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Mix Examples - Acids, Bases and Salts Questions in English

Class 10 Science · Acids, Bases and Salts · Mix Examples - Acids, Bases and Salts

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101
Medium
Write balanced chemical equations for the reaction of dilute $HCl$ with:
$(i)$ $Zn$ metal.
$(ii)$ $Na_{2}CO_{3}$.
$(iii)$ $NaOH$.

Solution

(N/A) $(i)$ The reaction of zinc metal with dilute hydrochloric acid produces zinc chloride and hydrogen gas: $Zn(s) + 2HCl(aq) \rightarrow ZnCl_{2}(aq) + H_{2}(g)$.
$(ii)$ The reaction of sodium carbonate with dilute hydrochloric acid produces sodium chloride,water,and carbon dioxide gas: $Na_{2}CO_{3}(s) + 2HCl(aq) \rightarrow 2NaCl(aq) + H_{2}O(l) + CO_{2}(g)$.
$(iii)$ The reaction of sodium hydroxide (a base) with dilute hydrochloric acid (an acid) is a neutralization reaction producing sodium chloride and water: $NaOH(aq) + HCl(aq) \rightarrow NaCl(aq) + H_{2}O(l)$.
102
Difficult
$(i)$ Name the products obtained in the chlor-alkali process.
$(ii)$ Name the gases liberated at the anode and at the cathode,respectively.
$(iii)$ Name the solution which is used as raw material in this process.

Solution

(N/A) $(i)$ The products obtained in the chlor-alkali process are chlorine gas $(Cl_2)$,hydrogen gas $(H_2)$,and sodium hydroxide $(NaOH)$ solution.
$(ii)$ Chlorine gas $(Cl_2)$ is liberated at the anode,and hydrogen gas $(H_2)$ is liberated at the cathode.
$(iii)$ The solution used as raw material in this process is brine,which is an aqueous solution of sodium chloride $(NaCl)$.
103
Medium
Complete and balance the following chemical equations:
$(a)$ $Ca(OH)_{2} + Cl_{2} \longrightarrow$
$(b)$ $CaSO_{4} \cdot 1/2 H_{2}O + H_{2}O \longrightarrow$
$(c)$ $Na_{2}CO_{3} \cdot 10H_{2}O \xrightarrow{\text{air}} \dots$

Solution

(N/A) $Ca(OH)_{2} + Cl_{2} \longrightarrow CaOCl_{2} + H_{2}O$ (Bleaching powder is formed).
$(b)$ $CaSO_{4} \cdot 1/2 H_{2}O + 1 \frac{1}{2} H_{2}O \longrightarrow CaSO_{4} \cdot 2H_{2}O$ (Gypsum is formed).
$(c)$ $Na_{2}CO_{3} \cdot 10H_{2}O \xrightarrow{\text{air}} Na_{2}CO_{3} \cdot H_{2}O + 9H_{2}O$ (Efflorescence occurs,forming sodium carbonate monohydrate).
104
Medium
$(a)$ Give the chemical names of acids present in:
$(i)$ ants
$(ii)$ lemon
$(iii)$ milk
$(iv)$ tomato

Solution

(N/A) $(i)$ Ants contain formic acid (also known as methanoic acid).
$(ii)$ Lemon contains citric acid.
$(iii)$ Milk contains lactic acid.
$(iv)$ Tomato contains oxalic acid.
105
Medium
Write the chemical names of two salts belonging to the sodium family.

Solution

(N/A) $(i)$ Sodium carbonate $(Na_{2}CO_{3})$
(ii) Sodium sulphate $(Na_{2}SO_{4})$
106
Medium
Explain why:
$(a)$ the colour of copper sulphate crystals changes on heating?
$(b)$ baking soda acts as an antacid?
$(c)$ an acid should be added to water while diluting?

