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Basic Terms Questions in English

Class 12 Chemistry · Coordination Compounds · Basic Terms

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251
AdvancedMCQ
If the addition of $AgNO_3$ to a solution of $Co(NH_3)_5Cl_3$ results in the precipitation of $AgCl$ corresponding to two ionizable chloride ions,it means that ..............
A
Two chlorine atoms satisfy primary valency and one chlorine atom satisfies secondary valency.
B
One chlorine atom satisfies both primary and secondary valency.
C
Three chlorine atoms satisfy primary valency.
D
Three chlorine atoms satisfy secondary valency.

Solution

(B) According to Werner's coordination theory,the chloride ions that are ionizable are those present outside the coordination sphere (primary valency).
Since the addition of $AgNO_3$ yields $AgCl$ precipitates corresponding to two chloride ions,it implies that two $Cl^-$ ions are outside the coordination sphere.
The formula of the complex is $[Co(NH_3)_5Cl]Cl_2$.
In this complex,the $Cl^-$ ion inside the square bracket satisfies both primary and secondary valency,while the two $Cl^-$ ions outside the bracket satisfy only primary valency.
Therefore,one chlorine atom satisfies both primary and secondary valency.
252
AdvancedMCQ
$A$ coordination compound of cobalt contains five ammonia molecules,one nitro group,and two chlorine atoms per cobalt atom. One mole of this compound produces three moles of ions in an aqueous solution. Reaction of this solution with excess $AgNO_3$ yields two moles of $AgCl$ precipitate. What is the ionic structure of this complex?
A
$[Co(NH_3)_4(NO_2)Cl][(NH_3)Cl]$
B
$[Co(NH_3)_5Cl][Cl(NO_2)]$
C
$[Co(NH_3)_5(NO_2)]Cl_2$
D
$[Co(NH_3)_5][(NO_2)_2Cl_2]$

Solution

(C) $1$. The complex contains $1$ $Co$ atom,$5$ $NH_3$ molecules,$1$ $NO_2$ group,and $2$ $Cl$ atoms.
$2$. The formation of $2$ moles of $AgCl$ precipitate with excess $AgNO_3$ indicates that there are $2$ ionizable $Cl^-$ ions outside the coordination sphere.
$3$. The total number of ions produced is $3$ ($1$ complex cation + $2$ $Cl^-$ anions),which matches the given information.
$4$. Therefore,the coordination sphere must be $[Co(NH_3)_5(NO_2)]$ and the counter ions are $2$ $Cl^-$.
$5$. The formula is $[Co(NH_3)_5(NO_2)]Cl_2$.
253
MediumMCQ
The number of chloride ions produced in an aqueous solution of tetraamminedichloroplatinum $(IV)$ chloride is ...........
A
$4$
B
$2$
C
$1$
D
$3$

Solution

(B) The chemical formula for tetraamminedichloroplatinum $(IV)$ chloride is $[Pt(NH_3)_4Cl_2]Cl_2$.
In an aqueous solution,this coordination compound dissociates as follows:
$[Pt(NH_3)_4Cl_2]Cl_2 (aq) \rightarrow [Pt(NH_3)_4Cl_2]^{2+} (aq) + 2Cl^- (aq)$.
From the dissociation,it is clear that $1$ mole of the complex produces $2$ moles of chloride ions $(Cl^-)$.
Therefore,the number of chloride ions produced is $2$.
254
MediumMCQ
The formula for iron $(III)$ hexacyanoferrate $(II)$ is ..........
A
$Fe[Fe(CN)_6]$
B
$Fe_3[Fe(CN)_6]$
C
$Fe_3[Fe(CN)_6]_4$
D
$Fe_4[Fe(CN)_6]_3$

Solution

(D) To determine the formula,we balance the charges of the ions involved.
Iron $(III)$ is $Fe^{3+}$.
Hexacyanoferrate $(II)$ is $[Fe(CN)_6]^{4-}$.
To make the compound electrically neutral,we use the criss-cross method:
$4 \times (Fe^{3+}) + 3 \times ([Fe(CN)_6]^{4-}) = 0$.
Thus,the formula is $Fe_4[Fe(CN)_6]_3$.
255
MediumMCQ
The ratio of the number of cations,anions,and water molecules respectively in potash alum is:
A
$1 : 2 : 6$
B
$1 : 1 : 2$
C
$1 : 1 : 6$
D
$2 : 2 : 6$

Solution

(C) The chemical formula of potash alum is $K_2SO_4 \cdot Al_2(SO_4)_3 \cdot 24H_2O$,which can be written as $K_2Al_2(SO_4)_4 \cdot 24H_2O$.
In this formula,the cations are $K^+$ and $Al^{3+}$,totaling $2 + 2 = 4$ cations.
The anions are $SO_4^{2-}$,totaling $4$ anions.
The number of water molecules is $24$.
Thus,the ratio of cations : anions : water molecules is $4 : 4 : 24$.
Simplifying this ratio by dividing by $4$,we get $1 : 1 : 6$.
256
EasyMCQ
In $[Ag(CN)_2]^-$,the number of $\pi$ bonds is
A
$2$
B
$3$
C
$4$
D
$6$

