NEET 2016 Biology Question Paper with Answer and Solution

201 QuestionsEnglishWith Solutions

BiologyQ51145 of 201 questions

Page 2 of 3 · English

51
BiologyMediumMCQNEET · 2016
Which of the following is not a characteristic feature during mitosis in somatic cells?
A
Chromosome movement
B
Synapsis
C
Spindle fibres
D
Disappearance of nucleolus

Solution

(B) : Synapsis is the process of pairing of homologous chromosomes. It occurs specifically during the zygotene stage of prophase $I$ of meiosis. This phenomenon is not observed during mitosis,as mitosis involves the division of somatic cells without the pairing of homologous chromosomes.
52
BiologyMediumMCQNEET · 2016
In meiosis,crossing over is initiated at:
A
zygotene
B
diplotene
C
pachytene
D
leptotene

Solution

(C) : Crossing over is a process of exchange of genetic material or chromatid segments between two homologous chromosomes. It is initiated during the pachytene stage of meiosis $I$.
53
BiologyMediumMCQNEET · 2016
$A$ few drops of sap were collected by cutting across a plant stem by a suitable method. The sap was tested chemically. Which one of the following test results indicates that it is phloem sap?
A
Acidic
B
Alkaline
C
Low refractive index
D
Absence of sugar

Solution

(B) Phloem sap is the fluid transported through the phloem tissue,which primarily consists of sucrose and other organic solutes.
Chemically,phloem sap is known to be alkaline in nature,typically having a $pH$ ranging from $7.5$ to $8.5$.
In contrast,xylem sap is generally acidic.
Therefore,an alkaline test result indicates that the collected fluid is phloem sap.
54
BiologyEasyMCQNEET · 2016
Which is essential for the growth of root tip?
A
$Zn$
B
$Fe$
C
$Ca$
D
$Mn$

Solution

(C) The correct answer is $C$.
Calcium $(Ca^{2+})$ is an essential mineral element required by plants.
It is specifically required for the formation of the middle lamella in cell walls and is crucial for the normal functioning of the root apical meristem.
It plays a vital role in cell division and cell elongation at the root tip,making it essential for root tip growth.
55
BiologyMediumMCQNEET · 2016
In which of the following,all three are macronutrients?
A
Molybdenum,magnesium,manganese
B
Nitrogen,nickel,phosphorus
C
Boron,zinc,manganese
D
None of these

Solution

(D) None of the options is correct. Macronutrients are essential elements which are present in easily detectable quantities,$1-10 \ mg$ per gram of dry weight. The macronutrients include carbon,hydrogen,oxygen,nitrogen,phosphorus,sulphur,potassium,calcium,and magnesium.
Micronutrients,or trace elements,are needed in very small amounts (equal to or less than $0.1 \ mg/g$ of dry matter). These include iron,manganese,copper,molybdenum,zinc,boron,chlorine,and nickel.
56
BiologyMediumMCQNEET · 2016
The process which makes a major difference between $C_3$ and $C_4$ plants is
A
glycolysis
B
Calvin cycle
C
photorespiration
D
respiration

Solution

(C) : Photorespiration is the light-dependent process of oxygenation of ribulose bisphosphate $(RuBP)$ and the release of carbon dioxide by the photosynthetic organs of a plant.
It leads to the oxidation of a considerable amount of photosynthetic products into $CO_2$ and $H_2O$ without the production of useful energy.
Photorespiration occurs significantly in $C_3$ plants because,at high temperatures and high oxygen concentrations,the enzyme $RuBP$ carboxylase acts as $RuBP$ oxygenase.
Photorespiration is essentially absent in $C_4$ plants due to their specialized anatomy (Kranz anatomy) which maintains a high $CO_2$ concentration around the enzyme.
Peroxisomes and mitochondria are required for completing this process.
57
BiologyMediumMCQNEET · 2016
Water vapour comes out from the plant leaf through the stomatal opening. Through the same stomatal opening,carbon dioxide diffuses into the plant during photosynthesis. Reason out the above statements using one of the following options.
A
The above processes happen only during night time.
B
One process occurs during day time and the other at night.
C
Both processes cannot happen simultaneously.
D
Both processes can happen together because the diffusion coefficient of water and $CO_2$ is different.

Solution

(D) The correct answer is $D$. Transpiration (loss of water vapour) and photosynthesis (uptake of $CO_2$) occur through the stomata. These two processes can occur simultaneously because the diffusion of gases is independent of each other. The rate of diffusion depends on the diffusion coefficient of the specific gas and the concentration gradient. Since water vapour and $CO_2$ have different diffusion coefficients,they can diffuse in opposite directions through the same stomatal pore at the same time.
58
BiologyMediumMCQNEET · 2016
In a chloroplast,the highest number of protons are found in:
A
intermembrane space
B
antennae complex
C
stroma
D
lumen of thylakoids

Solution

(D) During the light-dependent reactions of photosynthesis,protons $(H^+)$ are pumped from the stroma into the lumen of the thylakoids. This process is driven by the electron transport chain and the photolysis of water. As a result,a high concentration of protons accumulates within the thylakoid lumen,creating a proton gradient across the thylakoid membrane. This gradient is essential for the synthesis of $ATP$ via the enzyme $ATP$ synthase. Therefore,the highest concentration of protons is found in the lumen of the thylakoids.
59
BiologyMediumMCQNEET · 2016
Emerson's enhancement effect and Red drop have been instrumental in the discovery of
A
photophosphorylation and cyclic electron transport
B
oxidative phosphorylation
C
photophosphorylation and non-cyclic electron transport
D
two photosystems operating simultaneously.

Solution

(D) : Emerson et al. $(1957)$ found that if light of shorter wavelengths was provided at the same time as the longer red wavelengths,photosynthesis was even faster than the sum of the two rates with either colour alone. This synergism or enhancement became known as the Emerson enhancement effect. The two separate groups of pigments or photosystems cooperate in photosynthesis and that such long red wavelengths are absorbed only by one photosystem,called photosystem $I$ $(PS\ I)$. The second photosystem,photosystem $II$ $(PS\ II)$,absorbs wavelengths shorter than $690 \ nm$,and for maximum photosynthesis,wavelengths absorbed by both systems must function together. The two photosystems normally cooperate to cause photosynthesis at all wavelengths shorter than $690 \ nm$,because both photosystems absorb those wavelengths. The importance of Emerson's work is that it suggested the presence of two distinct photosystems.
60
BiologyMediumMCQNEET · 2016
$A$ plant in your garden avoids photorespiratory losses,has improved water use efficiency,shows high rates of photosynthesis at high temperatures,and has improved efficiency of nitrogen utilisation. In which of the following physiological groups would you assign this plant?
A
$CAM$
B
Nitrogen fixer
C
$C_3$
D
$C_4$

Solution

(D) The correct answer is $(d) C_4$ plants.
$C_4$ plants are specifically adapted to minimize photorespiration because they possess a specialized anatomy called Kranz anatomy,which separates the initial $CO_2$ fixation from the Calvin cycle.
These plants show high rates of photosynthesis even at high temperatures.
They exhibit improved water use efficiency compared to $C_3$ plants because they can fix $CO_2$ even when stomata are partially closed.
Additionally,$C_4$ plants have a higher nitrogen-use efficiency because they require less Rubisco enzyme to fix the same amount of carbon compared to $C_3$ plants.
61
BiologyEasyMCQNEET · 2016
Water soluble pigments found in plant cell vacuoles are
A
carotenoids
B
anthocyanins
C
xanthophylls
D
chlorophylls

Solution

(B) : Anthocyanins are water-soluble pigments that are commonly found in membrane-bound vacuoles. They are responsible for the red,purple,and blue colors of many fruits and flower petals.
62
BiologyMediumMCQNEET · 2016
Which of the following biomolecules is common to respiration-mediated breakdown of fats,carbohydrates,and proteins?
A
Glucose$-6-$phosphate
B
Fructose $1,6-$bisphosphate
C
Pyruvic acid
D
Acetyl CoA

Solution

(D) The correct answer is $(d)$. Carbohydrates are usually first converted into glucose before they are used for respiration.
Fats are broken down into glycerol and fatty acids. Fatty acids are degraded to acetyl CoA to enter the respiratory pathway,while glycerol is converted to $3-$phosphoglyceraldehyde $(PGAL)$.
Proteins are degraded by proteases into individual amino acids. After deamination,these amino acids enter the respiratory pathway at different stages,such as pyruvate,acetyl CoA,or intermediates of the Krebs' cycle.
Thus,acetyl CoA acts as a common metabolic intermediate for the breakdown of all three major biomolecules (carbohydrates,proteins,and fats),making the respiratory pathway an amphibolic pathway.
63
BiologyMediumMCQNEET · 2016
Oxidative phosphorylation is
A
formation of $ATP$ by transfer of phosphate group from a substrate to $ADP$
B
oxidation of phosphate group in $ATP$
C
addition of phosphate group to $ATP$
D
formation of $ATP$ by energy released from electrons removed during substrate oxidation.

