Introduction of Halogen containing compounds Questions in English

(A) vinylic halide is a compound in which the halogen atom is bonded to a carbon atom that is part of a carbon-carbon double bond $(C=C)$.
In the option $CH_2=CH-Cl$,the chlorine atom is directly attached to a carbon atom involved in a double bond,which defines it as a vinylic halide.
Therefore,the correct option is $A$.

(A) benzylic halide is a compound in which the halogen atom is bonded to an $sp^3$ hybridized carbon atom,which is directly attached to an aromatic ring.
In the structure $C_6H_5-CH_2-X$,the halogen atom $X$ is attached to a carbon atom that is bonded to a benzene ring $(C_6H_5)$.
This carbon atom is $sp^3$ hybridized,making it a benzylic halide.
Therefore,the correct option is $A$.

(D) haloarene is a compound in which a halogen atom is directly attached to an aromatic ring (benzene ring).
In option $D$,the halogen atom $X$ is directly bonded to the carbon atom of the benzene ring,which makes it an aryl halide or haloarene.
In option $A$,the halogen is attached to a side chain carbon,making it a benzyl halide.
In options $B$ and $C$,the compounds are aliphatic cyclic halides,not aromatic.

(B) benzylic halide is a compound in which the halogen atom is bonded to an $sp^3$ hybridized carbon atom,which is further attached to an aromatic ring.
In $Bromophenylmethane$ (also known as benzyl bromide),the bromine atom is attached to a $-CH_2-$ group,which is directly bonded to a benzene ring.
This structure fits the definition of a benzylic halide.
Therefore,the correct option is $B$.

(C) The given compound is $CH_3-CH=CH-C(Cl)(CH_3)_2$.
In this structure,the $-Cl$ atom is attached to a carbon atom that is directly bonded to a carbon-carbon double bond $(C=C)$.
Specifically,the carbon atom bearing the $-Cl$ is adjacent to the $sp^2$ hybridized carbon of the double bond.
Such a halide,where the halogen is attached to an $sp^3$ hybridized carbon atom next to a carbon-carbon double bond,is classified as an allylic halide.

(C) In $1, 2-$dichloroethane $(Cl-CH_2-CH_2-Cl)$,the two chlorine atoms are attached to adjacent carbon atoms.
Compounds in which two halogen atoms are attached to adjacent carbon atoms are known as vicinal dihalides or vicinal halides.
Therefore,the correct option is $C$.

(B) An allylic halide is a compound in which the halogen atom is bonded to an $sp^3$ hybridized carbon atom next to a carbon-carbon double bond $(C=C)$.
$A$: $3-$chlorocyclohexa$-1-$ene has the chlorine on a carbon adjacent to the double bond (Allylic).
$B$: $1-$chlorobut$-1-$ene has the chlorine directly attached to one of the carbons of the double bond ($sp^2$ hybridized),which is a vinylic halide,not allylic.
$C$: $1-$chlorobut$-2-$ene is not allylic; however,the question asks for the non-allylic structure. Checking $1-$chlorobut$-2-$ene $(CH_3-CH=CH-CH_2Cl)$,the $Cl$ is on an $sp^3$ carbon,but it is not adjacent to the double bond in the standard allylic sense $(C=C-C-X)$. Wait,$1-$chlorobut$-2-$ene is actually a primary alkyl halide,not allylic.
$D$: $3-$chloroprop$-1-$ene $(CH_2=CH-CH_2Cl)$ is the classic allylic halide.
Comparing the options,$1-$chlorobut$-1-$ene is a vinylic halide,and $1-$chlorobut$-2-$ene is a primary alkyl halide. Given the standard classification,$1-$chlorobut$-1-$ene is the most distinct non-allylic example provided.

(D) An allylic halide is a compound in which the halogen atom is bonded to an $sp^3$ hybridized carbon atom adjacent to a carbon-carbon double bond $(C=C)$.
$A$. Benzyl chloride $(C_6H_5CH_2Cl)$ is a benzylic halide.
$B$. $1-$Bromoethylbenzene $(C_6H_5CH(Br)CH_3)$ is a benzylic halide.
$C$. Bromobenzene $(C_6H_5Br)$ is an aryl halide.
$D$. $3-$Chlorocyclohex$-1-$ene has the chlorine atom attached to a carbon atom that is adjacent to the $C=C$ double bond,making it an allylic halide.

(A) An allylic halide is a compound in which the halogen atom is bonded to an $sp^3$ hybridized carbon atom next to a carbon-carbon double bond $(C=C)$.
In $2-$bromocyclohexene,the bromine atom is directly attached to one of the carbon atoms of the double bond,which is $sp^2$ hybridized. This makes it a vinylic halide,not an allylic halide.
In $3-$chloroprop$-1-$ene,$3-$chlorocyclohexene,and $1-$chlorobut$-2-$ene,the halogen is attached to an $sp^3$ carbon adjacent to the double bond,satisfying the definition of an allylic halide.
Therefore,the correct answer is $A$.

