Let $F_{1}(A, B, C)=(A \wedge \sim B) \vee[\sim C \wedge(A \vee B)] \vee \sim A$ and $F _{2}( A , B )=( A \vee B ) \vee( B \rightarrow \sim A )$ be two logical expressions. Then ...... .
$F _{1}$ and $F _{2}$ both are tautologies
$F _{1}$ is a tautology but $F _{2}$ is not a tautology
$F _{1}$ is not tautology but $F _{2}$ is a tautology
Both $F _{1}$ and $F _{2}$ are not tautologies
Negation of the statement $(p \vee r) \Rightarrow(q \vee r)$ is :
Negation of $(p \Rightarrow q) \Rightarrow(q \Rightarrow p)$ is
The contrapositive of the statement "If I reach the station in time, then I will catch the train" is
Let $\Delta, \nabla \in\{\wedge, \vee\}$ be such that $p \nabla q \Rightarrow(( p \nabla$q) $\nabla r$ ) is a tautology. Then (p $\nabla q ) \Delta r$ is logically equivalent to
The expression $ \sim ( \sim p\, \to \,q)$ is logically equivalent to