Solution

(D) Oxidative phosphorylation is the synthesis of energy-rich $ATP$ molecules using the energy liberated during the oxidation of reduced coenzymes $(NADH, FADH_2)$ produced during respiration.
The enzyme required for this synthesis is called $ATP$ synthase.
It is located in the $F_1$ headpiece of the $F_0-F_1$ complex (elementary particles) present in the inner mitochondrial membrane.
The $F_1$ particle is capable of $ATP$ synthesis.
$ATP$ synthase becomes active in $ATP$ formation only when there is a proton gradient with a higher concentration of $H^+$ ions on the $F_0$ side compared to the $F_1$ side.
This concentration difference creates an electric potential across the mitochondrial membrane.
The proton gradient and membrane electric potential together form the proton motive force $(PMF)$.
The flow of protons through the $F_0$ channel induces the $F_1$ particle to function as $ATP$ synthase.
The energy of the proton gradient is used to attach a phosphate group to $ADP$ via a high-energy bond,producing $ATP$.
64
BiologyMediumMCQNEET · 2016
You are given a tissue with its potential for differentiation in an artificial culture. Which of the following pairs of hormones would you add to the medium to secure shoots as well as roots?
A
$IAA$ and gibberellin
B
Auxin and cytokinin
C
Auxin and abscisic acid
D
Gibberellin and abscisic acid

Solution

(B) The correct answer is $B$. Cytokinin and auxin are two essential plant hormones added to the tissue culture medium in specific proportions to regulate morphogenesis.
These hormones induce cell division and the differentiation of the callus.
Specifically,a low auxin-to-cytokinin ratio promotes the formation of shoots,while a high auxin-to-cytokinin ratio promotes the development of roots in the callus.
65
BiologyEasyMCQNEET · 2016
Phytochrome is a
A
flavoprotein
B
glycoprotein
C
lipoprotein
D
chromoprotein

Solution

(D) : Phytochrome is a chromoprotein,a plant pigment that can detect the presence or absence of light. It is involved in regulating many processes linked to day length (photoperiod),such as seed germination and the initiation of flowering.
It consists of a light-detecting portion,called a chromophore,linked to a protein moiety.
It exists in two interconvertible forms,$Pr$ and $Pfr$,which possess different physical and chemical properties.
66
BiologyMediumMCQNEET · 2016
The Avena curvature test is used for the bioassay of
A
$IAA$
B
ethylene
C
$ABA$
D
$GA_3$

Solution

(A) $Avena$ curvature test is a bioassay based on the experiments of Went $(1928)$,which can measure auxin concentration up to $300 \ mg/litre$.
Indole-$3$-Acetic Acid $(IAA)$ is a universal natural auxin,and the $Avena$ curvature test serves as an accurate bioassay for this specific plant hormone.
67
BiologyMediumMCQNEET · 2016
Which hormones stimulate the production of pancreatic juice and bicarbonate?
A
Angiotensin and epinephrine
B
Gastrin and insulin
C
Cholecystokinin and secretin
D
Insulin and glucagon

Solution

(C) The correct answer is $C$.
$1$. Cholecystokinin $(CCK)$ is a hormone secreted by the $I$-cells of the duodenum and jejunum. It stimulates the pancreas to secrete and release digestive enzymes into the pancreatic juice and also causes the contraction of the gall bladder to release bile.
$2$. Secretin is a hormone secreted by the $S$-cells of the duodenum in response to low $pH$ (acidic chyme). It primarily stimulates the pancreatic ducts to secrete a fluid rich in bicarbonate ions $(HCO_3^-)$,which helps neutralize the acidic chyme in the duodenum.
68
BiologyEasyMCQNEET · 2016
Which of the following guards the opening of the hepatopancreatic duct into the duodenum?
A
Pyloric sphincter
B
Sphincter of Oddi
C
Semilunar valve
D
Ileocaecal valve

Solution

(B) The correct answer is $B$. The $Sphincter$ \text{ of } $Oddi$ is a muscular valve that regulates the flow of digestive juices, specifically bile and pancreatic juice, from the hepatopancreatic duct into the duodenum. It ensures that these secretions enter the small intestine only when required for digestion.
69
BiologyEasyMCQNEET · 2016
In the stomach,gastric acid is secreted by the
A
peptic cells
B
acidic cells
C
gastrin secreting cells
D
parietal cells

Solution

(D) : Parietal cells,also known as oxyntic cells,are large cells present on the side walls of the gastric glands.
They lie against the basement membrane.
They secrete hydrochloric acid $(HCl)$ and Castle's intrinsic factor,which is essential for the absorption of vitamin $B_{12}$ in the ileum.
70
BiologyMediumMCQNEET · 2016
The partial pressure of oxygen in the alveoli of the lungs is
A
equal to that in the blood
B
more than that in the blood
C
less than that in the blood
D
less than that of carbon dioxide.

Solution

(B) The partial pressure of oxygen $(pO_2)$ in the alveoli is approximately $104 \ mm \ Hg$.
In contrast,the $pO_2$ in deoxygenated blood is $40 \ mm \ Hg$ and in oxygenated blood is $95 \ mm \ Hg$.
Since the partial pressure of oxygen in the alveoli is higher than that in the blood,oxygen diffuses from the alveoli into the blood.
Therefore,the correct option is $B$.
71
BiologyMediumMCQNEET · 2016
Lungs do not collapse between breaths and some air always remains in the lungs which can never be expelled because
A
there is a negative pressure in the lungs
B
there is a negative intrapleural pressure pulling at the lung walls
C
there is a positive intrapleural pressure
D
pressure in the lungs is higher than the atmospheric pressure.

Solution

(B) : Intrapleural pressure is the pressure within the pleural cavity.
Intrapleural pressure is always negative,which acts like a suction to keep the lungs inflated and prevent them from collapsing.
The negative intrapleural pressure is due to three main factors: surface tension of the alveolar fluid,elasticity of the lungs,and elasticity of the thoracic wall.
Normally,there is a difference between intrapleural and intrapulmonary pressure,which is called transpulmonary pressure.
This transpulmonary pressure creates the suction to keep the lungs inflated.
If there is no pressure difference,there is no suction and the lungs will collapse.
72
BiologyMediumMCQNEET · 2016
Reduction in $pH$ of blood will
A
decrease the affinity of haemoglobin with oxygen
B
release bicarbonate ions by the liver
C
reduce the rate of heart beat
D
reduce the blood supply to the brain

Solution

(A) The correct answer is $A$.
Reduction in $pH$ of blood (increase in $H^+$ ion concentration) causes the oxygen-haemoglobin dissociation curve to shift to the right,a phenomenon known as the Bohr effect.
This shift indicates a decrease in the affinity of haemoglobin for oxygen,facilitating the dissociation of oxygen from haemoglobin at the tissue level where $pH$ is lower.
73
BiologyMediumMCQNEET · 2016
Name the chronic respiratory disorder caused mainly by cigarette smoking.
A
Respiratory acidosis
B
Respiratory alkalosis
C
Emphysema
D
Asthma

Solution

(C) : Emphysema is a chronic obstructive pulmonary disease $(COPD)$ caused mainly due to cigarette smoking.
It is a condition characterized by the abnormal distension of the bronchioles or alveolar sacs of the lungs.
This leads to the irreversible damage and loss of elasticity of the alveolar walls,which reduces the surface area available for gas exchange.
74
BiologyMediumMCQNEET · 2016
Asthma may be attributed to
A
inflammation of the trachea
B
accumulation of fluid in the lungs
C
bacterial infection of the lungs
D
allergic reaction of the mast cells in the lungs.

