ChemistryQ1–1 of 1 questions
Page 1 of 1 · Hindi
1
ChemistryEasyMCQGUJCET · 2006
निम्नलिखित में से विलयनों का कौन सा युग्म समान तापमान पर आइसोटोनिक हो सकता है?
A
$0.1 \ M$ यूरिया और $0.1 \ M$ $NaCl$
B
$0.2 \ M$ $BaCl_2$ और $0.2 \ M$ यूरिया
C
$0.1 \ M$ $NaCl$ और $0.1 \ M$ $K_2SO_4$
D
$0.1 \ M$ $Ba(NO_3)_2$ और $0.1 \ M$ $Na_2SO_4$
Solution
(D) यदि दो विलयनों का परासरण दाब $(\pi)$ समान तापमान पर समान हो,तो वे आइसोटोनिक होते हैं।
$\pi = i \times C \times R \times T$,जहाँ $i$ वॉट-हॉफ कारक है और $C$ मोलर सांद्रता है।
विकल्प $D$ के लिए:
$0.1 \ M$ $Ba(NO_3)_2$ के लिए,$i = 3$ $(Ba^{2+} + 2NO_3^-)$,अतः $\pi_1 = 3 \times 0.1 \times R \times T = 0.3 \ RT$.
$0.1 \ M$ $Na_2SO_4$ के लिए,$i = 3$ $(2Na^+ + SO_4^{2-})$,अतः $\pi_2 = 3 \times 0.1 \times R \times T = 0.3 \ RT$.
चूंकि $\pi_1 = \pi_2$,इसलिए विलयन आइसोटोनिक हैं।
$\pi = i \times C \times R \times T$,जहाँ $i$ वॉट-हॉफ कारक है और $C$ मोलर सांद्रता है।
विकल्प $D$ के लिए:
$0.1 \ M$ $Ba(NO_3)_2$ के लिए,$i = 3$ $(Ba^{2+} + 2NO_3^-)$,अतः $\pi_1 = 3 \times 0.1 \times R \times T = 0.3 \ RT$.
$0.1 \ M$ $Na_2SO_4$ के लिए,$i = 3$ $(2Na^+ + SO_4^{2-})$,अतः $\pi_2 = 3 \times 0.1 \times R \times T = 0.3 \ RT$.
चूंकि $\pi_1 = \pi_2$,इसलिए विलयन आइसोटोनिक हैं।
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