Transcription Questions in English

(C) The correct answer is $C$. Messenger $RNA$ $(mRNA)$ is synthesized within the nucleus of a eukaryotic cell through a process called transcription. While the nucleolus is primarily responsible for the synthesis and assembly of ribosomal $RNA$ $(rRNA)$,the synthesis of $mRNA$ occurs in the nucleoplasm,which is the region inside the nucleus but outside the nucleolus.

(C) The process of forming $RNA$ from a $DNA$ template is known as transcription. The enzyme responsible for catalyzing the synthesis of $RNA$ using a $DNA$ template is $RNA$ polymerase. Therefore,$RNA$ polymerase is the correct enzyme.

(A) In the process of transcription,the $RNA$ polymerase enzyme requires specific factors for its regulation.
$(1)$ The sigma $(\sigma)$ factor is responsible for the initiation of transcription by recognizing the promoter region on the $DNA$ template.
$(2)$ The rho $(\rho)$ factor is responsible for the termination of transcription,as it helps in releasing the newly synthesized $RNA$ transcript from the $DNA$ template.
Therefore,the sigma factor performs initiation and the rho factor performs termination.

(B) $RNA$ polymerase is the primary enzyme responsible for the process of transcription.
During transcription,this enzyme synthesizes an $RNA$ strand from a $DNA$ template by catalyzing the formation of phosphodiester bonds between ribonucleotides.

(D) The correct answer is $D$. In eukaryotic cells,the process of transcription produces a precursor $RNA$ molecule that is significantly longer than the mature $mRNA$. This precursor is known as heterogeneous nuclear $RNA$ $(hnRNA)$. It is considered the most heterogeneous because it contains both exons (coding sequences) and introns (non-coding sequences) and varies greatly in length and composition before undergoing post-transcriptional processing (splicing,capping,and tailing) to become functional $mRNA$.

(A) In eukaryotes,the process of transcription involves the enzyme $RNA$ polymerase $II$,which transcribes a precursor $RNA$ molecule known as Heterogenous nuclear $RNA$ $(hnRNA)$. This $hnRNA$ undergoes post-transcriptional modifications,such as splicing,capping,and tailing,to become functional $mRNA$ before it is exported from the nucleus to the cytoplasm for translation.

(D) During the process of transcription, the $mRNA$ is synthesized complementary to the template strand of $DNA$.
In $DNA$, $Adenine$ $(A)$ pairs with $Thymine$ $(T)$, and $Cytosine$ $(C)$ pairs with $Guanine$ $(G)$.
However, in $RNA$, $Thymine$ $(T)$ is replaced by $Uracil$ $(U)$.
Given the $DNA$ template sequence $ATTGCC$:
- $A$ pairs with $U$ in $mRNA$
- $T$ pairs with $A$ in $mRNA$
- $T$ pairs with $A$ in $mRNA$
- $G$ pairs with $C$ in $mRNA$
- $C$ pairs with $G$ in $mRNA$
- $C$ pairs with $G$ in $mRNA$
Therefore, the resulting $mRNA$ sequence is $UAACGG$.

(A) The process of transcription involves the synthesis of $RNA$ from a $DNA$ template.
This process is catalyzed by the enzyme $RNA$ polymerase.
In eukaryotes,$RNA$ polymerase $II$ is specifically responsible for the transcription of $mRNA$.
The core enzyme consists of subunits $\alpha, \alpha, \beta, \beta'$ and $\omega$,while the $\sigma$ (sigma) factor is required for the initiation of transcription.

(B) In eukaryotes,there are three main types of $RNA$ polymerases involved in transcription:
$1$. $RNA$ polymerase $I$ transcribes $rRNAs$ ($28S, 18S,$ and $5.8S$).
$2$. $RNA$ polymerase $II$ transcribes the precursor of $mRNA$,which is known as heterogeneous nuclear $RNA$ $(hnRNA)$.
$3$. $RNA$ polymerase $III$ is responsible for the transcription of $tRNA$,$5S$ $rRNA$,and $snRNA$ (small nuclear $RNA$).