Solution

(D) : Asthma is an allergic condition in which the tissue surrounding the bronchioles of the lungs swell up and compress the bronchioles,thus causing difficulty in breathing.
This allergy mainly involves $IgE$ antibodies and the release of chemicals like histamine and serotonin from the mast cells in the lungs.
75
BiologyMediumMCQNEET · 2016
Name the blood cells,whose reduction in number can cause clotting disorder,leading to excessive loss of blood from the body.
A
Erythrocytes
B
Leucocytes
C
Neutrophils
D
Thrombocytes

Solution

(D) : Thrombocytes are also known as blood platelets. They are minute,disc-shaped cell fragments found in mammalian blood. They are formed as fragments of larger cells called megakaryocytes in the red bone marrow and lack a nucleus. They play a crucial role in blood clotting by releasing substances like thromboxane $A_2$,serotonin,and other clotting factors. These chemicals initiate a chain of events that form a plug at the site of injury,preventing excessive blood loss. $A$ significant reduction in their number leads to clotting disorders,resulting in excessive bleeding from the body.
76
BiologyMediumMCQNEET · 2016
Serum differs from blood in
A
lacking globulins
B
lacking albumins
C
lacking clotting factors
D
lacking antibodies

Solution

(C) $Serum$ is the fluid that remains after blood has clotted.
When blood is allowed to clot, the clotting factors, such as $fibrinogen$, are consumed in the process of forming the clot.
Therefore, $serum$ is essentially blood plasma from which the clotting factors have been removed.
Thus, the correct answer is $C$.
77
BiologyMediumMCQNEET · 2016
Blood pressure in the pulmonary artery is
A
more than that in the pulmonary vein
B
less than that in the venae cavae
C
same as that in the aorta
D
more than that in the carotid artery

Solution

(A) The blood pressure in the pulmonary artery is higher than that in the pulmonary vein.
$1$. The pulmonary artery carries deoxygenated blood from the right ventricle to the lungs.
$2$. The pulmonary vein carries oxygenated blood from the lungs to the left atrium.
$3$. Since the pulmonary artery is closer to the pumping action of the heart (right ventricle) and the pulmonary vein is a venous vessel returning blood to the heart,the pressure in the artery is significantly higher than in the vein.
78
BiologyMediumMCQNEET · 2016
In mammals,which blood vessel would normally carry the largest amount of urea?
A
Hepatic Vein
B
Hepatic Portal Vein
C
Renal Vein
D
Dorsal Aorta

Solution

(A) The correct answer is $A$.
Urea is synthesized in the liver through the ornithine cycle (urea cycle) as a byproduct of amino acid metabolism.
Since the liver is the site of urea production,the blood leaving the liver via the hepatic vein contains the highest concentration of urea in the body.
In contrast,the renal vein carries blood away from the kidneys,which have already filtered the urea out of the blood,resulting in a lower concentration of urea compared to the hepatic vein.
79
BiologyEasyMCQNEET · 2016
The part of the nephron involved in the active reabsorption of sodium is
A
Distal convoluted tubule
B
Proximal convoluted tubule
C
Bowman's capsule
D
Descending limb of Henle's loop

Solution

(B) : From the Bowman's capsule,glomerular filtrate enters the proximal convoluted tubule $(PCT)$.
Absorption of selected materials takes place from the filtrate into the blood of the peritubular capillaries or vasa recta,which is termed tubular reabsorption.
Reabsorption involves both passive and active transport across the tubular epithelium.
About $65$ percent of the glomerular filtrate is normally reabsorbed in the $PCT$ before reaching the loop of Henle.
Glucose,amino acids,vitamins,hormones,sodium $(Na^+)$,potassium $(K^+)$,chlorides,phosphates,bicarbonates,much of the water,and some urea are absorbed here.
Sodium and potassium are reabsorbed primarily by active transport.
80
BiologyMediumMCQNEET · 2016
Name the ion responsible for unmasking of active sites for myosin for cross-bridge activity during muscle contraction.
A
Calcium
B
Magnesium
C
Sodium
D
Potassium

Solution

(A) During muscle contraction,the $Ca^{2+}$ ions play a critical role.
When a signal from the motor neuron reaches the muscle fiber,$Ca^{2+}$ ions are released into the sarcoplasm.
These $Ca^{2+}$ ions bind to the $Troponin$ subunit on the actin filaments.
This binding causes a conformational change in the $Troponin-Tropomyosin$ complex,which shifts the $Tropomyosin$ away from the active sites on the $F-actin$ filaments.
By unmasking these active sites,the $Myosin$ heads can bind to them to form cross-bridges,leading to muscle contraction.
81
BiologyMediumMCQNEET · 2016
Osteoporosis,an age-related disease of the skeletal system,may occur due to:
A
immune disorder affecting the neuromuscular junction leading to fatigue
B
high concentration of $Ca$ and $Na$
C
decreased level of estrogen
D
accumulation of uric acid leading to inflammation of joints

Solution

(C) Osteoporosis is a condition characterized by a reduction in bone mineral density,which makes bones brittle and prone to fractures.
Generalised osteoporosis is common in the elderly and in women after menopause.
After menopause,the levels of the hormone estrogen in the blood plasma are significantly reduced.
Estrogen plays a crucial role in regulating bone cells,specifically osteoblasts (which build bone) and inhibiting excessive activity of osteoclasts (which break down bone).
When estrogen levels drop,the balance of bone remodeling is disrupted,leading to bone loss and osteoporosis.
82
BiologyEasyMCQNEET · 2016
Lack of relaxation between successive stimuli in sustained muscle contraction is known as
A
tetanus
B
tonus
C
spasm
D
fatigue

Solution

(A) : Tetanus refers to a sustained state of muscle contraction resulting from the summation of a series of rapid muscular contractions (twitches) that are induced by repeated stimulation of the muscle. When the frequency of stimuli is high enough that the muscle cannot relax between them,the contractions fuse into a smooth,sustained contraction.
83
BiologyMediumMCQNEET · 2016
Choose the correct statement.
A
Nociceptors respond to changes in pressure.
B
Meissner's corpuscles are thermoreceptors.
C
Photoreceptors in the human eye are depolarised during darkness and become hyperpolarised in response to the light stimulus.
D
Receptors do not produce graded potentials.

Solution

(C) The correct statement is $C$.
Photoreceptors in the human eye are unique because they are the only type of sensory cells that are relatively depolarised (about $-35 \ mV$) when at rest (i.e.,in the dark),and they become hyperpolarised (to about $-70 \ mV$) in response to an adequate light stimulus.
Nociceptors respond to potentially damaging stimuli that result in pain,not pressure.
Meissner's corpuscles are a type of mechanoreceptor responsible for touch sensitivity,not thermoreception.
Receptors generally produce graded potentials known as receptor potentials.
84
BiologyEasyMCQNEET · 2016
Photosensitive compound in human eye is made up of
A
opsin and retinol
B
transducin and retinene
C
guanosine and retinol
D
opsin and retinal

Solution

(D) The correct answer is $D$.
In the human eye,the rods contain a photosensitive pigment known as rhodopsin.
Rhodopsin is a conjugated protein composed of two parts: a protein component called opsin and a light-absorbing pigment called retinal.
Retinal is an aldehyde derivative of vitamin $A$.
When light strikes the rhodopsin,it causes the dissociation of retinal from opsin,which triggers the nerve impulse.
85
BiologyMediumMCQNEET · 2016
Graves' disease is caused due to
A
hyposecretion of thyroid gland
B
hypersecretion of thyroid gland
C
hyposecretion of adrenal gland
D
hypersecretion of adrenal gland

Solution

(B) : Exophthalmic goitre or Graves' disease is a thyroid enlargement (goitre) in which the thyroid gland secretes an excessive amount of thyroid hormones.
It is characterized by exophthalmia (protrusion of eyeballs due to fluid accumulation behind them),weight loss,a slight rise in body temperature,excitability,rapid heartbeat,nervousness,and restlessness.
86
BiologyMediumMCQNEET · 2016
Name a peptide hormone which acts mainly on hepatocytes, adipocytes and enhances cellular glucose uptake and utilisation.
A
Insulin
B
Glucagon
C
Secretin
D
Gastrin

Solution

(A) $Insulin$ is a peptide hormone secreted by the $\beta$-cells of the islets of $Langerhans$ in the pancreas.
It acts mainly on hepatocytes (liver cells) and adipocytes (fat cells).
It enhances cellular glucose uptake and utilisation, thereby lowering blood glucose levels.
87
BiologyMediumMCQNEET · 2016
The posterior pituitary gland is not a 'true' endocrine gland because
A
it is provided with a duct
B
it only stores and releases hormones
C
it is under the regulation of hypothalamus
D
it secretes enzymes.

