Find the value of $\cos \left(-1710^{\circ}\right)$.
Find the value of $\cos \left(-1710^{\circ}\right)$.
We know that values of cos $x$ repeats after an interval of $2 \pi$ or $360^{\circ} .$
Therefore, $\cos \left(-1710^{\circ}\right)=\cos \left(-1710^{\circ}+5 \times 360^{\circ}\right)$
$=\cos \left(-1710^{\circ}+1800^{\circ}\right)=\cos 90^{\circ}=0$
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- [IIT 1966]