Solution

(N/A) Copper sulphate pentahydrate $(CuSO_4 \cdot 5H_2O)$ crystals are blue due to the presence of $5$ molecules of water of crystallisation. On heating, they lose these water molecules and become anhydrous copper sulphate $(CuSO_4)$, which is white in colour.
$(b)$ Baking soda $(NaHCO_3)$ is mildly alkaline in nature. When taken, it reacts with the excess hydrochloric acid $(HCl)$ produced in the stomach, neutralising it and providing relief from acidity.
$(c)$ The process of diluting a concentrated acid is highly exothermic. If water is added to a concentrated acid, the large amount of heat generated can cause the mixture to splash out, potentially causing severe acid burns. Therefore, acid is always added to water slowly with constant stirring.
107
Medium
$(a)$ What will you observe when dilute hydrochloric acid is added to a small amount of copper oxide in a beaker?
$(b)$ Aqueous solution of $HCl$ shows acidic character. But the aqueous solution of glucose fails to do so. Why?

Solution

(N/A) The colour of the solution becomes blue-green and the copper oxide dissolves. The chemical reaction is: $CuO + 2HCl \rightarrow CuCl_2 + H_2O$.
$(b)$ Aqueous solution of $HCl$ dissociates to produce $H^+$ ions,which are responsible for its acidic character. However,glucose $(C_6H_{12}O_6)$ is a covalent compound that does not dissociate into ions in water; therefore,it does not produce $H^+$ ions and fails to show acidic character.
108
Easy
$(a)$ Why should curd and sour substances not be kept in brass and copper vessels?

Solution

(N/A) Curd and other sour substances contain acids.
These acids react with the metal (copper) present in brass and copper vessels.
This chemical reaction leads to the formation of metallic salts (compounds) which are toxic or poisonous in nature.
Consuming food stored in such vessels can cause food poisoning.
109
Medium
Write the balanced chemical equations for the following reactions:
$(a)$ Chlorine is passed over dry slaked lime.
$(b)$ Sodium bicarbonate reacts with dilute hydrochloric acid.
$(c)$ Sodium bicarbonate is heated.

Solution

(N/A) When chlorine is passed over dry slaked lime $(Ca(OH)_2)$,it forms bleaching powder $(CaOCl_2)$ and water $(H_2O)$. The balanced equation is: $Ca(OH)_2 + Cl_2 \rightarrow CaOCl_2 + H_2O$
$(b)$ When sodium bicarbonate $(NaHCO_3)$ reacts with dilute hydrochloric acid $(HCl)$,it produces sodium chloride $(NaCl)$,water $(H_2O)$,and carbon dioxide $(CO_2)$. The balanced equation is: $NaHCO_3 + HCl \rightarrow NaCl + H_2O + CO_2$
$(c)$ When sodium bicarbonate $(NaHCO_3)$ is heated,it undergoes thermal decomposition to form sodium carbonate $(Na_2CO_3)$,water $(H_2O)$,and carbon dioxide $(CO_2)$. The balanced equation is: $2NaHCO_3 \xrightarrow{\Delta} Na_2CO_3 + H_2O + CO_2$
110
Medium
$(a)$ What is a universal indicator?
$(b)$ Write the chemical equation involved in the preparation of sodium hydroxide. Name the process.

Solution

(N/A) universal indicator is a mixture of several indicators that exhibits different colours at different concentrations of hydrogen ions in a solution,allowing for the determination of the $pH$ value.
$(b)$ The process is known as the Chlor-alkali process. The chemical equation is: $2NaCl(aq) + 2H_2O(l) \rightarrow 2NaOH(aq) + Cl_2(g) + H_2(g)$.
111
Medium
$(a)$ Write the chemical formula of hydrated copper sulphate and anhydrous copper sulphate. Giving an activity,illustrate how these two are interconvertible.
$(b)$ Write the chemical names and formulae of Plaster of Paris and gypsum.

Solution

(N/A) The chemical formula of hydrated copper sulphate is $CuSO_4 \cdot 5H_2O$ (blue vitriol),and anhydrous copper sulphate is $CuSO_4$ (white).
Activity: Take some copper sulphate crystals in a dry boiling tube and heat them. The blue colour of the crystals disappears,and the substance becomes white due to the loss of water of crystallisation. If we add a few drops of water to this anhydrous copper sulphate,the blue colour is restored.
$(b)$ Plaster of Paris: Calcium sulphate hemihydrate,$CaSO_4 \cdot \frac{1}{2}H_2O$.
Gypsum: Calcium sulphate dihydrate,$CaSO_4 \cdot 2H_2O$.
112
Medium
Write balanced chemical equations for the following:
$(i)$ Bleaching powder is kept open in air.
$(ii)$ Blue crystals of copper sulphate are heated.
$(iii)$ Chlorine gas is passed through dry slaked lime.

