A fluid is flowing through a horizontal pipe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a horizontal pipe,the height $h$ is constant,so $h_1 = h_2$. According to Bernoulli's equation:$P_1 + \frac{1}{2}\rho v_1^2 = P_2 + \frac{1}{2

Vedclass · Accepted Answer

$\sqrt{\frac{P}{\rho} + v^2}$

Vedclass · Answer

(B) For a horizontal pipe,the height $h$ is constant,so $h_1 = h_2$. According to Bernoulli's equation:$P_1 + \frac{1}{2}\rho v_1^2 = P_2 + \frac{1}{2}\rho v_2^2$Given $P_1 = P$,$v_1 = v$,$P_2 = \frac{P}{2}$,and $v_2 = V$.Substituting these values:$P + \frac{1}{2}\rho v^2 = \frac{P}{2} + \frac{1}{2}\rho V^2$Subtract $\frac{P}{2}$ from both sides:$\frac{P}{2} + \frac{1}{2}\rho v^2 = \frac{1}{2}\rho V^2$Multiply the entire equation by $\frac{2}{\rho}$:$\frac{P}{\rho} + v^2 = V^2$Taking the square root on both sides:$V = \sqrt{\frac{P}{\rho} + v^2}$

Similar Questions

The venturi-meter works on:

$A$ jet plane flies in the air because

Explain why the roof of a building flies off during a stormy wind.

Why does an airplane run a certain length on the runway first before taking off?

Explain blood flow and heart attack with the help of Bernoulli's principle.

Vedclass Test Series

Exam Paper Generator

Online Exam Module