(A) During transcription,the $DNA$ template strand is used to synthesize $mRNA$ through complementary base pairing.
In $DNA$,the base Adenine $(A)$ pairs with Thymine $(T)$,and Cytosine $(C)$ pairs with Guanine $(G)$.
However,in $mRNA$,Uracil $(U)$ replaces Thymine $(T)$.
Therefore,the base pairing rules for $mRNA$ synthesis are: $A$ pairs with $U$,$T$ pairs with $A$,$C$ pairs with $G$,and $G$ pairs with $C$.
Given the $DNA$ sequence $ATACG$:
- $A$ pairs with $U$
- $T$ pairs with $A$
- $A$ pairs with $U$
- $C$ pairs with $G$
- $G$ pairs with $C$
Thus,the resulting $mRNA$ sequence is $UAUGC$.

(A) Transcription is the process of synthesizing $RNA$ from a $DNA$ template. During this process,the genetic information stored in $DNA$ is copied into a complementary $m-RNA$ strand.

(D) $m-RNA$ (messenger $RNA$) is a polymer of ribonucleotides that acts as a complementary strand to $DNA$.
It carries the genetic information from the nucleus to the cytoplasm,where it serves as a template for the synthesis of proteins.

(A) Messenger $RNA$ $(mRNA)$ is synthesized inside the nucleus through the process of transcription.
During transcription,the $DNA$ template strand is used to produce a complementary $mRNA$ strand.
After synthesis,the $mRNA$ is processed and exported to the cytoplasm for translation.

(B) Genetic information is stored in the $DNA$ within the nucleus.
During the process of transcription,this information is copied into $mRNA$ $(messenger RNA)$.
$mRNA$ then exits the nucleus through nuclear pores and enters the cytoplasm,where it serves as a template for protein synthesis (translation).
Therefore,$RNA$ is the molecule responsible for transferring genetic information from the nucleus to the cytoplasm.

(D) In eukaryotes,the primary transcript produced by $RNA$ polymerase $II$ is known as heterogeneous nuclear $RNA$ $(hnRNA)$.
$hnRNA$ is a precursor to messenger $RNA$ $(mRNA)$.
It is significantly longer than the mature $mRNA$ because it contains both exons (coding sequences) and introns (non-coding sequences).
Typically,$hnRNA$ molecules are large,often containing $200$ or more nucleotides,and undergo processing such as splicing,capping,and tailing to become functional $mRNA$.

(B) The process of copying genetic information from one strand of the $DNA$ into $RNA$ is termed as transcription. This process occurs in the nucleus where $DNA$ serves as a template for the synthesis of $mRNA$.

(A) Transcription is the process of copying genetic information from one strand of the $DNA$ into $RNA$. The process involves three main stages: initiation,elongation,and termination.
$1$. Template binding: $RNA$ polymerase binds to the promoter region of the $DNA$ template strand to initiate transcription.
$2$. Chain initiation: The enzyme facilitates the start of $RNA$ synthesis.
$3$. Chain elongation: Ribonucleotide triphosphates are added to the growing $RNA$ chain based on the complementary base pairing rules ($A$ with $U$,$T$ with $A$,$G$ with $C$,$C$ with $G$).
$4$. Chain termination: The process stops when the $RNA$ polymerase reaches the terminator sequence.
While all these steps are part of transcription,'Template binding' is the specific initial event that dictates the start of the transcription process on the $DNA$ template.

(C) The $DNA$ double helix consists of two strands. One strand runs in the $3' \rightarrow 5'$ direction and acts as a template for $mRNA$ synthesis; this is called the template strand or antisense strand.
The other strand runs in the $5' \rightarrow 3'$ direction and is called the coding strand or sense strand.
The sense strand has the same nucleotide sequence as the $mRNA$ transcript,except that $Thymine$ $(T)$ is replaced by $Uracil$ $(U)$.

(D) During transcription,the $mRNA$ strand is synthesized complementary to the template strand of $DNA$.
In $DNA$,$Adenine$ $(A)$ pairs with $Thymine$ $(T)$,and $Guanine$ $(G)$ pairs with $Cytosine$ $(C)$.
However,in $mRNA$,$Uracil$ $(U)$ replaces $Thymine$ $(T)$.
Given $mRNA$ sequence: $AUC, GCG, UCA$.
The template $DNA$ strand must have the complementary bases: $A$ pairs with $T$,$U$ pairs with $A$,$C$ pairs with $G$,$G$ pairs with $C$.
Matching the sequence $AUC, GCG, UCA$ to the template $DNA$ strand:
$A \rightarrow T$
$U \rightarrow A$
$C \rightarrow G$
$G \rightarrow C$
$C \rightarrow G$
$G \rightarrow C$
$U \rightarrow A$
$C \rightarrow G$
$A \rightarrow T$
Thus,the template strand sequence is $TAG, CGC, AGT$. Therefore,option $D$ is correct.

