If x = sec theta + tan theta , then x + frac{ | vedclass

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Question

(b) Given that $x = \sec 	heta + 	an 	heta $

$ \Rightarrow \,x + \frac{1}{x} = \sec 	heta + 	an 	heta + \frac{1}{{\sec 	heta + 	an 	heta }

Vedclass · Accepted Answer

$2\sec 	heta $

Vedclass · Answer

(b) Given that $x = \sec 	heta + 	an 	heta $

$ \Rightarrow \,x + \frac{1}{x} = \sec 	heta + 	an 	heta + \frac{1}{{\sec 	heta + 	an 	heta }}$

$ = \sec 	heta + 	an 	heta + \sec 	heta - 	an 	heta = 2\sec 	heta $

If $x = \sec \theta + \tan \theta ,$ then $x + \frac{1}{x} = $

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