Solution

(B) : The posterior lobe of the pituitary gland does not synthesize any hormones.
Its hormones,specifically $Oxytocin$ and $Vasopressin$ $(ADH)$,are synthesized by the neurosecretory cells of the hypothalamus.
The posterior pituitary only stores and releases these hormones into the bloodstream.
Therefore,it is not considered a 'true' endocrine gland as it lacks the secretory function characteristic of endocrine tissues.
88
BiologyMediumMCQNEET · 2016
Which of the following pairs of hormones are not antagonistic (having opposite effects) to each other?
A
Aldosterone $\implies$ Atrial Natriuretic Factor
B
Relaxin $\implies$ Inhibin
C
Parathormone $\implies$ Calcitonin
D
Insulin $\implies$ Glucagon

Solution

(B) The correct answer is $(b)$.
Antagonistic hormones are those that have opposite effects on a physiological process.
$(a)$ Aldosterone increases blood pressure by retaining sodium,while Atrial Natriuretic Factor $(ANF)$ decreases blood pressure by promoting sodium excretion. They are antagonistic.
$(c)$ Parathormone increases blood calcium levels,while Calcitonin decreases blood calcium levels. They are antagonistic.
$(d)$ Insulin decreases blood glucose levels,while Glucagon increases blood glucose levels. They are antagonistic.
$(b)$ Relaxin is involved in relaxing pelvic ligaments and softening the cervix during childbirth,whereas Inhibin inhibits the secretion of $FSH$ from the anterior pituitary. Since they perform distinct,non-opposing functions,they are not antagonistic.
89
BiologyEasyMCQNEET · 2016
The amino acid tryptophan is the precursor for the synthesis of
A
estrogen and progesterone
B
cortisol and cortisone
C
melatonin and serotonin
D
thyroxine and triiodothyronine

Solution

(C) Tryptophan is an essential amino acid that serves as a precursor for the synthesis of the neurotransmitter serotonin and the hormone melatonin.
Serotonin is synthesized from tryptophan via the intermediate $5-hydroxytryptophan$.
Melatonin is subsequently synthesized from serotonin in the pineal gland.
90
BiologyMediumMCQNEET · 2016
$A$ cell at the telophase stage is observed by a student in a plant brought from the field. He tells his teacher that this cell is not like other cells at the telophase stage. There is no formation of a cell plate,and thus the cell contains a higher number of chromosomes compared to other dividing cells. This would result in:
A
somaclonal variation
B
polyteny
C
aneuploidy
D
polyploidy

Solution

(D) : Polyploidy is the phenomenon of the occurrence of more than two sets of chromosomes in the nucleus of a cell.
Polyploidy is more common in plants.
It arises as a result of the total non-disjunction of chromosomes during mitosis or meiosis,where the cell fails to divide after the replication of chromosomes,leading to an increase in the ploidy level.
91
BiologyMediumMCQNEET · 2016
It is much easier for a small animal to run uphill than for a large animal,because
A
small animals have a lower $O_2$ requirement
B
smaller animals have a higher metabolic rate
C
it is easier to carry a small body weight
D
the efficiency of muscles in large animals is less than in the small animals

Solution

(B) The metabolic rate of an organism is inversely proportional to its body size.
Smaller animals have a higher surface area to volume ratio,which results in a higher metabolic rate to maintain their body temperature and physiological functions.
Because of this higher metabolic rate,small animals can generate energy more rapidly,allowing them to perform strenuous activities like running uphill more easily compared to larger animals,which have a lower metabolic rate relative to their body size.
Therefore,the correct option is $(b)$.
92
BiologyMediumMCQNEET · 2016
The cortex is found between which of the following?
A
Endodermis and pith
B
Endodermis and vascular bundles
C
Epidermis and stele
D
Pericycle and endodermis

Solution

(C) In the anatomy of dicot stems and roots,the cortex is the region located between the epidermis (the outermost layer) and the stele (the central part containing vascular tissues).
Therefore,the cortex is found between the epidermis and the stele.
93
BiologyMediumMCQNEET · 2016
Identify the incorrect match.
A
Protista - Eukaryotes
B
Methanogens - Prokaryotes
C
Gas vacuoles - Green bacteria
D
Large central vacuoles - Animal cells

Solution

(D) The correct answer is $D$.
$A$. Protists are eukaryotic organisms,which is correct.
$B$. Methanogens are archaebacteria,which are prokaryotic,which is correct.
$C$. Gas vacuoles are found in blue-green,purple,and green photosynthetic bacteria,which is correct.
$D$. Large central vacuoles are characteristic of plant cells,not animal cells. Animal cells typically have small,temporary vacuoles or lack them entirely. Therefore,this is the incorrect match.
94
BiologyMediumMCQNEET · 2016
Identify the incorrect statement.
A
Cyanobacteria do not possess flagellated cells.
B
Mycoplasma are the smallest organisms lacking a cell wall.
C
The bacterial cell wall is composed of peptidoglycan.
D
Pili and fimbriae are involved in the motility of bacterial cells.

Solution

(D) The correct answer is $D$.
$A$: Cyanobacteria (blue-green algae) are photosynthetic prokaryotes that lack flagella throughout their life cycle. This statement is correct.
$B$: Mycoplasma are the smallest known living cells and they completely lack a cell wall,making them resistant to many antibiotics. This statement is correct.
$C$: The cell wall of bacteria is made up of peptidoglycan (murein). This statement is correct.
$D$: Pili and fimbriae are surface structures of bacteria. Pili are involved in conjugation (transfer of $DNA$),and fimbriae are involved in attachment to rocks or host tissues. Neither of these structures is involved in motility. Flagella are the primary structures responsible for bacterial motility. Therefore,this statement is incorrect.
95
BiologyEasyMCQNEET · 2016
Which organelle contains hydrolytic enzymes?
A
Ribosome
B
Mesosome
C
Lysosome
D
Microsome

Solution

(C) Lysosomes are membrane-bound vesicular structures formed by the process of packaging in the Golgi apparatus. They are rich in hydrolytic enzymes (hydrolases - lipases,proteases,carbohydrases) that are optimally active at the acidic $pH$. These enzymes are capable of digesting carbohydrates,proteins,lipids,and nucleic acids.
96
BiologyMediumMCQNEET · 2016
Microtubules are found in the structure of which of the following?
A
Spindle fibers, centrioles, and cilia
B
Centrioles, spindle fibers, and chromatin
C
Centrosome, nucleosomes, and centrioles
D
Cilia, flagella, and peroxisomes

Solution

(A) Microtubules are hollow, cylindrical structures composed of tubulin proteins. They form the structural components of the cytoskeleton.
Specifically, they are the primary building blocks of:
$1$. $Spindle fibers$: Essential for chromosome movement during cell division.
$2$. $Centrioles$: Cylindrical structures that organize the spindle apparatus.
$3$. $Cilia and flagella$: Hair-like appendages involved in cell movement, which possess a $9+2$ arrangement of microtubules.
Chromatin, nucleosomes, and peroxisomes do not contain microtubules as their structural components.
97
BiologyMediumMCQNEET · 2016
Mitochondria and chloroplasts:
$(a)$ Are semi-autonomous organelles.
$(b)$ Are formed by the division of pre-existing organelles. They contain $DNA$,but lack protein-synthesizing machinery.
Which of the following options is correct?
A
$(b)$ is correct,while $(a)$ is incorrect.
B
$(a)$ is correct,but $(b)$ is incorrect.
C
Both $(a)$ and $(b)$ are incorrect.
D
Both $(a)$ and $(b)$ are correct.