Solution

(C) The cyanide ion,$CN^-$,contains a triple bond between carbon and nitrogen,which consists of one $\sigma$ bond and two $\pi$ bonds.
In the complex $[Ag(CN)_2]^-$,there are two $CN^-$ ligands.
Therefore,the total number of $\pi$ bonds $= 2 \times 2 = 4$.
257
DifficultMCQ
When $AgNO_3$ is added to a solution of $Co(NH_3)_5Cl_3$,the precipitate of $AgCl$ shows two ionizable chloride ions. This means
A
Two chlorine atoms satisfy primary valency and one secondary valency
B
One chlorine atom satisfies primary as well as secondary valency
C
Three chlorine atoms satisfy primary valency
D
Three chlorine atoms satisfy secondary valency

Solution

(A) The formation of two moles of $AgCl$ precipitate indicates that there are two ionizable chloride ions outside the coordination sphere.
Therefore,the complex can be represented as $[Co(NH_3)_5Cl]Cl_2$.
In this structure,the two chloride ions outside the square brackets satisfy the primary valency,while the one chloride ion inside the coordination sphere satisfies both the primary and secondary valency.
The reaction is: $[Co(NH_3)_5Cl]Cl_2 + 2AgNO_3 \to [Co(NH_3)_5Cl](NO_3)_2 + 2AgCl$.
258
DifficultMCQ
The coordination number and the oxidation state of the element $E$ in the complex $[E(en)_2(C_2O_4)]NO_2$ (where $en$ is ethylene diamine) are,respectively:
A
$6$ and $2$
B
$4$ and $2$
C
$4$ and $3$
D
$6$ and $3$

Solution

(D) In the given complex,there are two $en$ ligands and one $C_2O_4$ ligand. Both are bidentate ligands.
Coordination number = $(2 \times 2) + (1 \times 2) = 4 + 2 = 6$.
Let the oxidation state of $E$ be $x$.
The complex is $[E(en)_2(C_2O_4)]NO_2$. Since $NO_2$ is a counter ion with a charge of $-1$,the complex cation $[E(en)_2(C_2O_4)]^+$ has a charge of $+1$.
$x + 2(0) + 1(-2) = +1$
$x - 2 = +1$
$x = +3$.
Therefore,the coordination number is $6$ and the oxidation state is $+3$. Thus,option $(d)$ is correct.
259
DifficultMCQ
Consider the following complex $[Co(NH_3)_5CO_3]ClO_4$. The coordination number,oxidation number,number of $d-$ electrons,and number of unpaired $d-$ electrons on the metal are respectively:
A
$6, 3, 6, 0$
B
$7, 2, 7, 1$
C
$7, 1, 6, 4$
D
$6, 2, 7, 3$

Solution

(B) The complex is $[Co(NH_3)_5CO_3]ClO_4$.
$NH_3$ is a monodentate ligand ($5$ ligands) and $CO_3^{2-}$ is a bidentate ligand ($1$ ligand).
Coordination number $(C.N.)$ $= 5 \times 1 + 1 \times 2 = 7$.
Let the oxidation state of $Co$ be $x$.
$x + 5(0) + 1(-2) + 1(-1) = 0 \implies x - 3 = 0 \implies x = +3$.
Electronic configuration of $Co$ $(Z=27)$ is $[Ar] 3d^7 4s^2$.
Electronic configuration of $Co^{3+}$ is $[Ar] 3d^6 4s^0$.
Number of $d-$ electrons is $6$.
Since $NH_3$ and $CO_3^{2-}$ are ligands,in the presence of strong field ligands,the $6$ electrons in the $3d$ orbital are paired.
Number of unpaired $d-$ electrons $= 0$.
260
DifficultMCQ
Assertion : When $NO$ reacts with $FeSO_4$,a brown coloured complex is formed.
Reason : In the complex,the coordination number of $Fe$ is $6$.
A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
C
If the Assertion is correct but Reason is incorrect.
D
If both the Assertion and Reason are incorrect.

Solution

(B) In the qualitative analysis of nitrate,a brown ring is formed due to the formation of $[Fe(H_2O)_5(NO)]^{2+}$. The chemical reaction is: $FeSO_4 + NO + 5H_2O \to [Fe(H_2O)_5(NO)]SO_4$.
In this complex,the central metal ion is $Fe^{2+}$. The ligands are five $H_2O$ molecules and one $NO$ molecule.
The coordination number is the total number of sigma bonds formed by the ligand atoms with the central metal ion,which is $5 + 1 = 6$.
Both the Assertion and the Reason are correct,but the Reason does not explain why the complex is brown-coloured (which is due to charge transfer). Therefore,the Reason is not the correct explanation of the Assertion.
261
DifficultMCQ
Assertion : $A$ chelating ligand must possess two or more lone pairs at such a distance that it may form suitable strain-free rings at the metal ion.
Reason : $H_2N-NH_2$ is a chelating ligand.
A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
C
If the Assertion is correct but Reason is incorrect.
D
If both the Assertion and Reason are incorrect.

Solution

(C) The Assertion is correct because a chelating ligand requires donor atoms positioned to form stable,strain-free rings (typically $5$ or $6$ membered) with the metal ion.
The Reason is incorrect because hydrazine $(H_2N-NH_2)$ acts as a monodentate ligand. Coordination by hydrazine would result in a $3$-membered ring,which is highly unstable due to significant angle strain,thus it does not act as a chelating ligand.
262
MediumMCQ
Assertion : Ethylenediaminetetraacetate ion forms an octahedral complex with the metal ion.
Reason : It has six donor atoms which coordinate simultaneously to the metal ion.
A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
C
If the Assertion is correct but Reason is incorrect.
D
If both the Assertion and Reason are incorrect.

