D
Ascariasis

Solution

(B) Elephantiasis, also known as $Filariasis$, is caused by the filarial worms $Wuchereria$ $bancrofti$ and $Wuchereria$ $malayi$.
These pathogens are transmitted to healthy individuals through the bite of female $Culex$ mosquitoes.
The parasites primarily reside in the lymphatic vessels, where they cause chronic inflammation and obstruction, leading to the characteristic swelling of the lower limbs and other body parts.
58
BiologyEasyMCQNEET · 2018
Among the following sets of examples for divergent evolution,select the incorrect option:
A
Eye of octopus,bat and man
B
Forelimbs of man,bat and cheetah
C
Brain of bat,man and cheetah
D
Heart of bat,man and cheetah

Solution

(A) Divergent evolution occurs when species with a common ancestor evolve different traits to adapt to different environments,resulting in homologous organs.
Homologous organs are those that have the same structural origin and developmental pattern but may perform different functions.
$A$. The eye of an octopus (a mollusc) and the eye of a mammal (bat or man) are examples of convergent evolution,not divergent evolution. They perform similar functions but have different evolutionary origins.
$B$. The forelimbs of man,bat,and cheetah are classic examples of homologous organs,showing divergent evolution.
$C$. The brains of vertebrates like bats,humans,and cheetahs share a common structural plan,indicating divergent evolution.
$D$. The hearts of vertebrates like bats,humans,and cheetahs share a common structural plan,indicating divergent evolution.
Therefore,the incorrect option regarding divergent evolution is the eye of an octopus,bat,and man.
59
BiologyEasyMCQNEET · 2018
The similarity of bone structure in the forelimbs of many vertebrates is an example of
A
Adaptive radiation
B
Homology
C
Convergent evolution
D
Analogy

Solution

(B) The similarity in the bone structure of the forelimbs of many vertebrates (such as whales,bats,cheetahs,and humans) indicates that they share a common ancestry.
These structures perform different functions in different animals (e.g.,swimming,flying,running,grasping) but share the same anatomical origin and basic structural plan.
Such structures are called homologous organs,and the phenomenon is known as homology.
Homology is based on divergent evolution,where organisms with a common ancestor evolve different traits to adapt to different environments.
60
BiologyMediumMCQNEET · 2018
Which of the following is not an autoimmune disease?
A
Vitiligo
B
Psoriasis
C
Alzheimer's disease
D
Rheumatoid arthritis

Solution

(C) An autoimmune disease occurs when the immune system mistakenly attacks healthy cells in the body.
$A$. Vitiligo is an autoimmune condition where the immune system destroys melanocytes.
$B$. Psoriasis is an autoimmune disease that causes skin cells to multiply up to $10$ times faster than normal.
$C$. Alzheimer's disease is a progressive neurodegenerative disorder characterized by the accumulation of amyloid plaques and tau tangles in the brain; it is not classified as an autoimmune disease.
$D$. Rheumatoid arthritis is an autoimmune disorder in which the immune system attacks the joints,causing inflammation.
Therefore,the correct answer is $C$.
61
BiologyMediumMCQNEET · 2018
Which of the following characteristics represent 'Inheritance of blood groups' in humans?
$(a)$ Dominance
$(b)$ Co-dominance
$(c)$ Multiple allele
$(d)$ Incomplete dominance
$(e)$ Polygenic inheritance
A
$a, c$ and $e$
B
$b, c$ and $e$
C
$b, d$ and $e$
D
$a, b$ and $c$

Solution

(D) The inheritance of $ABO$ blood groups in humans is governed by the gene $I$.
$1$. Dominance: The alleles $I^A$ and $I^B$ are dominant over the allele $i$.
$2$. Co-dominance: When both $I^A$ and $I^B$ are present together,they both express themselves equally,resulting in blood group $AB$.
$3$. Multiple Allelism: The gene $I$ exists in three allelic forms $(I^A, I^B, i)$,which is a classic example of multiple alleles.
Therefore,the characteristics represented are dominance,co-dominance,and multiple alleles,which correspond to $(a), (b),$ and $(c)$.
62
BiologyEasyMCQNEET · 2018
Conversion of milk to curd improves its nutritional value by increasing the amount of
A
Vitamin $E$
B
Vitamin $D$
C
Vitamin $B_{12}$
D
Vitamin $A$

