PhysicsQ1–2 of 2 questions
Page 1 of 1 · English
1
PhysicsEasyMCQAIIMS · 1983
In which of the following cases may forces not be required to keep the state of motion?
A
Particle going in a circle
B
Particle going along a straight line
C
The momentum of the particle constant
D
Acceleration of the particle constant
Solution
(C) According to Newton's second law of motion,the force $F$ acting on a particle is given by the rate of change of its linear momentum $P$,which is $F = \frac{dP}{dt}$.
If the momentum $P$ of the particle is constant,then its derivative with respect to time is zero,i.e.,$\frac{dP}{dt} = 0$.
Therefore,the force $F$ required to maintain this state is zero.
Thus,option $(c)$ is correct.
If the momentum $P$ of the particle is constant,then its derivative with respect to time is zero,i.e.,$\frac{dP}{dt} = 0$.
Therefore,the force $F$ required to maintain this state is zero.
Thus,option $(c)$ is correct.
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2
PhysicsEasyMCQAIIMS · 1983
In the case of $NPN$ transistors,the collector current is always less than the emitter current because:
A
Collector side is reverse biased and emitter side is forward biased
B
After electrons are lost in the base,only the remaining ones reach the collector
C
Collector side is forward biased and emitter side is reverse biased
D
Collector being reverse biased attracts fewer electrons
Solution
(B) In an $NPN$ transistor,the emitter current $(I_E)$ is the sum of the base current $(I_B)$ and the collector current $(I_C)$,expressed as $I_E = I_B + I_C$.
Since a small fraction of electrons injected from the emitter recombine with holes in the base region,the base current $(I_B)$ is non-zero.
Therefore,the collector current is given by $I_C = I_E - I_B$.
Because $I_B > 0$,it follows that $I_C < I_E$.
Since a small fraction of electrons injected from the emitter recombine with holes in the base region,the base current $(I_B)$ is non-zero.
Therefore,the collector current is given by $I_C = I_E - I_B$.
Because $I_B > 0$,it follows that $I_C < I_E$.
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