Solution

(A) The $EDTA^{4-}$ ion is a hexadentate ligand,meaning it has $6$ donor atoms (two nitrogen atoms and four oxygen atoms).
These $6$ donor atoms coordinate simultaneously to the central metal ion,forming a stable octahedral complex.
Therefore,the Reason correctly explains why the Assertion is true.
263
EasyMCQ
Are the oxidation state and covalency of $Al$ in $[AlCl(H_{2}O)_{5}]^{2+}$ same?
A
Yes
B
No
C
Cannot be determined
D
Depends on the solvent

Solution

(B) In the complex ion $[AlCl(H_{2}O)_{5}]^{2+}$,let the oxidation state of $Al$ be $x$.
$x + (-1) + 5(0) = +2$
$x - 1 = +2$
$x = +3$.
Thus,the oxidation state of $Al$ is $+3$.
The covalency is the total number of coordinate bonds formed by the central metal atom with the ligands.
Here,$Al$ is bonded to $1$ $Cl^-$ ion and $5$ $H_2O$ molecules,so the total number of coordinate bonds is $1 + 5 = 6$.
Therefore,the oxidation state $(+3)$ and covalency $(6)$ are not the same.
264
Easy
On the basis of the following observations made with aqueous solutions,assign secondary valences to metals in the following compounds:
Formula Moles of $AgCl$ precipitated per mole of the compound with excess $AgNO_3$
$(i) PdCl_2 \cdot 4NH_3$ $2$
$(ii) NiCl_2 \cdot 6H_2O$ $2$
$(iii) PtCl_4 \cdot 2HCl$ $0$
$(iv) CoCl_3 \cdot 4NH_3$ $1$
$(v) PtCl_2 \cdot 2NH_3$ $0$

Solution

(A) The secondary valence corresponds to the coordination number of the central metal atom.
$(i) PdCl_2 \cdot 4NH_3$ gives $2$ moles of $AgCl$,meaning $2$ $Cl^-$ ions are outside the coordination sphere. The formula is $[Pd(NH_3)_4]Cl_2$. Secondary valence = $4$.
$(ii) NiCl_2 \cdot 6H_2O$ gives $2$ moles of $AgCl$,meaning $2$ $Cl^-$ ions are outside. The formula is $[Ni(H_2O)_6]Cl_2$. Secondary valence = $6$.
$(iii) PtCl_4 \cdot 2HCl$ gives $0$ moles of $AgCl$,meaning all $Cl^-$ ions are inside. The formula is $H_2[PtCl_6]$. Secondary valence = $6$.
$(iv) CoCl_3 \cdot 4NH_3$ gives $1$ mole of $AgCl$,meaning $1$ $Cl^-$ ion is outside. The formula is $[Co(NH_3)_4Cl_2]Cl$. Secondary valence = $6$.
$(v) PtCl_2 \cdot 2NH_3$ gives $0$ moles of $AgCl$,meaning all $Cl^-$ ions are inside. The formula is $[Pt(NH_3)_2Cl_2]$. Secondary valence = $4$.
265
Medium
Explain the bonding in coordination compounds in terms of Werner's postulates.

Solution

(N/A) Werner's postulates explain the bonding in coordination compounds as follows:
$(i)$ $A$ metal exhibits two types of valencies,namely,primary and secondary valencies. Primary valencies are satisfied by negative ions,while secondary valencies are satisfied by both negative and neutral ions.
(In modern terminology,the primary valency corresponds to the oxidation number of the metal ion,whereas the secondary valency refers to the coordination number of the metal ion.)
$(ii)$ $A$ metal ion has a definite number of secondary valencies around the central atom. These valencies project in a specific direction in space,which determines the geometry of the coordination compound.
$(iii)$ Primary valencies are usually ionizable,while secondary valencies are non-ionizable.
266
Difficult
Explain with two examples each of the following: coordination entity,ligand,coordination number,coordination polyhedron,homoleptic and heteroleptic.

Solution

(N/A) $(i)$ Coordination entity:
$A$ coordination entity is an electrically charged radical or species. In a coordination entity,the central atom or ion is surrounded by a suitable number of neutral molecules or negative ions (called ligands). For example:
Cationic complex: $[Ni(NH_3)_6]^{2+}, [Fe(H_2O)_6]^{3+}$
Anionic complex: $[PtCl_4]^{2-}, [Ag(CN)_2]^{-}$
$(ii)$ Ligands:
The neutral molecules or negatively charged ions that surround the metal atom in a coordination entity are known as ligands. For example,$NH_3$ and $Cl^-$.
$(iii)$ Coordination number:
The total number of ligand donor atoms to which the central metal atom is directly bonded is called the coordination number. For example:
$(a)$ In $[PtCl_6]^{2-}$,the coordination number of $Pt$ is $6$.
$(b)$ In $[Ni(NH_3)_4]^{2+}$,the coordination number of $Ni$ is $4$.
$(iv)$ Coordination polyhedron:
It is the spatial arrangement of the ligand atoms which are directly attached to the central atom/ion. Examples include square planar and tetrahedral geometries.
$(v)$ Homoleptic complexes:
These are complexes in which the metal ion is bound to only one kind of donor group. For example: $[Co(NH_3)_6]^{3+}, [Ni(CO)_4]$.
$(vi)$ Heteroleptic complexes:
These are complexes where the central metal ion is bound to more than one type of donor group. For example: $[Co(NH_3)_4Cl_2]^{+}, [Co(NH_3)_5Cl]^{2+}$
267
Difficult
What is meant by unidentate,didentate and ambidentate ligands? Give two examples for each.

