Preparation of Haloalkanes Questions in English

(C) The reaction sequence is as follows:
$1$. Toluene reacts with $Br_2$ in the presence of $UV$ light to undergo free-radical substitution at the benzylic position,forming benzyl bromide $(C_6H_5CH_2Br)$.
$2$. Benzyl bromide reacts with $Mg$ in dry ether to form the Grignard reagent,benzylmagnesium bromide $(C_6H_5CH_2MgBr)$.
$3$. The Grignard reagent reacts with formaldehyde $(CH_2O)$ followed by acidic hydrolysis $(H_3O^+)$ to form $2-$phenylethanol $(C_6H_5CH_2CH_2OH)$.
$4$. Finally,$2$-phenylethanol reacts with $PBr_3$ to replace the hydroxyl group with a bromine atom,yielding ($2$-bromoethyl)benzene $(C_6H_5CH_2CH_2Br)$.

(D) The Swarts reaction is used to replace chlorine atoms with fluorine atoms in alkyl halides using inorganic fluorides like $\text{SbF}_3$ or $\text{Hg}_2\text{F}_2$.
This is the method used for the fluorination of $\text{CCl}_4$ to form $\text{CCl}_2\text{F}_2$ (Freon-$12$).
The reaction is: $\text{CCl}_4 + 2\text{HF} \xrightarrow{\text{SbF}_3} \text{CCl}_2\text{F}_2 + 2\text{HCl}$.