A liquid is kept in a cylindrical vessel which is being rotated about a vertical axis through the centre of the circular base. If the radius of the vessel is $ r $ and angular velocity of rotation is $\omega $, then the difference in the heights of the liquid at the centre of the vessel and the edge is

  • A

    $\frac{{r\omega }}{{2g}}$

  • B

    $\frac{{{r^2}{\omega ^2}}}{{2g}}$

  • C

    $\sqrt {2gr\omega } $

  • D

    $\frac{{{\omega ^2}}}{{2g{r^2}}}$

Similar Questions

Water is flowing through a channel (lying in a vertical plane) as shown in the figure. Three sections $A, B$ and $C$ are shown. Sections $B$ and $C$ have equal area of cross section. If $P_A, P_B$ and $P_C$ are the pressures at $A, B$ and $C$ respectively then

A fluid is flowing through a horizontal pipe of varying cross-section, with speed $v\;ms^{-1}$ at a point where the pressure is $P$ Pascal. At another point where pressure is $\frac{ P }{2}$ Pascal its speed is $V\;ms^{-1}$. If the density of the fluid is $\rho\, kg\, m ^{-3}$ and the flow is streamline, then $V$ is equal to

  • [JEE MAIN 2020]

A long cylindrical vessel is half filled with a liquid. When the vessel is rotated about its own vertical axis, the liquid rises up near the wall. If the radius of vessel is $5\,cm$ and its rotational speed is $2$ rotations per second, then the difference in the heights between the centre and the sides, in $cm,$ will be

  • [JEE MAIN 2019]

Why free surface of liquid tend to contract their surface ?

Using principle of venturi-meter explain carburetor and spray pump.