Solution

(N/A) $(i) \text{ } CaOCl_2(s) + CO_2(g) \to CaCO_3(s) + Cl_2(g)$
$(ii) \text{ } CuSO_4 \cdot 5H_2O(s) \xrightarrow{\text{Heat}} CuSO_4(s) + 5H_2O(g)$
$(iii) \text{ } Ca(OH)_2(s) + Cl_2(g) \to CaOCl_2(s) + H_2O(l)$
113
Medium
Write balanced chemical equations for the following:
$(i)$ Carbon dioxide gas is passed through lime water.
$(ii)$ $NaOH$ solution is heated with zinc granules.

Solution

(N/A) $(i)$ $Ca(OH)_2(aq) + CO_2(g) \to CaCO_3(s) + H_2O(l)$
(Lime water turns milky due to the formation of insoluble calcium carbonate.)
$(ii)$ $2NaOH(aq) + Zn(s) \xrightarrow{\text{Heat}} Na_2ZnO_2(aq) + H_2(g)$
(Sodium zincate is formed along with the evolution of hydrogen gas.)
114
Difficult
Equal lengths of magnesium ribbon are taken in two test tubes $A$ and $B$. $H_{2}SO_{4}$ is added to test tube $A$ and $H_{2}CO_{3}$ in test tube $B$ in equal amounts.
$(a)$ Identify the test tube showing vigorous reaction.
$(b)$ Give reason to support your answer.
$(c)$ Name the gas liberated in both the test tubes. How will you prove its liberation?

Solution

(A) Vigorous reaction will be seen in test tube $A$.
$(b)$ This is because $H_{2}SO_{4}$ is a strong acid,whereas $H_{2}CO_{3}$ is a weak acid.
$(c)$ $(i)$ Hydrogen gas $(H_{2})$ is liberated in both test tubes.
$(ii)$ When a burning candle is brought near the evolving gas,it burns with a 'pop' sound. This confirms the presence of hydrogen gas.
115
Difficult
Equal lengths of magnesium ribbon are taken in two test tubes $A$ and $B$. $H_{2}SO_{4}$ is added to test tube $A$ and $H_{2}CO_{3}$ is added to test tube $B$ in equal amounts.
$(a)$ Write chemical equations for both the reactions.
$(b)$ Out of the two acids taken above,which one will have a lower $pH$ value and lower $H^{+}$ concentration,respectively?

Solution

(B) The chemical equations for the reactions are:
$Mg(s) + H_{2}SO_{4}(aq) \rightarrow MgSO_{4}(aq) + H_{2}(g)$
$Mg(s) + H_{2}CO_{3}(aq) \rightarrow MgCO_{3}(s) + H_{2}(g)$
$(b)$ $H_{2}SO_{4}$ is a strong acid,while $H_{2}CO_{3}$ is a weak acid.
Therefore,$H_{2}SO_{4}$ will have a lower $pH$ value because it dissociates completely to provide a higher concentration of $H^{+}$ ions.
Conversely,$H_{2}CO_{3}$ will have a lower $H^{+}$ concentration because it is a weak acid and dissociates only partially.
116
Medium
How do metal carbonates and metal hydrogen carbonates react with acids? Give their chemical equations. Name the gas evolved during the reaction. What will happen when this gas is passed through lime water?

Solution

(N/A) Metal carbonates and metal hydrogen carbonates react with acids to produce the corresponding salt,carbon dioxide,and water.
$(b)$ Chemical equations:
$(i)$ Metal carbonate: $Na_{2}CO_{3}(s) + 2HCl(aq) \rightarrow 2NaCl(aq) + H_{2}O(l) + CO_{2}(g)$
$(ii)$ Metal hydrogen carbonate: $NaHCO_{3}(s) + HCl(aq) \rightarrow NaCl(aq) + H_{2}O(l) + CO_{2}(g)$
$(c)$ The gas evolved during the reaction is carbon dioxide $(CO_{2})$.
$(d)$ When carbon dioxide gas is passed through lime water $(Ca(OH)_{2})$,it turns milky due to the formation of white precipitate of calcium carbonate $(CaCO_{3})$.
117
Medium
Write the chemical equations for the reactions of zinc granules with:
$(a)$ Sulphuric acid
$(b)$ Hydrochloric acid
$(c)$ Aluminium chloride
$(d)$ Sodium hydroxide
$(e)$ Nitric acid