Solution

(C) The conversion of milk into curd is carried out by Lactic Acid Bacteria $(LAB)$ such as Lactobacillus.
These bacteria grow in milk and convert it into curd.
During this process,$LAB$ significantly increases the nutritional quality of curd by increasing the amount of Vitamin $B_{12}$.
Therefore,the correct option is $C$.
63
BiologyMediumMCQNEET · 2018
Match the items given in Column $I$ with those in Column $II$ and select the correct option given below:
Column $I$ Column $II$
$(a)$ Eutrophication $(i)$ $UV-B$ radiation
$(b)$ Sanitary landfill $(ii)$ Deforestation
$(c)$ Snow blindness $(iii)$ Nutrient enrichment
$(d)$ Jhum cultivation $(iv)$ Waste disposal
A
$a-iii, b-iv, c-i, d-ii$
B
$a-ii, b-i, c-iii, d-iv$
C
$a-i, b-ii, c-iv, d-iii$
D
$a-i, b-iii, c-iv, d-ii$

Solution

(A) The correct matches are as follows:
$(a)$ Eutrophication refers to the natural or artificial enrichment of water bodies with nutrients (like nitrogen and phosphorus),which leads to excessive growth of algae. Thus,$(a)-(iii)$.
$(b)$ Sanitary landfills are a method of solid waste disposal where waste is buried in a prepared area. Thus,$(b)-(iv)$.
$(c)$ Snow blindness is caused by the inflammation of the cornea due to high doses of $UV-B$ radiation,which is reflected by snow. Thus,$(c)-(i)$.
$(d)$ Jhum cultivation,also known as slash-and-burn agriculture,is a major cause of deforestation in many regions. Thus,$(d)-(ii)$.
Therefore,the correct sequence is $a-iii, b-iv, c-i, d-ii$.
64
BiologyMediumMCQNEET · 2018
Which one of the following population interactions is widely used in medical science for the production of antibiotics?
A
Parasitism
B
Commensalism
C
Amensalism
D
Mutualism

Solution

(C) Amensalism is a type of population interaction where one species is harmed while the other remains unaffected.
Antibiotics are chemical substances produced by some microorganisms (like fungi or bacteria) that inhibit or kill the growth of other microorganisms.
For example,the mold $Penicillium$ produces penicillin,which inhibits the growth of bacteria.
In this interaction,the bacteria are harmed,while the $Penicillium$ mold is not significantly affected by the presence of the bacteria,making it a classic example of amensalism.
65
BiologyEasyMCQNEET · 2018
All of the following are included in 'Ex-situ conservation' except:
A
Sacred groves
B
Wildlife safari parks
C
Botanical gardens
D
Seed banks

Solution

(A) Ex-situ conservation involves the conservation of organisms outside their natural habitats.
$1$. 'Ex-situ' methods include botanical gardens,zoological parks,wildlife safari parks,seed banks,and cryopreservation.
$2$. 'In-situ' conservation involves protecting the entire ecosystem and its biodiversity within its natural habitat.
$3$. Sacred groves are a form of 'In-situ' conservation where specific patches of forest are protected by local communities due to religious or cultural beliefs.
Therefore,sacred groves are not included in 'Ex-situ' conservation.
66
BiologyMediumMCQNEET · 2018
In a growing population of a country,
A
Pre-reproductive individuals are more than the reproductive individuals.
B
Pre-reproductive individuals are less than reproductive individuals.
C
Reproductive individuals and pre-reproductive individuals are equal in number.
D
Reproductive individuals are less than the post-reproductive individuals.

