ChemistryQ1–3 of 3 questions
Page 1 of 1 · English
1
ChemistryMediumMCQAIIMS · 1985
The bond order is maximum in
A
$O_2$
B
$O_2^{-}$
C
$O_2^{+}$
D
$O_2^{2-}$
Solution
(C) The bond order $(B.O.)$ is calculated using the formula: $B.O. = \frac{1}{2} (N_b - N_a)$.
For $O_2$ ($16$ electrons): $B.O. = \frac{1}{2} (10 - 6) = 2.0$.
For $O_2^{-}$ ($17$ electrons): $B.O. = \frac{1}{2} (10 - 7) = 1.5$.
For $O_2^{+}$ ($15$ electrons): $B.O. = \frac{1}{2} (10 - 5) = 2.5$.
For $O_2^{2-}$ ($18$ electrons): $B.O. = \frac{1}{2} (10 - 8) = 1.0$.
Comparing these values,the bond order is maximum in $O_2^{+}$.
For $O_2$ ($16$ electrons): $B.O. = \frac{1}{2} (10 - 6) = 2.0$.
For $O_2^{-}$ ($17$ electrons): $B.O. = \frac{1}{2} (10 - 7) = 1.5$.
For $O_2^{+}$ ($15$ electrons): $B.O. = \frac{1}{2} (10 - 5) = 2.5$.
For $O_2^{2-}$ ($18$ electrons): $B.O. = \frac{1}{2} (10 - 8) = 1.0$.
Comparing these values,the bond order is maximum in $O_2^{+}$.
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2
ChemistryEasyMCQAIIMS · 1985
Which of the following is the most stable cation?
A
$CH_3CH_2CH^{+}CH_3$
B
$(CH_3)_3C^{+}$
C
$CH_3CH_2CH_2CH_2^+$
D
$CH_3^+$
Solution
(B) The stability of carbocations follows the order: $3^{\circ} > 2^{\circ} > 1^{\circ} > \text{methyl}$.
$(CH_3)_3C^{+}$ is a $3^{\circ}$ carbocation,which is stabilized by the inductive effect of three methyl groups and hyperconjugation.
Therefore,$(CH_3)_3C^{+}$ is the most stable cation among the given options.
$(CH_3)_3C^{+}$ is a $3^{\circ}$ carbocation,which is stabilized by the inductive effect of three methyl groups and hyperconjugation.
Therefore,$(CH_3)_3C^{+}$ is the most stable cation among the given options.
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3
ChemistryMCQAIIMS · 1985
When a cell is fully turgid,which of the following will be zero?
A
Osmotic pressure
B
Turgor pressure
C
Wall pressure
D
Suction pressure
Solution
(D) The relationship between $DPD$ (Diffusion Pressure Deficit),$OP$ (Osmotic Pressure),and $TP$ (Turgor Pressure) is given by the equation: $DPD = OP - TP$.
When a cell is fully turgid,the $TP$ becomes equal to the $OP$.
Therefore,$DPD = OP - OP = 0$.
$DPD$ is also known as Suction Pressure $(SP)$.
Thus,when a cell is fully turgid,the Suction Pressure is zero.
When a cell is fully turgid,the $TP$ becomes equal to the $OP$.
Therefore,$DPD = OP - OP = 0$.
$DPD$ is also known as Suction Pressure $(SP)$.
Thus,when a cell is fully turgid,the Suction Pressure is zero.
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