If $r\,\sin \theta = 3,r = 4(1 + \sin \theta ),\,\,0 \le \theta \le 2\pi ,$ then $\theta = $
If $r\,\sin \theta = 3,r = 4(1 + \sin \theta ),\,\,0 \le \theta \le 2\pi ,$ then $\theta = $
- A
$\frac{\pi }{6},\frac{\pi }{3}$
- B
$\frac{\pi }{6},\frac{{5\pi }}{6}$
- C
$\frac{\pi }{3},\frac{\pi }{4}$
- D
$\frac{\pi }{2},\pi $
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