Solution

(N/A) ligand may contain one or more unshared pairs of electrons which are called the donor sites of ligands. Depending on the number of these donor sites,ligands can be classified as follows:
$(a)$ Unidentate ligands: Ligands with only one donor site are called unidentate ligands. For example,$NH_3$ and $Cl^-$.
$(b)$ Didentate ligands: Ligands that have two donor sites are called didentate ligands. For example,$H_2N-CH_2-CH_2-NH_2$ (ethane$-1,2-$diamine) and $C_2O_4^{2-}$ (oxalate ion).
$(c)$ Ambidentate ligands: Ligands that can attach themselves to the central metal atom through two different atoms are called ambidentate ligands. For example:
$1. NO_2^-$ (nitro,donor atom is $N$) and $ONO^-$ (nitrito,donor atom is $O$)
$2. SCN^-$ (thiocyanate,donor atom is $S$) and $NCS^-$ (isothiocyanate,donor atom is $N$)
268
Easy
How many ions are produced from the complex $[Co(NH_3)_6]Cl_2$ in solution?
$i. 6 \quad ii. 4 \quad iii. 3 \quad iv. 2$

Solution

(C) $iii.$ The given complex can be written as $[Co(NH_3)_6]Cl_2$.
In an aqueous solution,it dissociates as follows:
$[Co(NH_3)_6]Cl_2 \rightarrow [Co(NH_3)_6]^{2+} + 2Cl^-$
Thus,one $[Co(NH_3)_6]^{2+}$ ion and two $Cl^-$ ions are produced,resulting in a total of $3$ ions.
269
EasyMCQ
Complex compounds are formed between metal ions and which of the following?
A
Ligands
B
Solvents
C
Catalysts
D
Inert gases

Solution

(A) Complex compounds (or coordination compounds) are formed by the coordinate bonding between a central metal atom or ion and a surrounding array of molecules or anions,which are known as $Ligands$.
These $Ligands$ donate a pair of electrons to the central metal atom or ion to form coordinate covalent bonds.
270
Easy
What are coordination compounds?

Solution

(N/A) Coordination compounds are chemical compounds formed by the transition elements of the $d$-block of the periodic table.
When the $(n-1)d, ns$,and $np$ orbitals or $ns, np$,and $nd$ orbitals of a transition metal atom or ion are vacant,these elements accept electron pairs from anions or neutral molecules to form coordination compounds.
The bond formed between the metal atom/ion and the anions/neutral molecules in these compounds is known as a coordinate covalent bond.
271
Medium
Enlist the main postulates of Werner's theory.

Solution

(N/A) The main postulates of Werner's theory are:
$1$. In coordination compounds,metals exhibit two types of linkages or valencies: primary and secondary.
$2$. Primary valencies are normally ionisable and are satisfied by negative ions.
$3$. Secondary valencies are non-ionisable.
$4$. Secondary valencies are satisfied by neutral molecules or negative ions. The secondary valency is equal to the coordination number and is fixed for a metal.
$5$. The ions/groups bound by secondary linkages to the metal have characteristic spatial arrangements corresponding to different coordination numbers. Such a spatial arrangement is called a coordination polyhedron.
$6$. Octahedral,tetrahedral,and square planar geometrical shapes are common in coordination compounds of transition metals.
For example:
Octahedral complexes: $[Co(NH_3)_6]^{3+}, [CoCl(NH_3)_5]^{2+}, [CoCl_2(NH_3)_4]^{+}$
Tetrahedral complex: $[Ni(CO)_4]$
Square planar complex: $[PtCl_4]^{2-}$
The species within the square bracket are coordination entities or complexes,and the ions outside the square bracket are called counter ions.
272
Medium
Explain the concept of Primary Valency and Secondary Valency as proposed by Alfred Werner.

Solution

(N/A) Alfred Werner prepared and characterized a large number of coordination compounds and studied their physical and chemical behavior. He was the first to formulate ideas about the structure of coordination compounds.
$1$. Primary Valency: These are ionizable valencies,generally satisfied by negative ions. They correspond to the oxidation state of the metal ion.
$2$. Secondary Valency: These are non-ionizable valencies,satisfied by neutral molecules or negative ions. They correspond to the coordination number of the metal ion.
In a series of compounds of cobalt$(III)$ chloride with ammonia,it was found that some chloride ions could be precipitated as $AgCl$ on adding excess $AgNO_{3}$ solution,while others remained bonded to the metal.
$1$ mol $CoCl_{3} \cdot 6 NH_{3}$ (Yellow) gave $3$ mol $AgCl$
$1$ mol $CoCl_{3} \cdot 5 NH_{3}$ (Purple) gave $2$ mol $AgCl$
$1$ mol $CoCl_{3} \cdot 4 NH_{3}$ (Green) gave $1$ mol $AgCl$
$1$ mol $CoCl_{3} \cdot 4 NH_{3}$ (Violet) gave $1$ mol $AgCl$
$Formula$ $Solution \text{ } conductivity$
$[Co(NH_{3})_{6}]Cl_{3}$ $1:3$ electrolyte
$[CoCl(NH_{3})_{5}]Cl_{2}$ $1:2$ electrolyte
$[CoCl_{2}(NH_{3})_{4}]Cl$ $1:1$ electrolyte

