If sin 3 A =cos left( A -26^{circ}right), whe | vedclass

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Question

We are given that $\sin 3 A =\cos \left( A -26^{\circ}\right)$ ........$(1)$

Since,$\sin 3 A =\cos \left(90^{\circ}-3 A \right),$ we can write $(1)

Vedclass · Accepted Answer

$29$

Vedclass · Answer

We are given that $\sin 3 A =\cos \left( A -26^{\circ}\right)$ ........$(1)$

Since,$\sin 3 A =\cos \left(90^{\circ}-3 A \right),$ we can write $(1)$ as

$\cos \left(90^{\circ}-3 A \right)=\cos \left( A -26^{\circ}\right)$

Since,$90^{\circ}-3 A$ and $A -26^{\circ}$ are both acute angles, therefore,

$90^{\circ}-3 A = A -26^{\circ}$

Which Gives,$A=29^{\circ}$

If $\sin 3 A =\cos \left( A -26^{\circ}\right),$ where $3 A$ is an acute angle, find the value of $A= . . . . ^{\circ}$.

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