Solution

(A) population is considered to be growing (expanding) when the number of pre-reproductive individuals is significantly higher than the number of reproductive and post-reproductive individuals.
This creates an age pyramid with a broad base,indicating a high birth rate and a large number of young individuals who will enter the reproductive age in the future.
Therefore,the correct condition for a growing population is that pre-reproductive individuals are more than the reproductive individuals.
67
BiologyMediumMCQNEET · 2018
Which part of the poppy plant is used to obtain the drug "Smack"?
A
Leaves
B
Latex
C
Roots
D
Flowers

Solution

(B) The drug commonly known as "Smack" is $Heroin$, which is chemically $Diacetylmorphine$.
It is a white, odorless, bitter crystalline compound.
It is obtained by the acetylation of $Morphine$, which is extracted from the $Latex$ of the poppy plant, $Papaver \text{ } somniferum$.
68
BiologyDifficultMCQNEET · 2018
What type of ecological pyramid would be obtained with the following data?
Secondary consumer: $120\,g$
Primary consumer: $60\,g$
Primary producer: $10\,g$
A
Upright pyramid of biomass
B
Inverted pyramid of biomass
C
Upright pyramid of numbers
D
Pyramid of energy

Solution

(B) The given data represents the biomass at different trophic levels:
Primary producer: $10\,g$
Primary consumer: $60\,g$
Secondary consumer: $120\,g$
In this case,the biomass increases as we move from the producer level to the consumer levels.
An ecological pyramid where the biomass increases at higher trophic levels is known as an inverted pyramid.
Therefore,this data represents an inverted pyramid of biomass,which is commonly observed in aquatic ecosystems.
69
BiologyEasyMCQNEET · 2018
World Ozone Day is celebrated on
A
$22nd$ April
B
$5th$ June
C
$16th$ September
D
$21st$ April

Solution

(C) World Ozone Day is celebrated annually on $16th$ September.
This date was designated by the United Nations General Assembly to commemorate the signing of the Montreal Protocol on Substances that Deplete the Ozone Layer in $1987$.
The primary objective of this day is to raise awareness about the importance of the ozone layer and the need to protect it from ozone-depleting substances.
70
BiologyEasyMCQNEET · 2018
In the stratosphere,which of the following elements acts as a catalyst in the degradation of ozone and the release of molecular oxygen?
A
Oxygen
B
Carbon
C
$Fe$
D
$Cl$

Solution

(D) In the stratosphere,chlorofluorocarbons $(CFCs)$ are broken down by ultraviolet $(UV)$ radiation,which releases chlorine atoms $(Cl)$.
These chlorine atoms act as catalysts in the degradation of ozone $(O_3)$ into molecular oxygen $(O_2)$.
The reaction mechanism is as follows:
$Cl + O_3 \rightarrow ClO + O_2$
$ClO + O \rightarrow Cl + O_2$
Thus,the chlorine atom is regenerated and continues to destroy more ozone molecules.
71
BiologyMediumMCQNEET · 2018
Natality refers to.
A
Number of individuals entering a habitat
B
Death rate
C
Birth rate
D
Number of individuals leaving the habitat

Solution

(C) Natality is defined as the birth rate within a population.
It refers to the number of births per unit of time per unit of population.
In contrast,mortality refers to the death rate,immigration refers to the number of individuals entering a habitat,and emigration refers to the number of individuals leaving a habitat.
Therefore,the correct option is $C$.
72
BiologyMediumMCQNEET · 2018
$Niche$ is:
A
all the biological factors in the organism's environment
B
the functional role played by the organism where it lives
C
the range of temperature that the organism needs to live
D
the physical space where an organism lives

Solution

(B) $Niche$ refers to the specific functional role that an organism plays within its ecosystem. It encompasses how the organism interacts with both biotic and abiotic components of its environment,including its diet,reproductive habits,and how it utilizes resources. While a $Habitat$ refers to the physical place where an organism lives,a $Niche$ describes its 'profession' or functional status in the community.
73
BiologyEasyMCQNEET · 2018
Which of the following is a secondary pollutant?
A
$SO_2$
B
$CO$
C
$O_3$
D
$CO_2$