Solution

(B) Mitochondria and chloroplasts are known as semi-autonomous organelles because they possess their own $DNA$ and ribosomes.
Statement $(a)$ is correct as they are semi-autonomous.
Statement $(b)$ is incorrect because,although they contain $DNA$,they also contain ribosomes (specifically $70S$ ribosomes in prokaryotic-like fashion) which are the machinery for protein synthesis.
Therefore,$(a)$ is correct,but $(b)$ is incorrect.
98
BiologyEasyMCQNEET · 2016
Which of the following cell organelles is surrounded by a single membrane?
A
Chloroplast
B
Lysosomes
C
Nucleolus
D
Mitochondria

Solution

(B) $1$. Chloroplast is a double-membrane-bound organelle.
$2$. Lysosomes are single-membrane-bound organelles containing hydrolytic enzymes.
$3$. Nucleolus is a non-membrane-bound structure found inside the nucleus.
$4$. Mitochondria is a double-membrane-bound organelle.
Therefore, the correct answer is Lysosomes.
99
BiologyEasyMCQNEET · 2016
Where are the water-soluble pigments found in the vacuoles of plant cells?
A
Chlorophyll
B
Carotenoids
C
Anthocyanins
D
Xanthophylls

Solution

(C) In plant cells,the vacuole is a membrane-bound organelle that stores various substances. Water-soluble pigments,such as anthocyanins,are dissolved in the cell sap within the vacuole. These pigments are responsible for the red,purple,or blue colors in many flowers and fruits. Chlorophyll,carotenoids,and xanthophylls are typically found in plastids (like chloroplasts) and are generally fat-soluble,not water-soluble.
100
BiologyMediumMCQNEET · 2016
Smooth muscle tissue is ...
A
Involuntary,cylindrical,and striated.
B
Voluntary,fusiform,and uninucleate.
C
Involuntary,fusiform,and non-striated.
D
Voluntary,multinucleate,and cylindrical.

Solution

(C) Smooth muscle tissue (also known as visceral muscle) is characterized by the following features:
$1$. It is involuntary,meaning it is not under conscious control.
$2$. The cells are fusiform (spindle-shaped) in structure.
$3$. It is non-striated (smooth) because it lacks the regular arrangement of actin and myosin filaments found in skeletal muscle.
$4$. Each cell contains a single nucleus (uninucleate).
Therefore,the correct description is involuntary,fusiform,and non-striated.
101
BiologyMediumMCQNEET · 2016
In higher vertebrates,the immune system can distinguish self-cells and non-self. If this property is lost due to genetic abnormality and it attacks self-cells,then it leads to
A
autoimmune disease
B
active immunity
C
allergic response
D
graft rejection

Solution

(A) : Autoimmunity is a disorder of the body's defence mechanisms in which an immune response is elicited against its own tissues,which are thereby damaged or destroyed.
Autoimmunity may be caused due to genetic or environmental factors.
102
BiologyEasyMCQNEET · 2016
$A$ true breeding plant is
A
one that is able to breed on its own
B
produced due to cross-pollination among unrelated plants
C
near homozygous and produces offspring of its own kind
D
always homozygous recessive in its genetic constitution.

Solution

(C) true breeding plant is one that,when self-pollinated,consistently produces offspring with the same traits as the parent.
This occurs because the plant is near homozygous for the traits in question.
Therefore,it maintains its genetic purity over successive generations.
Option $C$ is the correct definition.
103
BiologyEasyMCQNEET · 2016
Interspecific hybridisation is the mating of
A
animals within the same breed without having common ancestors
B
two different related species
C
superior males and females of different breeds
D
more closely related individuals within the same breed for $4-6$ generations

Solution

(B) : In interspecific hybridisation,a species is mated with a different related species of the same genus.
Interspecific hybrids are generally difficult to produce,but they are important in plant breeding,particularly in breeding for disease resistance.
This is also called intrageneric hybridisation.
104
BiologyEasyMCQNEET · 2016
Among the following edible fishes,which one is a marine fish having a rich source of omega-$3$ fatty acids?
A
Mystus
B
Mangur
C
Mrigala
D
Mackerel

Solution

(D) The correct answer is $(d)$.
$Mackerel$ is a marine fish that is a rich source of omega-$3$ fatty acids.
$Mystus$,$Mangur$ (Clarias batrachus),and $Mrigala$ (Cirrhinus mrigala) are freshwater fishes.
105
BiologyEasyMCQNEET · 2016
$A$ system of rotating crops with legume or grass pasture to improve soil structure and fertility is called
A
strip farming
B
shifting agriculture
C
ley farming
D
contour farming

Solution

(C) : Ley farming is an agricultural system where the field is alternately seeded for grain and left fallow for growing hay or used for pasture.
During the fallow or pasture period,the soil is filled with the roots of grasses and other plants.
Subsequent ploughing mixes these organic materials into the soil,which improves soil structure and increases the nitrogen content,especially when legume forage crops are used.
This practice also protects the soil from erosion by maintaining constant soil coverage.
106
BiologyMediumMCQNEET · 2016
Match column $I$ with column $II$ and select the correct option using the codes given below.
Column-$I$Column-$II$
$(A)$ Citric acid$(i)$ Trichoderma
$(B)$ Cyclosporin $A$$(ii)$ Clostridium
$(C)$ Statins$(iii)$ Aspergillus
$(D)$ Butyric acid$(iv)$ Monascus
A
$A-(iii), B-(i), C-(ii), D-(iv)$
B
$A-(iii), B-(i), C-(iv), D-(ii)$
C
$A-(i), B-(iv), C-(ii), D-(iii)$
D
$A-(iii), B-(iv), C-(i), D-(ii)$

Solution

(B) The correct matches are as follows:
$(A)$ Citric acid is produced by the fungus $Aspergillus$ $niger$ $(iii)$.
$(B)$ Cyclosporin $A$ is an immunosuppressive agent produced by the fungus $Trichoderma$ $polysporum$ $(i)$.
$(C)$ Statins are blood-cholesterol lowering agents produced by the yeast $Monascus$ $purpureus$ $(iv)$.
$(D)$ Butyric acid is produced by the bacterium $Clostridium$ $butylicum$ $(ii)$.
Therefore, the correct matching is $A-(iii), B-(i), C-(iv), D-(ii)$.
The correct option is $(B)$.
107
BiologyMediumMCQNEET · 2016
Which of the following is wrongly matched in the given table?
MicrobeProductApplication
$(a)$ StreptococcusStreptokinaseRemoval of clot from blood vessel
$(b)$ Clostridium butylicumLipaseRemoval of oil stains
$(c)$ Trichoderma polysporumCyclosporin $A$Immuno-suppressive drug
$(d)$ Monascus purpureusStatinsLowering of blood cholesterol
A
$(a)$
B
$(b)$
C
$(c)$
D
$(d)$

Solution

(B) The correct answer is $(b)$.
$Clostridium$ $butylicum$ is a bacterium used for the production of butyric acid, not lipase.
Lipases are enzymes produced by microorganisms like $Candida$ $lipolytica$ or $Geotrichum$ $candidum$. These enzymes are used in detergent formulations to help remove oily stains from laundry.
Other options are correctly matched:
- $Streptococcus$ produces streptokinase, which acts as a 'clot buster' for removing clots from the blood vessels of patients who have undergone myocardial infarction.
- $Trichoderma$ $polysporum$ is a fungus that produces Cyclosporin $A$, which is used as an immuno-suppressive agent in organ transplant patients.
- $Monascus$ $purpureus$ is a yeast that produces statins, which act by competitively inhibiting the enzyme responsible for the synthesis of cholesterol.
108
BiologyMediumMCQNEET · 2016
Which kind of therapy was given in $1990$ to a four-year-old girl with adenosine deaminase $(ADA)$ deficiency?
A
Gene therapy
B
Chemotherapy
C
Immunotherapy
D
Radiation therapy

Solution

(A) : Gene therapy is a technique of genetic engineering which involves the replacement of a faulty or disease-causing gene with a normal,healthy,functional gene.
In $1990$,the first clinical gene therapy was administered to a $4$-year-old girl suffering from adenosine deaminase $(ADA)$ deficiency.
This enzyme is crucial for the proper functioning of the immune system.
$A$ deficiency of this enzyme leads to severe combined immunodeficiency $(SCID)$.
109
BiologyMediumMCQNEET · 2016
The two polypeptides of human insulin are linked together by
A
covalent bond
B
disulphide bridges
C
hydrogen bonds
D
phosphodiester bond