Solution

(N/A) $Zn(s) + H_{2}SO_{4}(aq) \rightarrow ZnSO_{4}(aq) + H_{2}(g)$
$(b)$ $Zn(s) + 2HCl(aq) \rightarrow ZnCl_{2}(aq) + H_{2}(g)$
$(c)$ $3Zn(s) + 2AlCl_{3}(aq) \rightarrow 3ZnCl_{2}(aq) + 2Al(s)$ (Zinc is more reactive than Aluminium,so it displaces it)
$(d)$ $Zn(s) + 2NaOH(aq) \rightarrow Na_{2}ZnO_{2}(aq) + H_{2}(g)$ (Formation of Sodium zincate)
$(e)$ $4Zn(s) + 10HNO_{3}(dilute) \rightarrow 4Zn(NO_{3})_{2}(aq) + NH_{4}NO_{3}(aq) + 3H_{2}O(l)$
118
Difficult
The metal salt $A$ is blue in colour. When salt $A$ is heated strongly over a burner,a substance $B$ present in it is eliminated and a white powder $C$ is left behind. When a few drops of a liquid $D$ are added to powder $C$,it becomes blue again.
$(a)$ Identify $A, B, C, D$.
$(b)$ Write the chemical equations involved.
$(c)$ Give an example of a salt which also shows the above property.

Solution

(A) : Hydrated copper sulphate $(CuSO_4 \cdot 5H_2O)$
$B$: Water of crystallisation $(H_2O)$
$C$: Anhydrous copper sulphate $(CuSO_4)$
$D$: Water $(H_2O)$
$(b)$ The chemical equations are:
$CuSO_4 \cdot 5H_2O (s) \xrightarrow{\text{Heat}} CuSO_4 (s) + 5H_2O (g)$
(Blue) (White)
$CuSO_4 (s) + 5H_2O (l) \rightarrow CuSO_4 \cdot 5H_2O (s)$
(White) (Blue)
$(c)$ Another salt that shows this property is Ferrous sulphate $(FeSO_4 \cdot 7H_2O)$,which is green in colour and turns white upon heating due to the loss of water of crystallisation.
119
Medium
$(a)$ Write the chemical name and chemical formula of washing soda.
$(b)$ How is it obtained from sodium chloride? Give equations of the reactions.
$(c)$ Why is it called a basic salt? Give any one of its uses.

Solution

(N/A) Chemical name: Sodium carbonate decahydrate.
Formula: $Na_{2}CO_{3} \cdot 10H_{2}O$
$(b)$ It is obtained via the Solvay process:
$NaCl + H_{2}O + CO_{2} + NH_{3} \rightarrow NH_{4}Cl + NaHCO_{3}$
$2NaHCO_{3} \xrightarrow{\Delta} Na_{2}CO_{3} + CO_{2} \uparrow + H_{2}O$
$Na_{2}CO_{3} + 10H_{2}O \rightarrow Na_{2}CO_{3} \cdot 10H_{2}O$
$(c)$ It is called a basic salt because it is a salt of a strong base $(NaOH)$ and a weak acid $(H_{2}CO_{3})$,which makes its aqueous solution alkaline.
Use: It is used for removing permanent hardness of water.
120
Medium
$(a)$ Identify the acid and the base whose combination forms the common salt that you use in your food. Write its formula and chemical name of this salt. Name the source from where it is obtained.
$(b)$ What is rock salt? Mention its colour and the reason due to which it has this colour.
$(c)$ What happens when electricity is passed through brine? Write the chemical equation for it.

