Find the radius of the circle in which a central angle of $60^{\circ}$ intercepts an arc of length $37.4 \,cm$ ( use $\pi=\frac{22}{7}$ ).
Find the radius of the circle in which a central angle of $60^{\circ}$ intercepts an arc of length $37.4 \,cm$ ( use $\pi=\frac{22}{7}$ ).
Here $l=37.4\, cm$ and $\theta=60^{\circ}=\frac{60 \pi}{180} radian =\frac{\pi}{3}$
Hence, by $r=\frac{l}{\theta},$ we have
$r=\frac{37.4 \times 3}{\pi}=\frac{37.4 \times 3 \times 7}{22}=35.7 \,cm$
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