Find six rational numbers between $3$ and $4$.
There are infinite rational numbers in between $3$ and $4$ .
$3$ and $4$ can be represented as $\frac{24}{8}$ and $\frac{32}{8}$ respectively.
Therefore, rational numbers between $3$ and $4$ are
$\frac{25}{8}, \,\frac{26}{8}, \,\frac{27}{8},\, \frac{28}{8}, \,\frac{29}{8}, \,\frac{30}{8}$
Show that $0.2353535 \ldots=0.2 \overline{35}$ can be expressed in the form $\frac{p}{q},$ where $p$ and $q$ are integers and $q \neq 0$.
Classify the following numbers as rational or irrational :
$(i)$ $2-\sqrt{5}$
$(ii)$ $(3+\sqrt{23})-\sqrt{23}$
$(iii)$ $\frac{2 \sqrt{7}}{7 \sqrt{7}}$
$(iv)$ $\frac{1}{\sqrt{2}}$
$(v)$ $2 \pi$
Show that $3.142678$ is a rational number. In other words, express $3.142678$ in the form $\frac {p }{q }$, where $p$ and $q$ are integers and $q \ne 0$.
Visualize the representation of $5.3 \overline{7}$. on the number line upto $5$ decimal places, that is, up to $5.37777$.
Recall, $\pi$ is defined as the ratio of the circumference (say $c$ ) of a circle to its diameter
(say $d$ ). That is, $\pi=\frac{c}{d}$. This seems to contradict the fact that $\pi$ is irrational. How will you resolve this contradiction ?