$A$ liquid is kept in a cylindrical vessel which is being rotated about a vertical axis through the centre of the circular base. If the radius of the vessel is $r$ and the angular velocity of rotation is $\omega$,then the difference in the heights of the liquid at the centre of the vessel and the edge is

  • A
    $\frac{r\omega}{2g}$
  • B
    $\frac{r^2\omega^2}{2g}$
  • C
    $\sqrt{2gr\omega}$
  • D
    $\frac{\omega^2}{2gr^2}$

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