A coordination compound of cobalt contains fi | vedclass

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(C) $1$. The complex contains $1$ $Co$ atom,$5$ $NH_3$ molecules,$1$ $NO_2$ group,and $2$ $Cl$ atoms.$2$. The formation of $2$ moles of $AgCl$ precipi

Vedclass · Accepted Answer

$[Co(NH_3)_5(NO_2)]Cl_2$

Vedclass · Answer

(C) $1$. The complex contains $1$ $Co$ atom,$5$ $NH_3$ molecules,$1$ $NO_2$ group,and $2$ $Cl$ atoms.$2$. The formation of $2$ moles of $AgCl$ precipitate with excess $AgNO_3$ indicates that there are $2$ ionizable $Cl^-$ ions outside the coordination sphere.$3$. The total number of ions produced is $3$ ($1$ complex cation + $2$ $Cl^-$ anions),which matches the given information.$4$. Therefore,the coordination sphere must be $[Co(NH_3)_5(NO_2)]$ and the counter ions are $2$ $Cl^-$.$5$. The formula is $[Co(NH_3)_5(NO_2)]Cl_2$.

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