Solution

(C) Primary pollutants are emitted directly from sources,such as $SO_2$,$CO$,and $CO_2$.
Secondary pollutants are formed in the atmosphere through chemical reactions between primary pollutants and other atmospheric components.
$O_3$ (Ozone) in the troposphere is a classic example of a secondary pollutant,formed by the reaction of nitrogen oxides and volatile organic compounds in the presence of sunlight.
74
BiologyMediumMCQNEET · 2018
Which one of the following plants shows a very close relationship with a species of moth,where none of the two can complete its life cycle without the other?
A
$Yucca$
B
$Hydrilla$
C
$Banana$
D
$Viola$

Solution

(A) The plant $Yucca$ exhibits a mutualistic relationship with a specific species of moth $(Tegeticula)$.
In this relationship,the moth deposits its eggs in the locule of the ovary of the $Yucca$ flower.
In exchange,the moth pollinates the $Yucca$ flower while moving around it.
The larvae of the moth hatch from the eggs as the seeds develop.
Neither the $Yucca$ plant nor the moth can complete their life cycles without each other,making this an obligate mutualism.
75
BiologyEasyMCQNEET · 2018
Pollen grains can be stored for several years in liquid nitrogen having a temperature of (in $^oC$)
A
$-160$
B
$-120$
C
$-196$
D
$-80$

Solution

(C) Pollen grains are stored in liquid nitrogen to maintain their viability for long periods.
This process is known as cryopreservation.
The temperature of liquid nitrogen is $-196^oC$.
At this extremely low temperature,the metabolic activities of the pollen grains are suspended,allowing them to be stored for several years.
76
BiologyMediumMCQNEET · 2018
Double fertilization is
A
Fusion of one male gamete with two polar nuclei
B
Fusion of two male gametes of a pollen tube with two different eggs
C
Fusion of two male gametes with one egg
D
Syngamy and triple fusion

Solution

(D) Double fertilization is a characteristic feature of angiosperms.
It involves two distinct fusion events:
$1$. Syngamy: One male gamete fuses with the egg cell to form a diploid zygote $(2n)$.
$2$. Triple fusion: The second male gamete fuses with the two polar nuclei (or the secondary nucleus) to form a primary endosperm nucleus $(PEN)$,which is triploid $(3n)$.
Therefore,double fertilization is the combination of syngamy and triple fusion.
77
BiologyEasyMCQNEET · 2018
Offsets are produced by
A
Parthenogenesis
B
Meiotic divisions
C
Parthenocarpy
D
Mitotic divisions

Solution

(D) Offsets are a type of vegetative propagule produced by certain aquatic plants like $Eichhornia$ (water hyacinth).
Vegetative propagation is a form of asexual reproduction where new plants are formed from vegetative parts of the parent plant.
Since asexual reproduction involves the formation of clones,it occurs through $Mitotic$ $divisions$ only,without the involvement of meiosis or gamete fusion.
78
BiologyMediumMCQNEET · 2018
Select the correct statement:
A
Transduction was discovered by $S$. Altman
B
Franklin Stahl coined the term "linkage"
C
Spliceosomes take part in translation.
D
Punnett square was developed by a British scientist

Solution

(D) The correct statement is that the Punnett square was developed by a British geneticist, Reginald $C$. Punnett.
- Transduction was discovered by Joshua Lederberg and Norton Zinder in $1952$, not $S$. Altman.
- The term "linkage" was coined by Thomas Hunt Morgan, not Franklin Stahl.
- Spliceosomes are involved in $RNA$ splicing (post-transcriptional modification), not in translation.
79
BiologyEasyMCQNEET · 2018
Which of the following has proved helpful in preserving pollen as fossils?
A
Sporopollenin
B
Pollenkitt
C
Oil content
D
Cellulosic intine

Solution

(A) The exine of the pollen grain is composed of a highly resistant organic material called $Sporopollenin$.
$Sporopollenin$ is one of the most resistant organic materials known.
It can withstand high temperatures,strong acids,and alkali solutions.
No enzyme that degrades $Sporopollenin$ is known to date.
Due to this remarkable stability,pollen grains are well-preserved as fossils.
80
BiologyMediumMCQNEET · 2018
Which of the following pairs is $wrongly$ matched?
A
Starch synthesis in pea : Multiple alleles
B
$T. H. Morgan$ : Linkage
C
$XO$ type sex determination : Grasshopper
D
$ABO$ blood grouping : Co-dominance