(B) Transcription is the process of copying genetic information from one strand of the $DNA$ into $RNA$.
This process is catalyzed by the enzyme $DNA$-dependent $RNA$ polymerase.
It involves the synthesis of an $RNA$ molecule using a $DNA$ strand as a template.
Therefore,option $B$ is the correct answer.

(C) Transcription is the process of copying genetic information from one strand of the $DNA$ into $RNA$.
Specifically,it involves the synthesis of $mRNA$ (messenger $RNA$) from a $DNA$ template.
Therefore,the correct answer is $mRNA$.

(A) The process of synthesizing $mRNA$ from a $DNA$ template is known as transcription.
Following this,the process of synthesizing a polypeptide chain (protein) from the $mRNA$ template on ribosomes is known as translation.

(B) The central dogma of molecular biology,proposed by Francis Crick,describes the unidirectional flow of genetic information.
It states that genetic information flows from $DNA$ to $RNA$ through a process called transcription,and from $RNA$ to protein through a process called translation.
Therefore,the correct sequence is $DNA \xrightarrow{\text{Transcription}} m-RNA \xrightarrow{\text{Translation}} \text{protein}$.

(A) Transcription is the process of synthesizing $RNA$ using a $DNA$ template.
During this process,the genetic information encoded in the $DNA$ is copied into a single-stranded $RNA$ molecule.
The resulting $RNA$ sequence is complementary to the template strand and identical to the coding strand of $DNA$,with the exception that the base $Thymine$ $(T)$ is replaced by $Uracil$ $(U)$.

(B) In eukaryotic genes,the coding sequence is interrupted by non-coding sequences.
$1$. The segments of $DNA$ that are transcribed into $mRNA$ and also translated into proteins are called $Exons$.
$2$. The segments of $DNA$ that are transcribed into $pre-mRNA$ but are removed during the process of $RNA$ splicing (and thus not translated into proteins) are called $Introns$.
$3$. Therefore,the portion that is transcribed but not translated is the $Intron$.

(A) Transcription is the process of copying genetic information from one strand of the $DNA$ into $RNA$.
This process is mediated by the enzyme $RNA$ polymerase.
It is the first step in gene expression where the genetic code is transcribed from $DNA$ to $mRNA$.

(A) Transcription is the process of copying genetic information from one strand of the $DNA$ into $RNA$.
This process is catalyzed by the enzyme $DNA$ dependent $RNA$ polymerase.
It uses a $DNA$ template to synthesize a complementary $RNA$ strand.
Therefore,the correct option is $A$.

(A) The process by which genetic information is copied from one strand of $DNA$ into $RNA$ is known as transcription.
This is the first step in gene expression where the enzyme $RNA$ polymerase synthesizes an $RNA$ molecule complementary to the $DNA$ template.

(C) In split genes,the coding sequences are known as $Exons$.
During the process of post-transcriptional modification,the non-coding sequences,known as $Introns$,are removed through splicing.
The remaining coding sequences,$Exons$,are then joined together to form a functional $mRNA$ molecule.

(C) The process of copying genetic information from one strand of the $DNA$ into $RNA$ is known as $Transcription$.
$Replication$ is the process of duplicating $DNA$.
$Translation$ is the process of synthesizing proteins from $mRNA$.
$Transformation$ refers to the uptake of foreign genetic material by a cell.

(A) During the process of transcription,the $DNA$ template strand is used to synthesize $mRNA$ through complementary base pairing.
In $DNA$,the base $Adenine$ $(A)$ pairs with $Thymine$ $(T)$,$Thymine$ $(T)$ pairs with $Adenine$ $(A)$,$Guanine$ $(G)$ pairs with $Cytosine$ $(C)$,and $Cytosine$ $(C)$ pairs with $Guanine$ $(G)$.
However,in $RNA$,$Uracil$ $(U)$ replaces $Thymine$ $(T)$.
Therefore,the base pairing rules for $DNA$ to $mRNA$ transcription are:
$A$ $(DNA)$ $\rightarrow$ $U$ (mRNA)
$T$ $(DNA)$ $\rightarrow$ $A$ (mRNA)
$C$ $(DNA)$ $\rightarrow$ $G$ (mRNA)
$G$ $(DNA)$ $\rightarrow$ $C$ (mRNA)
Given the $DNA$ template sequence $ATACG$:
$A \rightarrow U$
$T \rightarrow A$
$A \rightarrow U$
$C \rightarrow G$
$G \rightarrow C$
Thus,the resulting $mRNA$ sequence is $UAUGC$.

