Contrapositive of the statement:
'If a function $f$ is differentiable at $a$, then it is also continuous at $a$', is
Contrapositive of the statement:
'If a function $f$ is differentiable at $a$, then it is also continuous at $a$', is
- [JEE MAIN 2020]
- A
If a function $f$ is continuous at $a$, then it is not differentiable at $a$.
- B
If a function $f$ is not continuous at $a$, then it is differentiable at $a$.
- C
If a function $f$ is not continuous at $a$, then it is not differentiable at $a$.
- D
If a function $f$ is continuous at $a$, then it is differentiable at $a$.
Similar Questions
Among the statements
$(S1)$: $(p \Rightarrow q) \vee((\sim p) \wedge q)$ is a tautology
$(S2)$: $(q \Rightarrow p) \Rightarrow((\sim p) \wedge q)$ is a contradiction
Among the statements
$(S1)$: $(p \Rightarrow q) \vee((\sim p) \wedge q)$ is a tautology
$(S2)$: $(q \Rightarrow p) \Rightarrow((\sim p) \wedge q)$ is a contradiction
- [JEE MAIN 2023]
Which of the following statement is a tautology?
Which of the following statement is a tautology?
If $(p\; \wedge \sim r) \Rightarrow (q \vee r)$ is false and $q$ and $r$ are both false, then $p$ is
If $(p\; \wedge \sim r) \Rightarrow (q \vee r)$ is false and $q$ and $r$ are both false, then $p$ is
Let $F_{1}(A, B, C)=(A \wedge \sim B) \vee[\sim C \wedge(A \vee B)] \vee \sim A$ and $F _{2}( A , B )=( A \vee B ) \vee( B \rightarrow \sim A )$ be two logical expressions. Then ...... .
Let $F_{1}(A, B, C)=(A \wedge \sim B) \vee[\sim C \wedge(A \vee B)] \vee \sim A$ and $F _{2}( A , B )=( A \vee B ) \vee( B \rightarrow \sim A )$ be two logical expressions. Then ...... .
- [JEE MAIN 2021]
The statement $( p \wedge q ) \Rightarrow( p \wedge r )$ is equivalent to.
The statement $( p \wedge q ) \Rightarrow( p \wedge r )$ is equivalent to.
- [JEE MAIN 2022]