Solution

(B) Human insulin is composed of $51$ amino acids arranged in two polypeptide chains.
Chain $A$ consists of $21$ amino acids,and chain $B$ consists of $30$ amino acids.
These two polypeptide chains are interconnected by disulphide bridges (or $S-S$ linkages).
110
BiologyMediumMCQNEET · 2016
Which part of the tobacco plant is infected by $Meloidogyne \ incognita$?
A
Stem
B
Root
C
Flower
D
Leaf

Solution

(B) $Meloidogyne \ incognita$ is a nematode that infects the roots of tobacco plants,causing a significant reduction in yield. This infection is prevented using $RNA$ interference $(RNAi)$ technology.
111
BiologyMediumMCQNEET · 2016
Which of the following is correct for $r$-selected species?
A
Large number of progeny with small size
B
Large number of progeny with large size
C
Small number of progeny with small size
D
Small number of progeny with large size

Solution

(A) $r$-selected species ($r$-strategists) are organisms that can colonize a habitat rapidly by utilizing available resources before competitors arrive.
These organisms typically have short life spans and small body sizes (e.g.,bacteria,many insects).
Their survival strategy relies on producing a large number of offspring to ensure that at least some survive in unstable or temporary environments,rather than investing energy in competitive ability or parental care.
112
BiologyMediumMCQNEET · 2016
If $'+'$ sign is assigned to beneficial interaction,$'-'$ sign to detrimental and $'O'$ sign to neutral interaction,then the population interaction represented by $'+, -'$ refers to
A
mutualism
B
amensalism
C
commensalism
D
parasitism

Solution

(D) The population interaction represented by $'+, -'$ is known as parasitism.
In this interaction,one species (the parasite) benefits $('+')$ while the other species (the host) is harmed $('-')$.
Parasitism is an association in which one organism (the parasite) lives on (ectoparasitism) or in (endoparasitism) the body of another organism (host),from which it obtains its nutrients.
This association is beneficial for the parasites as they get a continuous supply of nutrients from their host and are able to rapidly multiply their numbers.
However,it is detrimental for the host organism as parasitic infection leads to various complications and diseases in the host body,which may also be fatal to the host under certain circumstances.
113
BiologyMediumMCQNEET · 2016
The principle of competitive exclusion was stated by
A
$C$. Darwin
B
$G$.$F$. Gause
C
Mac Arthur
D
Verhulst and Pearl

Solution

(B) : Two or more species with closely similar niche requirements cannot exist indefinitely in the same area as sooner or later they come into competition for possession of it. This is called as Gause's competitive exclusion principle,which states that an ecological niche cannot be simultaneously and completely occupied by established populations of more than one species. Two species can live in the same habitat but not in the same niche. The more similar the two niches are,the more severe the competition is.
114
BiologyMediumMCQNEET · 2016
When does the growth rate of a population following the logistic model equal zero? The logistic model is given as $dN/dt = rN(1 - N/K)$.
A
when $N/K$ equals zero
B
when death rate is greater than birth rate
C
when $N/K$ is exactly one
D
when $N$ nears the carrying capacity of the habitat.

Solution

(C) The logistic growth model is represented by the equation $dN/dt = rN(1 - N/K)$.
Here,$dN/dt$ represents the population growth rate.
For the growth rate to be zero,$dN/dt = 0$.
Substituting this into the equation: $0 = rN(1 - N/K)$.
Since $r$ (intrinsic rate of natural increase) and $N$ (population size) are generally non-zero in an active population,the term $(1 - N/K)$ must be equal to zero.
This implies $1 - N/K = 0$,which simplifies to $N/K = 1$.
Therefore,the population growth rate becomes zero when the population size $N$ reaches the carrying capacity $K$ (i.e.,$N/K = 1$).
115
BiologyMediumMCQNEET · 2016
Gause's principle of competitive exclusion states that
A
no two species can occupy the same niche indefinitely for the same limiting resources
B
larger organisms exclude smaller ones through competition
C
more abundant species will exclude the less abundant species through competition
D
competition for the same resources exclude species having different food preferences.

Solution

(A) : Two or more species with closely similar niche requirements cannot exist indefinitely in the same area as sooner or later they come into competition for possession of it.
This is called Gause's competitive exclusion principle,which states that an ecological niche cannot be simultaneously and completely occupied by established populations of more than one species.
Two species can live in the same habitat but not in the same niche.
The more similar the two niches are,the more severe the competition is.
116
BiologyMediumMCQNEET · 2016
The primary producers of the deep-sea hydrothermal vent ecosystem are
A
green algae
B
chemosynthetic bacteria
C
blue-green algae
D
coral reefs

Solution

(B) The correct answer is $B$.
Hydrothermal vents are fissures in the ocean floor that release jets of hot water rich in minerals and $H_2S$.
In these extreme environments,sunlight is absent,so photosynthesis cannot occur.
Instead,chemosynthetic bacteria act as the primary producers.
These bacteria derive energy by oxidizing hydrogen sulfide $(H_2S)$ present in the vent water.
This energy is utilized to synthesize organic compounds from inorganic carbon sources.
Consequently,these bacteria form the foundation of the hydrothermal vent food web,supporting all other life forms in that ecosystem.
117
BiologyEasyMCQNEET · 2016
Which of the following would appear as the pioneer organisms on bare rocks?
A
Mosses
B
Green algae
C
Lichens
D
Liverworts

Solution

(C) The correct answer is $C$.
Bare rocky habitats are extremely hostile environments for living organisms.
These areas lack water because the rocky substratum cannot absorb or retain rainwater.
Additionally, there is no mechanism for nutrient retention, making it difficult for most plants to grow.
$Lichens$ are the pioneer species in such habitats because they are highly resistant to desiccation (drying out) and can withstand extreme temperature fluctuations.
They secrete acids that help in the weathering of rocks, which eventually leads to soil formation and allows other successional species to colonize the area.
118
BiologyMediumMCQNEET · 2016
Which one of the following is a characteristic feature of a cropland ecosystem?
A
Absence of weeds
B
Ecological succession
C
Absence of soil organisms
D
Least genetic diversity

Solution

(D) The correct answer is $(d)$.
Cropland ecosystems are artificial or man-made terrestrial ecosystems that are created and maintained by humans for agricultural productivity.
Because these systems are designed to favor a specific crop species (monoculture),they exhibit the least genetic diversity compared to natural ecosystems.
Weeds are often present,soil organisms are essential for soil health,and ecological succession is typically suppressed by human intervention.
119
BiologyEasyMCQNEET · 2016
The term ecosystem was coined by
A
$E$. Haeckel
B
$E$. Warming
C
$E$. $P$. Odum
D
$A$. $G$. Tansley

Solution

(D) The term ecosystem was coined by the British ecologist $A. G. Tansley$ in $1935$. An ecosystem is a functional unit of nature where living organisms interact among themselves and also with the surrounding physical environment.
120
BiologyMediumMCQNEET · 2016
How many hotspots of biodiversity in the world have been identified till date by Norman Myers?
A
$17$
B
$25$
C
$34$
D
$43$

Solution

(C) The concept of biodiversity hotspots was first proposed by Norman Myers in $1988$ to identify regions that are rich in biodiversity but are under serious threat of habitat loss.
Initially,he identified $10$ hotspots,which he later expanded to $25$ and eventually,with further research and global assessment,the number of identified biodiversity hotspots reached $34$.
These regions are characterized by high levels of plant endemism and significant loss of habitat.
Therefore,the correct answer is $34$.
121
BiologyMediumMCQNEET · 2016
Which of the following is correctly matched?
A
Aerenchyma - Opuntia
B
Age pyramid - Biome
C
Parthenium hysterophorus - Threat to biodiversity
D
Stratification - Population

Solution

(C) : $Parthenium$ $hysterophorus$ is commonly known as congress grass or carrot weed. It is an herbaceous annual plant of the family $Asteraceae$.
It is a deadly invasive,noxious weed infesting both cropped and non-cropped areas.
It rapidly colonizes areas,replacing native vegetation,and causes a number of human health-related problems such as skin allergy,rhinitis,and eye irritation.
Also,being toxic and unpalatable,it causes fodder scarcity.
Hence,it is considered a significant threat to biodiversity.
122
BiologyMediumMCQNEET · 2016
The Red List contains data or information on:
A
all economically important plants
B
plants whose products are in international trade
C
threatened species
D
marine vertebrates only