(D) $RNA$ synthesis, also known as transcription, is the process of copying a segment of $DNA$ into $RNA$. This process is catalyzed by the enzyme $RNA$ polymerase. In prokaryotes, the $RNA$ polymerase enzyme consists of a core enzyme and a sigma factor $(\sigma)$. The sigma factor is essential for the initiation of transcription as it helps the $RNA$ polymerase to recognize the promoter site on the $DNA$ template. Therefore, $RNA$ polymerase is the primary enzyme responsible for the synthesis of $RNA$.

(B) The process of copying genetic information from one strand of the $DNA$ into $RNA$ is termed as $Transcription$.
In this process,only one segment of $DNA$ and only one of the two strands is copied into $RNA$.
$Translation$ is the process of protein synthesis from $m-RNA$.
$Replication$ is the process of $DNA$ duplication.

(A) The process of transcription,which involves the synthesis of $m-RNA$ from a $DNA$ template,occurs within the nucleus of eukaryotic cells.
After synthesis,the $m-RNA$ is processed and then transported out of the nucleus into the cytoplasm through nuclear pores to participate in protein synthesis at the ribosomes.

(B) The genetic information stored in the $DNA$ (located within the nucleus) is transcribed into $mRNA$ (messenger $RNA$).
$mRNA$ then moves out of the nucleus into the cytoplasm through nuclear pores.
In the cytoplasm,this $mRNA$ serves as a template for protein synthesis at the ribosomes.
Therefore,$RNA$ acts as the carrier of genetic information from the nucleus to the cytoplasm.

(A) The $DNA$ molecule consists of two strands: the template strand and the non-template (coding) strand.
During transcription,the $m-RNA$ is synthesized complementary to the template strand.
Since the $m-RNA$ sequence is complementary to the template strand and the template strand is complementary to the non-template strand,the $m-RNA$ sequence is identical to the non-template strand,except that $Thymine$ $(T)$ in $DNA$ is replaced by $Uracil$ $(U)$ in $RNA$.
Given non-template sequence: $CAG, TCG, GAT$.
Replacing $T$ with $U$ gives the $m-RNA$ sequence: $CAG, UCG, GAU$.

(A) The flow of genetic information from $DNA$ to $RNA$ is known as Transcription.
In this process,a segment of $DNA$ is copied into $RNA$ by the enzyme $RNA$ polymerase.
Translation is the process where $RNA$ is used to synthesize proteins.
Replication is the process of copying $DNA$ to form another $DNA$ molecule.
Transformation refers to the uptake of foreign genetic material by a cell.

(A) In $DNA$,the base pairing rules are $A$ pairs with $T$,and $C$ pairs with $G$.
When $DNA$ is transcribed into $RNA$,the base $T$ in $DNA$ is replaced by $U$ $(Uracil)$ in $RNA$.
Therefore,the complementary $RNA$ sequence is formed by pairing $A$ with $U$,$T$ with $A$,$C$ with $G$,and $G$ with $C$.
Given $DNA$ sequence: $CAT, TAG, CAT, CAT, GAC$.
$1$. $C$ pairs with $G$,$A$ pairs with $U$,$T$ pairs with $A$ $\rightarrow$ $GUA$.
$2$. $T$ pairs with $A$,$A$ pairs with $U$,$G$ pairs with $C$ $\rightarrow$ $AUC$.
$3$. $C$ pairs with $G$,$A$ pairs with $U$,$T$ pairs with $A$ $\rightarrow$ $GUA$.
$4$. $C$ pairs with $G$,$A$ pairs with $U$,$T$ pairs with $A$ $\rightarrow$ $GUA$.
$5$. $G$ pairs with $C$,$A$ pairs with $U$,$C$ pairs with $G$ $\rightarrow$ $CUG$.
Thus,the complementary $RNA$ sequence is $GUA, AUC, GUA, GUA, CUG$.

(B) The process of copying genetic information from one strand of the $DNA$ into $RNA$ is termed as $Transcription$.
$Translation$ refers to the process of polymerization of amino acids to form a polypeptide based on the sequence of nucleotides in $mRNA$.
$Transduction$ is the process by which foreign $DNA$ is introduced into a cell by a virus.
$Transformation$ is the process of uptake of naked $DNA$ by a bacterial cell.
Therefore,the correct answer is $Transcription$.