Solution

(A) $1$. Starch synthesis in pea is controlled by a single gene with two alleles ($B$ and $b$), which exhibits pleiotropy, not multiple alleles.
$2$. $T. H. Morgan$ is known for his work on linkage in Drosophila.
$3$. $XO$ type sex determination is observed in grasshoppers.
$4$. $ABO$ blood grouping in humans is an example of multiple alleles and co-dominance (for $I^A$ and $I^B$ alleles). However, the primary genetic principle for $ABO$ blood grouping is multiple alleles, and the pairing with co-dominance is technically correct but less specific than the error in option $A$. Since starch synthesis is clearly pleiotropy, option $A$ is the $wrongly$ matched pair.
81
BiologyEasyMCQNEET · 2018
Select the $correct$ match:
A
Francois Jacob and Jacques Monod - $Lac\,operon$
B
Alec Jeffreys - $Streptococcus\,pneumoniae$
C
Matthew Meselson and $F$. Stahl - $Pisum\,sativum$
D
Alfred Hershey and Martha Chase - $TMV$

Solution

(A) $1$. Francois Jacob and Jacques Monod proposed the $Lac\,operon$ model in $1961$ to explain gene regulation in $E. coli$.
$2$. Alec Jeffreys is known for developing $DNA$ fingerprinting,not for $Streptococcus\,pneumoniae$ (which was studied by Frederick Griffith).
$3$. Matthew Meselson and $F$. Stahl provided experimental evidence for the semi-conservative replication of $DNA$ in $E. coli$,not $Pisum\,sativum$ (which was studied by Gregor Mendel).
$4$. Alfred Hershey and Martha Chase conducted experiments with bacteriophages to prove that $DNA$ is the genetic material,not $TMV$ (Tobacco Mosaic Virus).
82
BiologyEasyMCQNEET · 2018
Which of the following flowers only once in its life-time?
A
Papaya
B
Bamboo species
C
Mango
D
Jackfruit

Solution

(B) Monocarpic plants are those that flower and fruit only once in their lifetime and then die.
Bamboo species (e.g.,$Bambusa$ $tulda$) are classic examples of monocarpic plants that exhibit a unique phenomenon of flowering only once in their lifetime,usually after $50-100$ years of vegetative growth,followed by the production of a large number of seeds and subsequent death.
Papaya,Mango,and Jackfruit are polycarpic plants,meaning they flower and produce fruits repeatedly throughout their lifespan.
83
BiologyEasyMCQNEET · 2018
The experimental proof for semiconservative replication of $DNA$ was first shown in a:
A
Virus
B
Fungus
C
Plant
D
Bacterium

Solution

(D) The experimental proof for the semiconservative replication of $DNA$ was first provided by Matthew Meselson and Franklin Stahl in $1958$.
They performed their experiments on the bacterium $Escherichia coli$ $(E. coli)$.
They grew $E. coli$ in a medium containing $^{15}N$ (a heavy isotope of nitrogen) for many generations, resulting in $DNA$ containing $^{15}N$.
Then, they transferred these bacteria to a medium containing $^{14}N$ (a normal isotope of nitrogen).
After one generation, the $DNA$ extracted had a hybrid density, and after two generations, it showed both light and hybrid $DNA$, which confirmed the semiconservative mode of $DNA$ replication.
84
BiologyMediumMCQNEET · 2018
Which of the following is commonly used as a vector for introducing a $DNA$ fragment in human lymphocytes?
A
$pBR\,322$
B
$Ti\,plasmid$
C
$\lambda$ phage
D
Retrovirus