Solution

(C) The correct answer is $C$. The Red Data Book or Red List is a comprehensive catalogue of taxa (species,subspecies,etc.) that are facing a risk of extinction. It provides information on the conservation status of these threatened species to help in their protection and management. The Red Data Book was first initiated in $1963$ by the International Union for Conservation of Nature $(IUCN)$.
123
BiologyEasyMCQNEET · 2016
Which of the following national parks is home to the famous musk deer or hangul?
A
Keibul Lamjao National Park,Manipur
B
Bandhavgarh National Park,Madhya Pradesh
C
Eaglenest Wildlife Sanctuary,Arunachal Pradesh
D
Dachigam National Park,Jammu and Kashmir

Solution

(D) The correct answer is $D$. Dachigam National Park,located in Jammu and Kashmir,is famous for being the natural habitat of the Hangul,also known as the Kashmir stag. The Hangul is a subspecies of the Central Asian red deer and is critically endangered. While musk deer are also found in high-altitude regions of the Himalayas,the Hangul is specifically associated with the Dachigam National Park.
124
BiologyMediumMCQNEET · 2016
Which is the national aquatic animal of India?
A
Blue whale
B
Sea horse
C
Gangetic shark
D
River dolphin

Solution

(D) : The River dolphin (Platanista gangetica) found in the holy rivers Ganga,Brahmaputra,Indus,and their tributaries is the National aquatic animal of India.
The presence of the River dolphin in the Ganga indicates the purity and health of the freshwater ecosystem.
125
BiologyMediumMCQNEET · 2016
Which of the following is the most important cause of animals and plants being driven to extinction?
A
Habitat loss and fragmentation
B
Co-extinctions
C
Over-exploitation
D
Alien species invasion

Solution

(A) The correct answer is $(A)$.
Habitat loss and fragmentation is the most important cause driving animals and plants to extinction.
Destruction of natural habitats poses the most serious threat to biodiversity.
Overpopulation,urbanization,and industrialization lead to the destruction or fragmentation of natural habitats to fulfill the requirement for additional land.
Loss of habitat results in the annihilation of plants and microorganisms,and forces animals out of their natural homes,where they often die in alien environments.
Fragmentation of habitats disrupts complex interactions among species,destroys species in the cleared regions,eliminates species restricted to deeper undisturbed parts of forests,and decreases overall biodiversity in the habitat fragments.
126
BiologyMediumMCQNEET · 2016
Biochemical Oxygen Demand $(BOD)$ may not be a good index for pollution for water bodies receiving effluents from
A
domestic sewage
B
dairy industry
C
petroleum industry
D
sugar industry

Solution

(C) $(BOD)$ is a measure of the amount of dissolved oxygen required by aerobic microorganisms to break down the organic matter present in a given volume of water.
It is an effective indicator for biodegradable organic pollutants.
Domestic sewage,dairy industry effluents,and sugar industry effluents contain high amounts of biodegradable organic matter.
However,effluents from the petroleum industry contain non-biodegradable hydrocarbons and toxic chemicals that cannot be easily broken down by aerobic decomposers.
Therefore,$(BOD)$ is not a reliable index for measuring pollution in water bodies receiving effluents from the petroleum industry.
127
BiologyMediumMCQNEET · 2016
$A$ lake which is rich in organic waste may result in
A
increased population of aquatic organisms due to minerals
B
drying of the lake due to algal bloom
C
increased population of fish due to lots of nutrients
D
mortality of fish due to lack of oxygen

Solution

(D) : High amount of organic waste in a lake will trigger and activate decomposer microbes,which will decompose the organic waste.
Biochemical Oxygen Demand $(BOD)$ of this lake will shoot up,and decomposers will utilize most of the dissolved oxygen present in the lake.
Consequently,the level of dissolved oxygen will decrease to an alarming extent.
Aquatic animals like fish,which totally depend on the oxygen dissolved in water,will ultimately die due to suffocation.
128
BiologyMediumMCQNEET · 2016
The highest $DDT$ concentration in an aquatic food chain shall occur in:
A
phytoplankton
B
seagull
C
crab
D
eel

Solution

(B) $DDT$ is non-biodegradable and is not metabolized within the body of an organism. Instead,it accumulates in the fat tissues.
Therefore,its concentration increases from one trophic level to another in a food chain,with the highest amount being present in the top consumer,a process known as biomagnification.
In an aquatic food chain,the seagull is the top carnivore and therefore will possess the highest concentration of $DDT$.
129
BiologyEasyMCQNEET · 2016
Depletion of which gas in the atmosphere can lead to an increased incidence of skin cancers?
A
Ammonia
B
Methane
C
Nitrous oxide
D
Ozone

Solution

(D) The correct answer is $D$.
Ozone $(O_3)$ layer is present in the stratosphere and acts as a protective shield against harmful $UV$ radiations coming from the sun.
$UV$ radiations are highly energetic and can cause mutations in the $DNA$ of living organisms.
Depletion or thinning of the ozone layer allows a higher intensity of $UV$ radiations to reach the Earth's surface.
Increased exposure to these radiations leads to various health issues,including an increased incidence of skin cancers,cataracts,impaired vision,sunburns,and a weakened immune system.
130
BiologyEasyMCQNEET · 2016
Joint Forest Management concept was introduced in India during: (in $s$)
A
$1980$
B
$1990$
C
$1960$
D
$1970$

Solution

(A) The Joint Forest Management $(JFM)$ concept was introduced in India in the $1980s$.
Under this initiative,the government works in collaboration with local village and tribal communities to protect and manage degraded forest lands.
This approach ensures that local communities receive benefits from the forest resources in exchange for their active participation in conservation and sustainable management efforts.
131
BiologyMediumMCQNEET · 2016
$A$ river with an inflow of domestic sewage rich in organic waste may result in
A
an increased production of fish due to biodegradable nutrients
B
death of fish due to lack of oxygen
C
drying of the river very soon due to algal bloom
D
increased population of aquatic food web organisms.

Solution

(B) : High amount of organic waste in a river will trigger and activate decomposer microbes which will decompose the organic waste.
Biochemical Oxygen Demand $(BOD)$ of this river will shoot up,and decomposers will utilize most of the dissolved oxygen present in the water.
Consequently,the level of dissolved oxygen will decrease to an alarming extent.
Aquatic animals like fish,which depend on the oxygen dissolved in water,will ultimately die due to suffocation.
132
BiologyMediumMCQNEET · 2016
Which of the following is found as a pioneer organism on bare rocks?
A
Liverworts
B
Mosses
C
Green algae
D
Lichens

Solution

(D) Lichens are considered pioneer organisms in primary succession on bare rocks. They secrete acids that help in the weathering of rocks,which leads to the formation of soil. This process creates a suitable environment for the growth of other organisms like mosses and eventually higher plants.
133
BiologyMediumMCQNEET · 2016
What is the mechanism of moving a segment from one linkage group to another called?
A
Translocation
B
Duplication
C
Inversion
D
Crossing over

Solution

(A) Translocation is a type of chromosomal mutation in which a segment of a chromosome breaks off and attaches to another non-homologous chromosome. This results in the movement of a genetic segment from one linkage group to another. Therefore,the correct answer is translocation.
134
BiologyMediumMCQNEET · 2016
Which of the following is $NOT$ required for the current $DNA$ fingerprinting technique?
A
Zinc finger analysis
B
Restriction enzymes
C
$DNA-DNA$ hybridization
D
Polymerase chain reaction

Solution

(A) $DNA$ fingerprinting involves identifying differences in specific regions of $DNA$ sequence called repetitive $DNA$. The steps involved are:
$1$. Isolation of $DNA$.
$2$. Digestion of $DNA$ by restriction endonucleases.
$3$. Separation of $DNA$ fragments by electrophoresis.
$4$. Transferring (blotting) of separated $DNA$ fragments to synthetic membranes,such as nitrocellulose or nylon.
$5$. Hybridization using labelled $VNTR$ probe.
$6$. Detection of hybridized $DNA$ fragments by autoradiography.
Polymerase chain reaction $(PCR)$ is often used to amplify the $DNA$ sample if the amount of $DNA$ is very small.
Zinc finger analysis is a technique used for studying $DNA$-binding proteins and is not a part of the standard $DNA$ fingerprinting procedure.
135
BiologyMediumMCQNEET · 2016
Biochemical Oxygen Demand $(BOD)$ is not a good index for pollution in water bodies receiving effluents from which of the following?
A
Petroleum industries
B
Sugar industry
C
Domestic sewage
D
Dairy industry

