PhysicsQ1–1 of 1 questions
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1
PhysicsEasyMCQAIIMS · 1984
એક કેપેસિટરની કેપેસિટન્સ $4 \times 10^{-6} \, F$ છે અને તેનો પોટેન્શિયલ $100 \, V$ છે. તેને સંપૂર્ણપણે ડિસ્ચાર્જ કરવા પર મુક્ત થતી ઉર્જા ....... $J$ હશે.
A
$0.02$
B
$0.04$
C
$0.025$
D
$0.05$
Solution
(A) કેપેસિટરમાં સંગ્રહિત ઉર્જાનું સૂત્ર $U = \frac{1}{2} C V^2$ છે.
આપેલ છે:
કેપેસિટન્સ $C = 4 \times 10^{-6} \, F$
પોટેન્શિયલ $V = 100 \, V$
સૂત્રમાં કિંમતો મૂકતા:
$U = \frac{1}{2} \times (4 \times 10^{-6}) \times (100)^2$
$U = \frac{1}{2} \times 4 \times 10^{-6} \times 10000$
$U = 2 \times 10^{-6} \times 10^4$
$U = 2 \times 10^{-2} \, J$
$U = 0.02 \, J$
તેથી,મુક્ત થતી ઉર્જા $0.02 \, J$ છે.
આપેલ છે:
કેપેસિટન્સ $C = 4 \times 10^{-6} \, F$
પોટેન્શિયલ $V = 100 \, V$
સૂત્રમાં કિંમતો મૂકતા:
$U = \frac{1}{2} \times (4 \times 10^{-6}) \times (100)^2$
$U = \frac{1}{2} \times 4 \times 10^{-6} \times 10000$
$U = 2 \times 10^{-6} \times 10^4$
$U = 2 \times 10^{-2} \, J$
$U = 0.02 \, J$
તેથી,મુક્ત થતી ઉર્જા $0.02 \, J$ છે.
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