Find five rational numbers between $1$ and $2$.

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We can approach this problem in at least two ways.

Recall that to find a rational number between $r$ and $s,$ you can add $r$ and $s$ and divide the sum by $2,$ that is $\frac{r+s}{2}$ lies between $r$ and $s .$ So, $\frac{3}{2}$ is a number between $1$ and $2 .$ You can proceed in this manner to find four more rational numbers between $1$ and $2 .$ These four numbers are $\frac{5}{4}, \frac{11}{8}, \frac{13}{8}$ and $\frac{7}{4}$.

Or

The other option is to find all the five rational numbers in one step. since we want five numbers, we write $1$ and $2$ as rational numbers with denominator $5+1$, i.e., $1=\frac{6}{6}$ and $2=\frac{12}{6} .$ Then you can check that $\frac{7}{6}, \frac{8}{6}, \frac{9}{6}, \frac{10}{6}$ and $\frac{11}{6}$ are all rational numbers between $1$ and $2 .$ So, the five numbers are $\frac{7}{6}, \frac{4}{3}, \frac{3}{2}, \frac{5}{3}$ and $\frac{11}{6}$.

Similar Questions

Classify the following numbers as rational or irrational :

$(i)$ $\sqrt{23}$

$(ii)$ $\sqrt{225}$

$(iii)$ $0.3796$

$(iv)$ $7.478478 \ldots$

$(v)$ $1.101001000100001 \ldots$

Rationalise the denominators of the following :

$(i)$ $\frac{1}{\sqrt{7}}$

$(ii)$ $\frac{1}{\sqrt{7}-\sqrt{6}}$

$(iii)$ $\frac{1}{\sqrt{5}+\sqrt{2}}$

$(iv)$ $\frac{1}{\sqrt{7}-2}$

Find six rational numbers between $3$ and $4$.

Check whether $7 \sqrt{5}, \,\frac{7}{\sqrt{5}}, \,\sqrt{2}+21, \,\pi-2$ are irrational numbers or not.

Visualize the representation of $5.3 \overline{7}$. on the number line upto $5$ decimal places, that is, up to $5.37777$.