Solution

(A) $BOD$ measures the amount of dissolved oxygen required by aerobic microorganisms to decompose the organic matter present in a water sample. It is an effective indicator for organic pollutants,such as those found in domestic sewage,sugar industry waste,and dairy industry waste,which are rich in biodegradable organic matter. However,petroleum industries release non-biodegradable or toxic chemical pollutants that cannot be easily broken down by microorganisms. Therefore,$BOD$ is not a suitable index for measuring pollution caused by petroleum industry effluents.
136
BiologyMediumMCQNEET · 2016
Which of the following is incorrectly matched regarding the microbe,its derivative,and its application?
A
Monascus purpureus - Statins - Lowers blood cholesterol levels.
B
Streptococcus - Streptokinase - Removes clots from blood vessels.
C
Clostridium butylicum - Lipase - Used to remove oily stains in laundry.
D
Trichoderma polysporum - Cyclosporin-$A$ - Immunosuppressive agent in organ transplant patients.

Solution

(C) The correct answer is $C$.
$1$. $Monascus$ $purpureus$ produces statins,which act as blood-cholesterol-lowering agents.
$2$. $Streptococcus$ produces streptokinase,which is used as a 'clot buster' for removing clots from the blood vessels of patients who have undergone myocardial infarction.
$3$. $Clostridium$ $butylicum$ is a bacterium that produces butyric acid. Lipase is produced by the fungus $Candida$ $lipolytica$ or $Rhizopus$ $arrhizus$,not $Clostridium$ $butylicum$. Lipases are used in detergent formulations and are helpful in removing oily stains from the laundry.
$4$. $Trichoderma$ $polysporum$ is a fungus that produces cyclosporin-$A$,which is used as an immunosuppressive agent in organ transplant patients.
137
BiologyMediumMCQNEET · 2016
Why are stirred-tank bioreactors specifically designed?
A
To ensure the availability of oxygen throughout the process.
B
To maintain anaerobic conditions in the culture vessel.
C
To maintain the purity of the product.
D
To add preservatives to the product.

Solution

(A) Stirred-tank bioreactors are cylindrical vessels designed to facilitate the mixing of the reactor contents.
They are equipped with an agitator system,an oxygen delivery system,a foam control system,a temperature control system,a pH control system,and sampling ports.
The primary purpose of the stirring mechanism is to ensure even mixing and,crucially,to provide optimal oxygen availability throughout the entire culture medium for the aerobic growth of microorganisms.
138
BiologyMediumMCQNEET · 2016
When foreign $DNA$ and a plasmid are cut by the same restriction endonuclease,which enzyme is used to join them to form a recombinant plasmid?
A
$DNA$ polymerase-$III$
B
$DNA$ ligase
C
Eco $RI$
D
Taq polymerase

Solution

(B) $1$. When a foreign $DNA$ fragment and a plasmid vector are cut with the same restriction endonuclease,they produce complementary sticky ends.
$2$. These complementary sticky ends allow the foreign $DNA$ to base-pair with the plasmid vector.
$3$. However,the sugar-phosphate backbone of the $DNA$ remains broken at the nicks.
$4$. The enzyme $DNA$ ligase is responsible for catalyzing the formation of phosphodiester bonds between the adjacent nucleotides,thereby sealing the nicks and creating a stable recombinant $DNA$ molecule.
139
BiologyMediumMCQNEET · 2016
Which of the following processes is $NOT$ a part of the downstream processing?
A
Preservation
B
Expression
C
Separation
D
Purification

Solution

(B) Downstream processing refers to the stages of processing that occur after the biosynthesis of the product in a bioreactor.
It includes the following steps:
$1$. Separation of the product from the culture medium.
$2$. Purification of the product.
$3$. Formulation with suitable preservatives.
$4$. Quality control and clinical trials.
'Expression' is a part of the upstream processing,where the gene of interest is expressed in the host organism to produce the desired product. Therefore,it is not a part of downstream processing.
140
BiologyMediumMCQNEET · 2016
Which of the following restriction enzymes produces blunt ends?
A
$Xho-I$
B
$Hind-III$
C
$Sal-I$
D
$Eco-RV$

Solution

(D) Restriction enzymes are classified based on the type of ends they produce after $DNA$ cleavage.
$1$. Sticky ends (cohesive ends) are produced by enzymes like $Eco-RI$,$Hind-III$,$Xho-I$,and $Sal-I$,which create staggered cuts.
$2$. Blunt ends (flush ends) are produced by enzymes that cut both strands of $DNA$ at the same position,typically in the center of the recognition site.
$3$. $Eco-RV$ is a well-known restriction enzyme that recognizes the sequence $5'-GATATC-3'$ and cuts between the $T$ and $A$ residues,resulting in blunt ends.
Therefore,the correct option is $D$.
141
BiologyMediumMCQNEET · 2016
Which of the following is known as a restriction endonuclease?
A
Protease
B
DNase-$I$
C
RNase
D
Hind-$II$

Solution

(D) Restriction endonucleases are enzymes that cut $DNA$ at specific recognition sequences.
$Hind-II$ was the first restriction endonuclease to be isolated and characterized.
Proteases are enzymes that break down proteins.
DNase-$I$ and RNase are enzymes that degrade $DNA$ and $RNA$,respectively,but they are not restriction endonucleases.
142
BiologyMediumMCQNEET · 2016
Which of the following is $NOT$ a characteristic of a plasmid?
A
Circular structure
B
Transferable
C
Single-stranded
D
Autonomous replication

Solution

(C) Plasmids are small,circular,double-stranded $DNA$ molecules that are distinct from a cell's chromosomal $DNA$.
They are found primarily in bacteria and can replicate independently of the chromosomal $DNA$.
They are often used as vectors in genetic engineering because they can be transferred between cells.
Since plasmids are double-stranded,the statement that they are 'single-stranded' is incorrect.
143
BiologyMediumMCQNEET · 2016
From which organism is the $Taq$ polymerase enzyme isolated?
A
$Thiobacillus$ $ferrooxidans$
B
$Bacillus$ $subtilis$
C
$Pseudomonas$ $putida$
D
$Thermus$ $aquaticus$

Solution

(D) The $Taq$ polymerase enzyme is isolated from a thermophilic bacterium called $Thermus$ $aquaticus$.
This bacterium thrives in high-temperature environments such as hot springs.
Because of its origin,the $Taq$ polymerase enzyme is thermostable,meaning it can withstand the high temperatures required during the denaturation step of the Polymerase Chain Reaction $(PCR)$ process.
Therefore,it is widely used in $PCR$ to amplify $DNA$ segments.
144
BiologyMediumMCQNEET · 2016
What is the consequence of discharging organic-rich domestic sewage into a river?
A
The population of aquatic food organisms increases.
B
The number of fish increases due to biodegradable nutrients.
C
Fish die due to the lack of oxygen.
D
The river dries up quickly due to the abundance of fish.

Solution

(C) When organic-rich domestic sewage is discharged into a river,it acts as a nutrient source for microorganisms like bacteria.
These microorganisms decompose the organic matter,a process that consumes a large amount of dissolved oxygen $(DO)$ from the water.
This leads to a sharp decline in the $BOD$ (Biochemical Oxygen Demand) levels and a significant reduction in dissolved oxygen.
As a result,aquatic organisms,especially fish,die due to the lack of oxygen (hypoxia).
145
BiologyEasyMCQNEET · 2016
In which year was the Joint Forest Management $(JFM)$ scheme introduced in India?
A
$1970$
B
$1980$
C
$1990$
D
$1960$

Solution

(B) The Government of India introduced the concept of Joint Forest Management $(JFM)$ in the year $1980$.
This initiative was launched to involve local communities in the management and restoration of degraded forests.
Under this scheme,local communities are entitled to intermediary benefits like non-timber forest products and a share in the timber harvested by successful protection and management.

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