Solution

(D) Retroviruses have the natural ability to infect host cells and integrate their genetic material into the host genome.
In biotechnology,disarmed retroviruses are used as vectors to deliver desired genes into animal cells,including human lymphocytes.
$pBR\,322$ is a plasmid vector used in bacteria.
$Ti\,plasmid$ is used for gene transfer in plants.
$\lambda$ phage is a bacteriophage used as a cloning vector in bacteria.
Therefore,the correct option is $D$.
85
BiologyMediumMCQNEET · 2018
Select the $correct$ match.
A
$G. Mendel$ - Transformation
B
Ribozyme - Nucleic acid
C
$T.H. Morgan$ - Transduction
D
$F_2 \times$ Recessive parent - Dihybrid cross

Solution

(B) . $G. Mendel$ is known for the laws of inheritance,not transformation. Transformation was discovered by $F. Griffith$.
$B$. Ribozyme is an $RNA$ molecule that acts as an enzyme,which is a nucleic acid. This is the correct match.
$C$. $T.H. Morgan$ is known for linkage and recombination,not transduction. Transduction was discovered by $Zinder$ and $Lederberg$.
$D$. $F_2 \times$ Recessive parent is a test cross,not a dihybrid cross. $A$ dihybrid cross involves the study of two traits.
86
BiologyEasyMCQNEET · 2018
Use of bioresources by multinational companies and organisations without authorisation from the concerned country and its people is called
A
Bioexploitation
B
Bio-infringement
C
Biodegradation
D
Biopiracy

Solution

(D) Biopiracy is the term used to refer to the use of bioresources by multinational companies and other organizations without proper authorization from the countries and people concerned without compensatory payment.
87
BiologyMediumMCQNEET · 2018
$A$ 'new' variety of rice was patented by a foreign company, though such varieties have been present in India for a long time. This is related to
A
Basmati
B
$Co-667$
C
Lerma Rojo
D
Sbarbati Sonora

Solution

(A) In $1997$, an American company named RiceTec Inc. was granted a patent by the $US$ Patent and Trademark Office for 'Basmati' rice lines and grains. This was highly controversial because Basmati rice has been grown in India and Pakistan for centuries and is a traditional variety. This act is considered an example of biopiracy, where multinational companies exploit biological resources and traditional knowledge of developing countries without proper authorization or compensation.
88
BiologyMediumMCQNEET · 2018
In India,the organisation responsible for assessing the safety of introducing genetically modified organisms for public use is
A
Council for Scientific and Industrial Research $(CSIR)$
B
Indian Council of Medical Research $(ICMR)$
C
Research Committee on Genetic Manipulation $(RCGM)$
D
Genetic Engineering Appraisal Committee $(GEAC)$

Solution

(D) The Indian government has established the Genetic Engineering Appraisal Committee $(GEAC)$ under the Ministry of Environment,Forest and Climate Change.
This organization is responsible for making decisions regarding the validity of research involving genetically modified organisms $(GMOs)$ and the safety of introducing them for public use.
While the Research Committee on Genetic Manipulation $(RCGM)$ monitors the safety of research activities,the final approval for commercial release and public use is granted by the $GEAC$.
89
BiologyEasyMCQNEET · 2018
The correct order of steps in Polymerase Chain Reaction $(PCR)$ is
A
Denaturation,Annealing,Extension
B
Extension,Denaturation,Annealing
C
Denaturation,Extension,Annealing
D
Annealing,Extension,Denaturation

Solution

(A) The Polymerase Chain Reaction $(PCR)$ is a technique used to amplify a specific $DNA$ segment.
It consists of three main steps performed in a cyclic manner:
$1$. Denaturation: The double-stranded $DNA$ is heated to a high temperature (usually around $94-98^{\circ}C$) to separate the two strands.
$2$. Annealing: The temperature is lowered (usually $50-65^{\circ}C$) to allow the primers to bind to the complementary sequences on the single-stranded $DNA$ templates.
$3$. Extension: The temperature is adjusted (usually $72^{\circ}C$) for the $DNA$ polymerase enzyme to synthesize the new $DNA$ strand by adding nucleotides to the primers.
Therefore,the correct order is Denaturation,Annealing,and Extension.

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