MathematicsQ51–51 of 85 questions
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51
MathematicsEasyMCQAP EAMCET · 2010
ધારો કે $A$ અને $B$ બે એવી ઘટનાઓ છે કે જેથી $P(A \cap B) = \frac{3}{25}$ અને $P(B - A) = \frac{8}{25}$ થાય. તો,$P(B)$ ની કિંમત શોધો.
A
$\frac{11}{25}$
B
$\frac{3}{11}$
C
$\frac{1}{11}$
D
$\frac{9}{11}$
Solution
(A) આપેલ છે કે $P(A \cap B) = \frac{3}{25}$ અને $P(B - A) = \frac{8}{25}$.
ગણ અને સંભાવનાના ગુણધર્મો મુજબ,ઘટના $B$ ને બે અલગ-અલગ ગણના યોગ તરીકે દર્શાવી શકાય છે: $(B - A)$ અને $(A \cap B)$.
તેથી,$P(B) = P(B - A) + P(A \cap B)$.
આપેલ કિંમતો મૂકતા:
$P(B) = \frac{8}{25} + \frac{3}{25} = \frac{11}{25}$.
ગણ અને સંભાવનાના ગુણધર્મો મુજબ,ઘટના $B$ ને બે અલગ-અલગ ગણના યોગ તરીકે દર્શાવી શકાય છે: $(B - A)$ અને $(A \cap B)$.
તેથી,$P(B) = P(B - A) + P(A \cap B)$.
આપેલ કિંમતો મૂકતા:
$P(B) = \frac{8}{25} + \frac{3}{25} = \frac{11}{25}$.
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