In these compounds,the atoms within the square brackets are directly bonded to the metal ion and represent the secondary valency,which is $6$ for cobalt in these examples.
273
Medium
Explain double salts and coordination compounds.

Solution

(N/A) Both double salts and coordination compounds are formed by the combination of two or more stable compounds in stoichiometric ratios. However,they differ in their behavior in solution.
Double salts,such as carnallite $(KCl \cdot MgCl_2 \cdot 6H_2O)$,Mohr's salt $(FeSO_4 \cdot (NH_4)_2SO_4 \cdot 6H_2O)$,and potash alum $(KAl(SO_4)_2 \cdot 12H_2O)$,dissociate completely into simple ions when dissolved in water.
In contrast,coordination compounds like $K_4[Fe(CN)_6]$ contain complex ions. The complex ion $[Fe(CN)_6]^{4-}$ does not dissociate into $Fe^{2+}$ and $CN^-$ ions in solution.
274
MediumMCQ
What is a coordination compound?
A
$A$ compound formed by the combination of two or more simple salts.
B
$A$ compound containing a central metal atom or ion bonded to a surrounding array of molecules or anions,called ligands.
C
$A$ compound that dissociates completely into its constituent ions in aqueous solution.
D
$A$ compound formed by the sharing of electrons between two non-metal atoms.

Solution

(B) coordination compound is a chemical structure that consists of a central metal atom or ion bonded to a surrounding array of molecules or anions,which are known as ligands.
These ligands are attached to the central metal atom or ion by coordinate covalent bonds.
For example,in the complex $[Cu(NH_3)_4]^{2+}$,the $Cu^{2+}$ ion is the central metal ion,and the four $NH_3$ molecules act as ligands.
275
EasyMCQ
Determine the primary and secondary valency for $K_4[Fe(CN)_6]$.
A
Primary valency = $2$,Secondary valency = $6$
B
Primary valency = $4$,Secondary valency = $6$
C
Primary valency = $6$,Secondary valency = $2$
D
Primary valency = $2$,Secondary valency = $4$

Solution

(A) In the coordination compound $K_4[Fe(CN)_6]$,the central metal atom is $Fe$.
The primary valency corresponds to the oxidation state of the central metal atom.
Let the oxidation state of $Fe$ be $x$.
$4(+1) + x + 6(-1) = 0$
$4 + x - 6 = 0$
$x = +2$.
Thus,the primary valency is $2$.
The secondary valency corresponds to the coordination number,which is the number of ligand donor atoms directly bonded to the central metal atom.
Here,$6$ $CN^-$ ligands are bonded to $Fe$,so the coordination number is $6$.
Thus,the secondary valency is $6$.
276
EasyMCQ
What is the coordination number of $Co$ in $[CoCl_2(NH_3)_4]^+$?
A
$2$
B
$4$
C
$6$
D
$8$

Solution

(C) The coordination number is defined as the number of ligand donor atoms to which the metal is directly bonded.
In the complex $[CoCl_2(NH_3)_4]^+$,the central metal ion is $Co^{3+}$.
There are $2$ $Cl^-$ ligands (monodentate) and $4$ $NH_3$ ligands (monodentate).
Total coordination number = $(2 \times 1) + (4 \times 1) = 6$.
277
Difficult
Explain the terms 'Coordination Entity' and 'Central Atom/Ion' in the context of coordination compounds.

Solution

(N/A) Coordination Entity: $A$ coordination entity constitutes a central metal atom or ion bonded to a fixed number of ions or molecules.
Example: In $\left[ CoCl_3(NH_3)_3 \right]$,the cobalt ion is surrounded by three ammonia molecules and three chloride ions.
Central Atom/Ion: The atom or ion to which a fixed number of ions or groups are bound in a definite geometrical arrangement around it in a coordination entity is called the central atom or ion.
Example: In $\left[ CoCl_3(NH_3)_3 \right]$,the central metal ion is $Co^{3+}$,which acts as a Lewis acid.
278
Medium
Provide the classification of ligands.

Solution

(N/A) Ligands are atoms,molecules,or ions that donate an electron pair to the central metal ion to form a coordination bond. They can be classified based on different criteria:
$1$. On the basis of charge:
- Neutral ligands: $H_2O, NH_3, CO$
- Anionic ligands: $Cl^-, CN^-, OH^-$
- Cationic ligands: $NO^+, NH_2NH_3^+$
$2$. On the basis of denticity (number of donor atoms):
- Monodentate (Unidentate): Ligands with one donor atom (e.g.,$Cl^-, H_2O$)
- Polydentate: Ligands with more than one donor atom (e.g.,$EDTA^{4-}$ is hexadentate)
Special types include:
- Ambidentate ligands: Ligands that can coordinate through two different atoms (e.g.,$SCN^-$ can coordinate through $S$ or $N$)
- Bridging ligands: Ligands that link two metal centers.
279
Difficult
Explain the terms: Coordination Number,Coordination Sphere,and Coordination Polyhedron.

