જો r,sin theta = 3,r = 4(1 + sin theta ),,,0 | vedclass

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Question

(b) Eliminating $r$, we get 

$\because$  $\sin 	heta = \frac{1}{2},\, - \frac{3}{2}$ (rejected)

$ \Rightarrow $ $	heta = \frac{\pi }

Vedclass · Accepted Answer

$\frac{\pi }{6},\frac{{5\pi }}{6}$

Vedclass · Answer

(b) Eliminating $r$, we get 

$\because$  $\sin 	heta = \frac{1}{2},\, - \frac{3}{2}$ (rejected)

$ \Rightarrow $ $	heta = \frac{\pi }{6},\,\pi - \frac{\pi }{6} = \frac{{5\pi }}{6}$.

જો $r\,\sin \theta = 3,r = 4(1 + \sin \theta ),\,\,0 \le \theta \le 2\pi ,$ તો $\theta = $

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