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(B) Using Bernoulli's principle and the equation of continuity:Comparing points $A$ and $B$:From the equation of continuity,$A_A V_A = A_B V_B$.Since

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$P_A < P_B < P_C$

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(B) Using Bernoulli's principle and the equation of continuity:Comparing points $A$ and $B$:From the equation of continuity,$A_A V_A = A_B V_B$.Since $A_A V_B$.Applying Bernoulli's equation between $A$ and $B$ (at the same height): $P_A + \frac{1}{2} \rho V_A^2 = P_B + \frac{1}{2} \rho V_B^2$.Since $V_A > V_B$,we have $\frac{1}{2} \rho V_A^2 > \frac{1}{2} \rho V_B^2$,which implies $P_A Comparing points $B$ and $C$:Since $A_B = A_C$,the velocity of fluid is the same,i.e.,$V_B = V_C$.Applying Bernoulli's equation: $P_B + \frac{1}{2} \rho V_B^2 + \rho g h_B = P_C + \frac{1}{2} \rho V_C^2 + \rho g h_C$.Since $V_B = V_C$,this simplifies to $P_B + \rho g h_B = P_C + \rho g h_C$.Given that $h_B > h_C$,it follows that $P_B Combining $(1)$ and $(2)$,we get $P_A < P_B < P_C$.

Water is flowing through a channel (lying in a vertical plane) as shown in the figure. Three sections $A, B$ and $C$ are shown. Sections $B$ and $C$ have equal area of cross-section. If $P_A, P_B$ and $P_C$ are the pressures at $A, B$ and $C$ respectively,then:

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