Solution

(N/A) Coordination Number: The number of ligand donor atoms to which the metal is directly bonded is called the coordination number. For example,in the complex ions $[PtCl_6]^{2-}$ and $[Ni(NH_3)_4]^{2+}$,the coordination numbers of $Pt$ and $Ni$ are $6$ and $4$ respectively. In $[Fe(C_2O_4)_3]^{3-}$ and $[Co(en)_3]^{3+}$,the coordination number of $Fe$ and $Co$ is $6$.
Coordination Sphere: The central atom/ion and the ligands attached to it are enclosed in a square bracket and are collectively termed as the coordination sphere.
The groups that ionize are written outside the bracket and are called counter ions. For example,in the complex $K_4[Fe(CN)_6]$,$[Fe(CN)_6]^{4-}$ is the coordination sphere and $K^+$ is the counter ion.
Coordination Polyhedron: The spatial arrangement of the ligand atoms which are directly attached to the central atom/ion defines the geometry of the coordination polyhedron.
280
Medium
Explain homoleptic and heteroleptic complexes.

Solution

(N/A) Homoleptic complexes: These are coordination complexes in which the metal atom or ion is bonded to only one type of donor group (ligand).
Example: $[Co(NH_3)_6]^{3+}$.
Heteroleptic complexes: These are coordination complexes in which the metal atom or ion is bonded to more than one type of donor group (ligand).
Example: $[Co(NH_3)_4Cl_2]^+$.
281
Easy
Explain the following term with an example: Hexadentate ligands.

Solution

(N/A) Hexadentate ligands: These are ligands that possess $six$ donor atoms and are capable of forming $six$ coordinate bonds with a single metal ion simultaneously.
Example: Ethylenediamine tetraacetate $(EDTA^{4-})$ is a classic example of a hexadentate ligand. It contains $two$ nitrogen atoms and $four$ oxygen atoms as donor sites,as shown in the structure:
(Structure of $EDTA^{4-}$ with $six$ donor sites labeled $1$ to $6$)
282
MediumMCQ
On what basis is the classification of ligands done?
A
Based on the charge on the ligand
B
Based on the number of donor atoms (denticity)
C
Based on the nature of the metal ion
D
Based on the geometry of the complex

Solution

(B) Ligands are classified based on the number of donor atoms they use to coordinate with the central metal atom or ion. This property is known as the $denticity$ of the ligand. Depending on the number of donor atoms,ligands can be classified as monodentate,bidentate,polydentate,etc.
283
Medium
State the rules for writing the formula of a mononuclear coordination species.

Solution

(N/A) The following rules are applied for writing the formulas of coordination compounds:
$(i)$ The central atom is written first.
$(ii)$ The ligands are then written in alphabetical order.
$(iii)$ Polydentate ligands are also listed in alphabetical order. In the case of abbreviated ligands,the first letter of the abbreviation is used to determine the alphabetical order.
$(iv)$ The formula for the entire coordination entity,whether charged or not,is enclosed in square brackets. When ligands are polyatomic,their formulas are enclosed in parentheses. Abbreviations are also enclosed in parentheses.
$(v)$ There should be no space between the ligands and the metal within the coordination sphere.
$(vi)$ When the formula of a charged coordination entity is written,the charge is indicated outside the square brackets as a superscript on the right side,without the counter-ion charge.
Example: $[Co(CN)_6]^{3-}$.
$(vii)$ The charge of the cation is balanced by the charge of the anion.
284
MediumMCQ
Give examples of ambidentate ligands.
A
$NO_2^-$ and $SCN^-$
B
$Cl^-$ and $Br^-$
C
$NH_3$ and $H_2O$
D
$CO$ and $CN^-$

Solution

(A) An ambidentate ligand is a ligand that can coordinate to a central metal atom through two different donor atoms.
Examples include:
$1$. $NO_2^-$: It can coordinate through the nitrogen atom (nitro,$M-NO_2$) or through the oxygen atom (nitrito,$M-ONO$).
$2$. $SCN^-$: It can coordinate through the sulfur atom (thiocyanato,$M-SCN$) or through the nitrogen atom (isothiocyanato,$M-NCS$).
285
Difficult
$A$ coordination compound $CrCl_{3} \cdot 4 H_{2} O$ precipitates silver chloride when treated with silver nitrate. The molar conductance of its solution corresponds to a total of two ions. Write the structural formula of the compound and name it.

