Find the value of $\cos \left(-1710^{\circ}\right)$.

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We know that values of cos $x$ repeats after an interval of $2 \pi$ or $360^{\circ} .$

Therefore, $\cos \left(-1710^{\circ}\right)=\cos \left(-1710^{\circ}+5 \times 360^{\circ}\right)$

$=\cos \left(-1710^{\circ}+1800^{\circ}\right)=\cos 90^{\circ}=0$

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