Solution

(N/A) The common salt used in food is sodium chloride $(NaCl)$. It is formed by the combination of hydrochloric acid $(HCl)$ and sodium hydroxide $(NaOH)$. The primary source of common salt is seawater (ocean water).
$(b)$ Rock salt refers to large deposits of solid salt found in several parts of the world. It is often brown in colour due to the presence of impurities.
$(c)$ When electricity is passed through an aqueous solution of sodium chloride (brine),it decomposes to form sodium hydroxide,chlorine gas,and hydrogen gas. This process is known as the chlor-alkali process. The chemical equation is: $2NaCl(aq) + 2H_2O(l) \xrightarrow{\text{Electricity}} 2NaOH(aq) + Cl_2(g) + H_2(g)$.
121
Medium
$(a)$ Tooth enamel is one of the hardest substances in our body. Explain the changes in $pH$ of the mouth that indicate tooth decay. How does toothpaste help in preventing it?
$(b)$ What is the nature of the salt if the $pH$ of its solution is greater than $7$? Name the acid and base that would be used to prepare the following salts:
$(i)$ Potassium sulphate.
$(ii)$ Ammonium chloride.

Solution

(N/A) Tooth decay starts when the $pH$ of the mouth falls below $5.5$. This occurs when bacteria present in the mouth produce acids by degrading sugar and food particles remaining in the mouth after eating. Using toothpaste,which is generally basic,helps neutralize the excess acid and prevents tooth decay.
$(b)$ If the $pH$ of a salt solution is greater than $7$,the nature of the salt is basic.
$(i)$ For Potassium sulphate $(K_2SO_4)$: Base is $KOH$ (Potassium hydroxide) and Acid is $H_2SO_4$ (Sulphuric acid).
$(ii)$ For Ammonium chloride $(NH_4Cl)$: Base is $NH_4OH$ (Ammonium hydroxide) and Acid is $HCl$ (Hydrochloric acid).
122
Medium
$(a)$ Study the following chemical equation:
$CaSO_4 \cdot 2H_2O \xrightarrow{373K} CaSO_4 \cdot \frac{1}{2}H_2O + \frac{3}{2}H_2O$
Name the reactant and the product. State one use of the product.

Solution

(N/A) Reactant: $CaSO_4 \cdot 2H_2O$ is known as Gypsum.
Product: $CaSO_4 \cdot \frac{1}{2}H_2O$ is known as Plaster of Paris $(POP)$.
Use: It is widely used by doctors as plaster for supporting fractured bones in the right position or for making toys,materials for decoration,and surfaces for smooth finishing.
123
Medium
$(a)$ State in tabular form the name of the acid and base from which the following salts are formed. Also,mention the nature of the salt,whether it is acidic or basic?
$(i)$ Sodium acetate.
$(ii)$ Ammonium sulphate.

Solution

(N/A) The nature of a salt depends on the strength of the acid and base from which it is formed. $A$ salt of a strong base and a weak acid is basic,while a salt of a strong acid and a weak base is acidic.
Salt Acid Base Nature
$(i)$ Sodium acetate Acetic acid $(CH_3COOH)$ Sodium hydroxide $(NaOH)$ Basic
$(ii)$ Ammonium sulphate Sulphuric acid $(H_2SO_4)$ Ammonium hydroxide $(NH_4OH)$ Acidic
124
Medium
$(a)$ $A$ salt is produced by the reaction between an acid and a base. Identify the acid and the base from which the following salts have been formed:
$(i)$ $Na_{2}SO_{4}$
$(ii)$ $NH_{4}Cl$
$(iii)$ $KNO_{3}$
$(iv)$ $NaCl$

Solution

$A$ salt is formed by the neutralization reaction between an acid and a base. The cation of the salt comes from the base,and the anion comes from the acid.
Salt Acid and Base
$(i)$ $Na_{2}SO_{4}$ Acid: $H_{2}SO_{4}$,Base: $NaOH$
$(ii)$ $NH_{4}Cl$ Acid: $HCl$,Base: $NH_{4}OH$
$(iii)$ $KNO_{3}$ Acid: $HNO_{3}$,Base: $KOH$
$(iv)$ $NaCl$ Acid: $HCl$,Base: $NaOH$
125
MediumMCQ
Which of the following salts has a $pH$ less than $7$? Why?
A
$NaCl$
B
$NH_4Cl$
C
$Na_2CO_3$
D
$CH_3COONa$