Solution

(N/A) The compound gives a white precipitate of $AgCl$ when treated with $AgNO_{3}$,which indicates that at least one $Cl^{-}$ ion is present in the ionization sphere.
Since the molar conductance corresponds to a total of two ions,the complex must dissociate into two ions: one cation and one anion.
Therefore,the complex must be $[Cr(H_{2}O)_{4}Cl_{2}]Cl$,which dissociates as $[Cr(H_{2}O)_{4}Cl_{2}]Cl \rightarrow [Cr(H_{2}O)_{4}Cl_{2}]^{+} + Cl^{-}$.
The structural formula is $[Cr(H_{2}O)_{4}Cl_{2}]Cl$ and its $IUPAC$ name is Tetraaquadichloridochromium$(III)$ chloride.
286
Medium
Define the following terms:
$1$. Coordination entity
$2$. Central metal ion

Solution

Coordination entity: $A$ coordination entity constitutes a central metal atom or ion bonded to a fixed number of ions or molecules. For example,$[CoCl_{3}(NH_{3})_{3}]$ is a coordination entity in which the cobalt is surrounded by three ammonia and three chloride ions. Other examples are $[Ni(CO)_{4}]$,$[PtCl_{2}(NH_{3})_{2}]$,$[Fe(CN)_{6}]^{4-}$,and $[Co(NH_{3})_{6}]^{3+}$.
Central metal ion/atom: In a coordination entity,the atom or ion to which a fixed number of ions or groups are bound in a definite geometrical arrangement is called the central metal ion or atom. For example,in the coordination entities $[NiCl_{2}(H_{2}O)_{4}]$,$[CoCl(NH_{3})_{5}]^{2+}$,and $[Fe(CN)_{6}]^{3-}$,the central ions are $Ni^{2+}$,$Co^{3+}$,and $Fe^{3+}$ respectively. These central ions or atoms act as electron pair acceptors and are also referred to as Lewis acids.
287
Medium
Define the following terms:
$1$. Ligands
$2$. Coordination number

Solution

(N/A) Ligands: The ions or molecules bound to the central atom/ion in the coordination entity are called ligands. These may be simple ions such as $Cl^{-}$,small molecules such as $H_{2}O$ or $NH_{3}$,larger molecules such as $H_{2}NCH_{2}CH_{2}NH_{2}$ or $N(CH_{2}CH_{2}NH_{2})_{3}$,or even macromolecules such as proteins. Ligands are electron pair donors and are therefore referred to as Lewis bases.
Coordination number $(CN)$: The coordination number of a metal ion in a complex is defined as the number of ligand donor atoms to which the metal is directly bonded. The coordination number depends on the denticity of the ligands. For example,in the complexes $[PtCl_{6}]^{2-}$ and $[Ni(NH_{3})_{4}]^{2+}$,the coordination numbers of $Pt$ and $Ni$ are $6$ and $4$,respectively. Similarly,in the complex ions $[Fe(C_{2}O_{4})_{3}]^{3-}$ and $[Co(en)_{3}]^{3+}$,the coordination number of both $Fe$ and $Co$ is $6$ because $C_{2}O_{4}^{2-}$ and $en$ (ethane-$1,2$-diamine) are bidentate ligands. The coordination number is determined only by the number of sigma bonds formed between the ligand donor atoms and the central metal ion.
288
Medium
Define the following term: Coordination sphere.

Solution

(N/A) Coordination sphere: The central metal atom or ion and the ligands directly attached to it are enclosed within a square bracket,which is collectively referred to as the coordination sphere. For example,in the complex $K_{4}[Fe(CN)_{6}]$,the coordination sphere is $[Fe(CN)_{6}]^{4-}$,while $K^{+}$ acts as the counter ion. Counter ions are ionizable groups that are written outside the square bracket.
289
Medium
Define the following terms: Homoleptic and heteroleptic complexes.

Solution

(N/A) Homoleptic and heteroleptic complexes:
$(a)$ Homoleptic Complexes: Complexes in which a metal is bound to only one kind of donor groups are known as homoleptic.
Example: $[Co(NH_3)_6]^{3+}, [Ni(CO)_4]$ etc.
$(b)$ Heteroleptic Complexes: Complexes in which a metal is bound to more than one kind of donor groups are known as heteroleptic.
Example: $[Co(NH_3)_4Cl_2]^{+}, [Co(CN)_2Cl_2]^{+}$ etc.
290
Medium
Define the following terms: Homoleptic and heteroleptic complexes.

Solution

(N/A) Homoleptic and heteroleptic complexes:
$(a)$ Homoleptic Complexes: Complexes in which a metal is bound to only one kind of donor groups are known as homoleptic.
Example: $[Co(NH_{3})_{6}]^{3+}, [Ni(CO)_{4}]$.
$(b)$ Heteroleptic Complexes: Complexes in which a metal is bound to more than one kind of donor groups are known as heteroleptic.
Example: $[Co(NH_{3})_{4}Cl_{2}]^{+}, [Pt(NH_{3})_{2}Cl_{2}]$.
291
Medium
Explain the classification of ligands on the basis of charge.

Solution

(N/A) $i$. Anionic ligands: Ligands that carry a negative charge are called anionic ligands. Examples include $Cl^{-}, Br^{-}, I^{-}, C_{2}O_{4}^{2-}, SO_{4}^{2-}, NO_{3}^{-}, NO_{2}^{-}$.
$ii$. Cationic ligands: Ligands that carry a positive charge are called cationic ligands. Examples include $NO^{+}, NH_{2}NH_{3}^{+}$.
$iii$. Neutral ligands: Ligands that carry no charge are called neutral ligands. Examples include $H_{2}O, CH_{3}OH, NH_{3}, CO$,and pyridine.
292
Medium
Explain the classification of ligands on the basis of their denticity.