(D) The structure of tertiary butyl iodide is $(CH_3)_3CI$.
To name it according to $IUPAC$ rules:
$1$. Identify the longest carbon chain containing the functional group. The longest chain has $3$ carbon atoms (propane).
$2$. Number the chain such that the substituent gets the lowest possible number. The iodine atom is at position $2$,and a methyl group is also at position $2$.
$3$. The $IUPAC$ name is $2-$iodo$-2-$methyl propane.

(B) The given structure is $C_6H_5-C(CH_3)_2-Cl$.
In this compound,the halogen atom $(Cl)$ is attached to a carbon atom which is directly bonded to an aromatic ring (benzene ring).
Such compounds,where the halogen is attached to an $sp^3$ hybridized carbon atom next to an aromatic ring,are classified as $Benzylic$ halides.

(C) Tincture of iodine is a common antiseptic solution.
It typically consists of $2-3 \%$ elemental iodine,along with potassium iodide or sodium iodide,dissolved in a mixture of ethanol and water.
The presence of alcohol is a defining characteristic of tincture solutions.

(A) The classification of organic halides is based on the position of the halogen atom relative to the carbon skeleton:
$A$. Vinyl halides: The halogen is attached directly to a carbon atom of a double bond. In $3-$bromo$-4-$methylcyclohexene,the bromine is attached to a carbon involved in a double bond,making it a vinyl halide $(A-III)$.
$B$. Allyl halides: The halogen is attached to an $sp^3$ hybridized carbon atom next to a carbon-carbon double bond. In $1-$bromo$-3-$methylcyclohexene,the bromine is attached to a carbon adjacent to the double bond $(B-IV)$.
$C$. Benzyl halides: The halogen is attached to a carbon atom which is directly attached to an aromatic ring. In $1-$bromo$-1-$phenylethane,the bromine is attached to the benzylic carbon $(C-I)$.
$D$. Aryl halides: The halogen is attached directly to an aromatic ring. In $3-$bromotoluene,the bromine is attached directly to the benzene ring $(D-II)$.
Thus,the correct matching is $A-III, B-IV, C-I, D-II$.

(D) In chlorocyclohexane,the chlorine atom is attached to a carbon atom that is further bonded to two other carbon atoms within the cyclohexane ring.
Since the carbon atom bearing the halogen is bonded to two other carbon atoms,it is a $secondary$ $(2^{\circ})$ carbon.
Therefore,chlorocyclohexane is classified as a $secondary$ alkyl halide.

(A) An allylic halide is a compound in which the halogen atom is bonded to an $sp^3$ hybridized carbon atom that is adjacent to a carbon-carbon double bond $(C=C)$.
Let us analyze the structures:
$A$. $4-$chlorobut$-1-$ene $(CH_2=CH-CH_2-CH_2-Cl)$: The $Cl$ atom is attached to a carbon atom that is not adjacent to the double bond. This is a primary alkyl halide,not an allylic halide.
$B$. $1-$chlorobut$-2-$ene $(CH_3-CH=CH-CH_2-Cl)$: The $Cl$ atom is attached to a carbon atom adjacent to the double bond. This is an allylic halide.
$C$. $3-$chloro$-2-$methylbut$-1-$ene $(CH_2=C(CH_3)-CHCl-CH_3)$: The $Cl$ atom is attached to a carbon atom adjacent to the double bond. This is an allylic halide.
$D$. $4-$chloropent$-2-$ene $(CH_3-CH=CH-CH_2-CH_2-Cl)$: The $Cl$ atom is attached to a carbon atom that is not adjacent to the double bond. This is not an allylic halide.
Note: Both $A$ and $D$ are not allylic halides. However,$4-$chlorobut$-1-$ene is the most common example provided in textbooks to illustrate a non-allylic halide.

(A) primary $(1^{\circ})$ halide is one in which the halogen atom is attached to a primary carbon atom (a carbon atom bonded to only one other carbon atom).
Let us analyze the structures:
$A$. $1-$bromo-but$-2-$ene: $CH_2(Br)-CH=CH-CH_3$. The $Br$ is attached to a $CH_2$ group,which is bonded to only one carbon atom. Thus,it is a primary halide.
$B$. $4-$bromo-pent$-2-$ene: $CH_3-CH=CH-CH_2-CH_2(Br)$. This is also a primary halide,but $1-$bromo-but$-2-$ene is the most standard example of an allylic primary halide.
$C$. $2-$bromo$-2-$methylpropane: $(CH_3)_3C-Br$. The $Br$ is attached to a tertiary carbon.
$D$. $t-$butyl bromide: $(CH_3)_3C-Br$. This is the same as $C$,a tertiary halide.
Therefore,$1-$bromo-but$-2-$ene is a primary halide.

