Find five rational numbers between $1$ and $2$.
We can approach this problem in at least two ways.
Recall that to find a rational number between $r$ and $s,$ you can add $r$ and $s$ and divide the sum by $2,$ that is $\frac{r+s}{2}$ lies between $r$ and $s .$ So, $\frac{3}{2}$ is a number between $1$ and $2 .$ You can proceed in this manner to find four more rational numbers between $1$ and $2 .$ These four numbers are $\frac{5}{4}, \frac{11}{8}, \frac{13}{8}$ and $\frac{7}{4}$.
Or
The other option is to find all the five rational numbers in one step. since we want five numbers, we write $1$ and $2$ as rational numbers with denominator $5+1$, i.e., $1=\frac{6}{6}$ and $2=\frac{12}{6} .$ Then you can check that $\frac{7}{6}, \frac{8}{6}, \frac{9}{6}, \frac{10}{6}$ and $\frac{11}{6}$ are all rational numbers between $1$ and $2 .$ So, the five numbers are $\frac{7}{6}, \frac{4}{3}, \frac{3}{2}, \frac{5}{3}$ and $\frac{11}{6}$.
Classify the following numbers as rational or irrational :
$(i)$ $\sqrt{23}$
$(ii)$ $\sqrt{225}$
$(iii)$ $0.3796$
$(iv)$ $7.478478 \ldots$
$(v)$ $1.101001000100001 \ldots$
Rationalise the denominators of the following :
$(i)$ $\frac{1}{\sqrt{7}}$
$(ii)$ $\frac{1}{\sqrt{7}-\sqrt{6}}$
$(iii)$ $\frac{1}{\sqrt{5}+\sqrt{2}}$
$(iv)$ $\frac{1}{\sqrt{7}-2}$
Find six rational numbers between $3$ and $4$.
Check whether $7 \sqrt{5}, \,\frac{7}{\sqrt{5}}, \,\sqrt{2}+21, \,\pi-2$ are irrational numbers or not.
Visualize the representation of $5.3 \overline{7}$. on the number line upto $5$ decimal places, that is, up to $5.37777$.