Solution

(N/A) The total number of donor atoms in a ligand is called its denticity.
$(i)$ Monodentate ligands: These ligands have only one donor atom or are coordinated through a single electron pair with a metal ion. They are also known as unidentate ligands. They may be neutral or anionic.
Example:
$(a)$ Neutral: $H_{2}O, CO, NH_{3}, C_{6}H_{5}N$ (pyridine) etc.
$(b)$ Anionic: $Cl^{-}, Br^{-}, I^{-}, NO_{2}^{-}, SCN^{-}$ etc.
$(ii)$ Polydentate ligands: These ligands may be bidentate,tridentate,tetradentate,pentadentate,and hexadentate if the number of donor atoms are $2, 3, 4, 5$ and $6$ respectively.
Examples:
$C_{2}O_{4}^{2-}$ (bidentate),$PO_{4}^{3-}$ (tridentate),$N(CH_{2}CH_{2}NH_{2})_{3}$ (tetradentate),ethylene diamine triacetate ion (pentadentate),and ethylene diamine tetraacetate ion (hexadentate).
293
Medium
Write a note on ambidentate ligands.

Solution

(N/A) Ambidentate ligands are a type of monodentate ligand that has more than one potential donor atom and can coordinate to the metal ion through only one donor atom at a time.
Examples: $NO_{2}^{-}$,$SCN^{-}$,$CN^{-}$,$S_{2}O_{3}^{2-}$ etc.
$(i)$ $NO_{2}^{-}$ (nitrite ion):
- $M \leftarrow NO_{2}$ (nitrito-$N$,coordinating through nitrogen)
- $M \leftarrow ONO$ (nitrito-$O$,coordinating through oxygen)
$(ii)$ $SCN^{-}$ (thiocyanate ion):
- $M \leftarrow SCN$ (thiocyanato-$S$,coordinating through sulphur)
- $M \leftarrow NCS$ (isothiocyanato-$N$,coordinating through nitrogen)
294
Medium
Explain the following term with an example: Bidentate ligands.

Solution

Bidentate ligands are ligands that possess two donor atoms and can form two coordinate bonds with a single metal ion simultaneously.
Examples include:
$1$. Ethane$-1,2-$diamine $(NH_2CH_2CH_2NH_2)$: $A$ neutral bidentate ligand where both nitrogen atoms act as donor sites.
$2$. Oxalate ion $(C_2O_4^{2-})$: An anionic bidentate ligand where two oxygen atoms act as donor sites.
295
Medium
Explain the following term with an example: Tridentate ligands.

Solution

(N/A) Tridentate ligands: These are ligands that possess $3$ donor atoms and form $3$ coordinate bonds with a central metal ion.
Example: Diethylenetriamine $(NH_2CH_2CH_2NHCH_2CH_2NH_2)$ is a common tridentate ligand. It has $3$ nitrogen atoms with lone pairs that can coordinate to the metal ion.
$(a)$ Triaminopropane: $CH_2(NH_2)-CH(NH_2)-CH_2(NH_2)$
$(b)$ Diethylenetriamine: $H_2N-CH_2-CH_2-NH-CH_2-CH_2-NH_2$
296
Medium
Explain the following term with an example: Tetradentate ligands.

Solution

(N/A) Tetradentate ligands: These are ligands that possess four donor atoms and can form four coordinate bonds with a single metal ion simultaneously.
Example: Triethylenetetramine (trien),which has the formula $NH_2-CH_2-CH_2-NH-CH_2-CH_2-NH-CH_2-CH_2-NH_2$. It contains four nitrogen atoms with lone pairs that can act as donor sites.
297
Medium
Explain the following term with an example: Pentadentate ligands.

Solution

(N/A) Pentadentate ligands: These are ligands that possess five donor atoms and form five coordinate bonds with a central metal ion.
Example: Ethylene diamine triacetate $(EDTA^{3-})$. The structure shows five donor sites (three oxygen atoms from carboxylate groups and two nitrogen atoms from amine groups) capable of coordinating with a metal ion.
298
Medium
Explain the following term with an example: Hexadentate ligands.

Solution

(N/A) Hexadentate ligands: These ligands have $six$ donor atoms and form $six$ coordinate bonds with a metal ion.
Example: Ethylenediamine tetraacetate $(EDTA^{4-})$. The structure shows the $six$ donor atoms (two nitrogen atoms and four oxygen atoms) labeled $1$ to $6$.
299
Medium
Give the chemical formulas for the following:
$(i)$ Sodium nitroprusside
$(ii)$ The purple solution formed in the test for sulphur
$(iii)$ Sodium hexacyanoferrate $(II)$
$(iv)$ Iron $(III)$ hexacyanoferrate $(II)$
$(v)$ Ferri-ferrocyanide
$(vi)$ Sodium thiocyanate

Solution

(N/A) The chemical formulas are as follows:
$(i)$ $Na_{2}[Fe(CN)_{5}NO]$
$(ii)$ $[Fe(CN)_{5}NOS]^{4-}$
$(iii)$ $Na_{4}[Fe(CN)_{6}]$
$(iv)$ $Fe_{4}[Fe(CN)_{6}]_{3}$
$(v)$ $Fe_{4}[Fe(CN)_{6}]_{3}$
$(vi)$ $NaSCN$

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