(A) gem-dihalide is a compound that has two halogen atoms on the same carbon atom.
Ethylidene chloride $(CH_3CHCl_2)$ is a gem-dihalide because both chlorine atoms are attached to the same carbon atom.
Ethylene dichloride $(ClCH_2CH_2Cl)$ is a vic-dihalide.
Hence,the correct option is $(A)$.

(A) geminal dihalide is a compound in which two halogen atoms are attached to the same carbon atom.
In $1,1-$Dichloropropane,both chlorine atoms are attached to the first carbon atom $(CH_3CH_2CHCl_2)$.
Therefore,it is a geminal dichloride.

(C) Vinyl halides are compounds in which the halogen atom is bonded to an $sp^2$ hybridized carbon atom of a carbon-carbon double bond $(C=C)$.
In the given list:
$(b)$ $1\text{-chlorocyclohexene}$ and $(d)$ $1\text{-chloroethene}$ $(CH_2=CHCl)$ have the chlorine atom directly attached to the double-bonded carbon.
Therefore,they are vinyl chlorides.

(D) Benzene is a non-polar solvent,while water is a polar solvent.
Compounds that are non-polar or have low polarity tend to dissolve in benzene.
$C_2H_5OH$ (ethanol),$CH_3CO_2H$ (acetic acid),and $CH_3CHO$ (acetaldehyde) are polar and can form hydrogen bonds with water,making them soluble in water.
$C_6H_5NO_2$ (nitrobenzene) is a non-polar organic compound,which makes it insoluble in water but soluble in non-polar solvents like benzene.

(B) An allylic halide is a compound in which the halogen atom is bonded to an $sp^3$ hybridized carbon atom that is adjacent to a carbon-carbon double bond $(C=C)$.
In option $B$,the chlorine atom is attached to a carbon atom that is directly adjacent to the $C=C$ double bond. This carbon is $sp^3$ hybridized,making it an allylic halide.
In option $A$,the chlorine is attached directly to the double-bonded carbon,which is a vinylic halide.
Therefore,the correct option is $B$.

(A) The chemical formula of chloroethane is $CH_3CH_2Cl$.
In this molecule,the carbon atom attached to the chlorine atom (halogen) is bonded to two hydrogen atoms.
Since this carbon atom is attached to only one other carbon atom,it is a primary $(1^{\circ})$ carbon.
Therefore,chloroethane is a primary alkyl halide.
Thus,the correct answer is: Two,primary.

(C) . Vinyl chloride is $CH_2=CHCl$ $(III)$.
$B$. Benzyl chloride is $C_6H_5CH_2Cl$ $(IV)$.
$C$. Alkyl chloride is $CH_3-CH(Cl)CH_3$ $(II)$.
$D$. Allyl chloride is $CH_2=CH-CH_2Cl$ $(I)$.
Therefore,the correct matching is $A-III, B-IV, C-II, D-I$.

(D) An allylic halide is a compound in which the halogen atom is bonded to a carbon atom that is $sp^3$ hybridized and adjacent to a carbon-carbon double bond.
In $1$-Bromo-$2$-methylbut-$2$-ene,the bromine is on a carbon adjacent to the double bond ($sp^3$ hybridized),so it is allylic.
In $1$-Bromobut-$2$-ene,the bromine is on a carbon adjacent to the double bond ($sp^3$ hybridized),so it is allylic.
In $3$-Bromo-$2$-methylbut-$1$-ene,the bromine is on a carbon adjacent to the double bond ($sp^3$ hybridized),so it is allylic.
In $2$-Bromo-$2$-methylbut-$2$-ene,the bromine atom is directly bonded to a carbon atom that is part of the double bond ($sp^2$ hybridized),which classifies it as a vinylic halide,not an allylic halide.

(C) An allylic chloride is a compound in which the chlorine atom is attached to an $\text{sp}^3$ hybridized carbon atom that is adjacent to a carbon-carbon double bond (i.e.,an allylic carbon).
$1$. In $CH_2=CH-CH_2-Cl$,the chlorine is attached to an $\text{sp}^3$ carbon adjacent to a double bond,so it is an allylic chloride.
$2$. In $CH_3-CH=CH-CH_2-Cl$,the chlorine is attached to an $\text{sp}^3$ carbon adjacent to a double bond,so it is an allylic chloride.
$3$. In chlorobenzene,the chlorine atom is attached directly to an $\text{sp}^2$ hybridized carbon atom of the benzene ring. This is an aryl chloride,not an allylic chloride.
$4$. In vinyl chloride $(CH_2=CH-Cl)$,the chlorine is attached directly to an $\text{sp}^2$ hybridized carbon atom of the double bond. This is a vinylic chloride,not an allylic chloride.
Since both chlorobenzene and vinyl chloride are not allylic chlorides,and typically in such multiple-choice questions,the most distinct non-allylic example is sought,chlorobenzene is a classic example of an aryl halide.