(C) Transcription is the process of copying genetic information from one strand of the $DNA$ into $RNA$.
In this process,the enzyme $RNA$ polymerase catalyzes the synthesis of $mRNA$ (messenger $RNA$) using a $DNA$ template.
Therefore,transcription is defined as the synthesis of $mRNA$ from a $DNA$ template.

(C) The process of copying genetic information from one strand of the $DNA$ into $RNA$ is termed as $Transcription$.
$1$. $Transcription$ is the first step in gene expression where a specific segment of $DNA$ is copied into $RNA$ by the enzyme $RNA$ polymerase.
$2$. $Translation$ is the process of protein synthesis from $mRNA$.
$3$. $Replication$ is the process of duplicating $DNA$.
$4$. $Transformation$ is the uptake of foreign genetic material by a cell.
Therefore, the correct option is $C$.

(B) In eukaryotic cells,the primary transcript (pre-$mRNA$) undergoes post-transcriptional modifications to become mature $mRNA$.
$1$. Capping: $A$ $7-methyl$ guanosine $(m^7G)$ cap is added to the $5'$ end of the transcript.
$2$. Tailing: $A$ poly-$A$ tail (a sequence of adenine nucleotides) is added to the $3'$ end.
$3$. Splicing: Introns are removed,and exons are joined together.
These modifications protect the $mRNA$ from degradation and facilitate its transport and translation. Therefore,the presence of a $5'$ cap and a $3'$ poly-$A$ tail is the hallmark of a mature eukaryotic $mRNA$.

(D) transcription unit in $DNA$ is defined primarily by three regions in the $DNA$:
$1$. $A$ Promoter: It is the site where transcription begins.
$2$. The Structural gene: It contains the genetic information required for the synthesis of $RNA$.
$3$. $A$ Terminator: It is the site where the transcription process ends.
Therefore,all these components together constitute the transcription unit. The correct option is $D$.

(B) In eukaryotic organisms, the primary transcript (pre-mRNA) contains both coding sequences (exons) and non-coding sequences (introns).
To form a functional mRNA, the non-coding introns must be removed, and the coding exons must be joined together in a specific order.
This process is known as $Splicing$.
$Capping$ refers to the addition of a methylguanosine triphosphate at the $5'$ end, and $Tailing$ refers to the addition of poly-$A$ residues at the $3'$ end.

(B) During the process of transcription,$DNA$ acts as a template for $m-RNA$ synthesis.
According to the base-pairing rules,$Adenine$ $(A)$ in $DNA$ pairs with $Uracil$ $(U)$ in $RNA$,and $Thymine$ $(T)$ in $DNA$ pairs with $Adenine$ $(A)$ in $RNA$.
The given $DNA$ template strand is $5'-AAAA-3'$.
Since the strands are antiparallel,the $m-RNA$ will be synthesized in the $5' \rightarrow 3'$ direction,complementary to the $3' \rightarrow 5'$ template.
Therefore,the $m-RNA$ sequence will be $3'-UUUU-5'$ (which is equivalent to $5'-UUUU-3'$ in terms of base composition).
Thus,the correct option is $B$.

(B) Transcription is the process of copying genetic information from one strand of the $DNA$ into $RNA$. The enzyme responsible for catalyzing this process is $DNA$-dependent $RNA$ polymerase. It uses $DNA$ as a template to synthesize a complementary $RNA$ strand. Therefore,the correct option is $B$.

(A) Transcription is the process of copying genetic information from one strand of the $DNA$ into $RNA$.
This process is catalyzed by the enzyme $RNA$ polymerase.
$DNA$ polymerase is involved in $DNA$ replication,while exonucleases are involved in $DNA$ repair or degradation,and recombinases are involved in genetic recombination.

(C) In the process of transcription,the $DNA$ sequence is copied into $RNA$.
Transcription begins at a specific site on the $DNA$ template strand known as the promoter.
The promoter acts as a binding site for $RNA$ polymerase,which initiates the synthesis of $RNA$.
Therefore,the promoter is the initiation site for transcription.

(B) In a transcription unit,the $DNA$ sequence is defined by the polarity of the template strand.
$1$. The promoter is a $DNA$ sequence that provides a binding site for $RNA$ polymerase.
$2$. It is located at the $5'$ end (upstream) of the structural gene.
$3$. The terminator is located at the $3'$ end (downstream) of the structural gene.
$4$. Therefore,the promoter is situated towards the $5'$ end of the structural gene.