Solution

(B) The salt $NH_4Cl$ has a $pH$ less than $7$.
This is because $NH_4Cl$ is a salt formed from a strong acid $(HCl)$ and a weak base $(NH_4OH)$.
Strong acids ionize completely in water,while weak bases do not ionize completely.
Consequently,the resulting solution becomes acidic due to the presence of excess hydrogen ions $(H^+)$,leading to a $pH$ value of less than $7$.
126
Difficult
$A$ metal compound $'A'$ reacts with dilute sulphuric acid to produce a gas which extinguishes a burning candle. Identify the compound $'A'$ and the gas produced. Write a balanced chemical equation for the reaction if one of the compounds formed in the reaction is sodium sulphate.

Solution

(A) Compound $'A'$ is sodium carbonate $(Na_{2}CO_{3})$ and the gas evolved is carbon dioxide $(CO_{2})$.
The chemical reaction is as follows:
$Na_{2}CO_{3}(s) + H_{2}SO_{4}(aq) \to Na_{2}SO_{4}(aq) + CO_{2}(g) + H_{2}O(l)$
In this reaction,sodium carbonate reacts with dilute sulphuric acid to form sodium sulphate,water,and carbon dioxide gas. Carbon dioxide does not support combustion,which is why it extinguishes a burning candle.
127
Difficult
You have two solutions $A$ and $B$. The $pH$ of solution $A$ is $6$ and the $pH$ of solution $B$ is $8$. Which solution has more hydrogen ion concentration? Which one of these is acidic and which one is basic?

Solution

(A) $(i)$ The lower the $pH$ of the solution,the higher the hydrogen ion concentration. Thus,solution $A$ $(pH = 6)$ has a higher hydrogen ion concentration compared to solution $B$ $(pH = 8)$.
$(ii)$ Solution $A$ is acidic because its $pH < 7$,while solution $B$ is basic because its $pH > 7$.
128
Medium
Give suitable reasons for the following statements: An aqueous solution of sodium chloride is neutral,but an aqueous solution of sodium is basic.

Solution

(N/A) An aqueous solution of sodium chloride $(NaCl)$ is neutral because it is a salt formed from the neutralization reaction between a strong acid $(HCl)$ and a strong base $(NaOH)$. Since both components are strong,the resulting salt solution does not undergo hydrolysis to change the $pH$ of the water,remaining at $pH = 7$.
An aqueous solution of sodium $(Na)$ is basic because sodium is a highly reactive alkali metal. When it reacts with water,it produces sodium hydroxide $(NaOH)$,which is a strong base,and hydrogen gas $(H_2)$. The presence of $NaOH$ in the solution increases the concentration of hydroxide ions $(OH^-)$,making the solution basic.
The chemical reaction is: $2Na(s) + 2H_2O(l) \longrightarrow 2NaOH(aq) + H_2(g)$
129
Medium
State the chemical property in each of the following cases,on which the following uses of baking soda are based:
$(a)$ Applied on an ant stung area.
$(b)$ As a constituent of baking powder.
$(c)$ In soda-acid fire extinguisher.

Solution

(N/A) Baking soda is basic in nature,so it neutralizes the acidic effect of the formic acid injected by an ant sting.
$(b)$ Baking soda $(NaHCO_{3})$ reacts with tartaric acid present in baking powder upon heating or mixing with water to release $CO_{2}$ gas. This $CO_{2}$ gas gets trapped in the dough,making the bread or cake soft and spongy.
$(c)$ Baking soda reacts with an acid (like $H_{2}SO_{4}$) to produce a large volume of $CO_{2}$ gas,which cuts off the oxygen supply and extinguishes the fire.
130
Medium
Differentiate between strong electrolytes and weak electrolytes. Mention two examples each.

Solution

(N/A) Strong electrolytes are substances that dissociate completely into ions when dissolved in an aqueous solution. They conduct electricity very well due to the high concentration of ions. Examples: $NaCl$ (Sodium chloride) and $HCl$ (Hydrochloric acid).
Weak electrolytes are substances that dissociate only partially into ions in an aqueous solution. They conduct electricity poorly because only a small fraction of the molecules exist as ions. Examples: $CH_{3}COOH$ (Acetic acid) and $NH_{4}OH$ (Ammonium hydroxide).
131
EasyMCQ
When soap is scrubbed on a stain of curry on a white cloth,why does it become reddish-brown,and why does it turn yellow again when the cloth is washed with plenty of water?
A
Soap reacts with turmeric to form a new compound.
B
Turmeric acts as a natural acid-base indicator.
C
The soap is acidic in nature.
D
The water neutralizes the soap.

Solution

(B) Curry contains turmeric,which acts as a natural acid-base indicator.
Soap is basic in nature.
When soap is applied to the turmeric stain,the basic medium causes the turmeric to turn reddish-brown.
When the cloth is washed with plenty of water,the soap is rinsed away,removing the basic medium.
As the medium is no longer basic,the turmeric returns to its original yellow color.
132
Medium
Name the gas which is liberated when an acid reacts with a metal. Illustrate with an example. How will you test the presence of this gas?

Solution

(N/A) When an acid reacts with a metal,$Hydrogen$ gas is liberated.
Example: When $Zinc$ granules react with dilute $Hydrochloric$ acid $(HCl)$,$Zinc$ chloride $(ZnCl_{2})$ and $Hydrogen$ gas $(H_{2})$ are produced.
$Zn(s) + 2HCl(aq) \longrightarrow ZnCl_{2}(aq) + H_{2}(g)$
Test for $Hydrogen$ gas: Bring a burning candle or a matchstick near the mouth of the test tube containing the gas. The gas burns with a characteristic '$pop$' sound,which confirms the presence of $Hydrogen$ gas.
133
Medium
Write the chemical formula of bleaching powder. How is bleaching powder prepared? For what purpose is it used in drinking water?

Solution

(N/A) The chemical formula of bleaching powder is $CaOCl_{2}$.
Bleaching powder is prepared by the action of chlorine gas on dry slaked lime $[Ca(OH)_{2}]$. The chemical equation for the reaction is:
$Ca(OH)_{2} + Cl_{2} \longrightarrow CaOCl_{2} + H_{2}O$
In drinking water,it is used as a disinfectant to kill germs and bacteria,making the water safe for consumption.
134
Medium
Explain the action of dilute hydrochloric acid on the following with chemical equations:
$(a)$ Magnesium ribbon
$(b)$ Sodium hydroxide
$(c)$ Crushed egg shells

Solution

(N/A) Dilute hydrochloric acid reacts with magnesium to form magnesium chloride and hydrogen gas is liberated.
$Mg(s) + 2HCl(aq) \longrightarrow MgCl_2(aq) + H_2(g)$
$(b)$ The reaction between dilute hydrochloric acid and sodium hydroxide is a neutralization reaction,forming sodium chloride salt and water.
$NaOH(aq) + HCl(aq) \longrightarrow NaCl(aq) + H_2O(l)$
$(c)$ Egg shells are primarily composed of calcium carbonate $(CaCO_3)$. Dilute hydrochloric acid reacts with calcium carbonate to produce calcium chloride,carbon dioxide gas,and water.
$CaCO_3(s) + 2HCl(aq) \longrightarrow CaCl_2(aq) + CO_2(g) + H_2O(l)$
135
Medium
$(a)$ $A$ solution of a substance $'X'$ is used for testing carbon dioxide. Write the equation of the reaction of $'X'$ with carbon dioxide.
$(b)$ How is $'X'$ obtained? Write the chemical equation.

Solution

(N/A) The substance $'X'$ is lime water,which is calcium hydroxide $\left[ Ca(OH)_{2} \right]$.
The chemical equation for the reaction of lime water with carbon dioxide is:
$Ca(OH)_{2}(aq) + CO_{2}(g) \longrightarrow CaCO_{3}(s) + H_{2}O(l)$
$(b)$ $'X'$ (calcium hydroxide) is obtained by the reaction of quick lime (calcium oxide) with water (slaking of lime).
The chemical equation is:
$CaO(s) + H_{2}O(l) \longrightarrow Ca(OH)_{2}(aq)$
136
Medium
Tap water conducts electricity,whereas distilled water does not. Why?

Solution

(N/A) Tap water contains various dissolved salts that dissociate into ions when electricity is passed through it. These ions act as charge carriers,allowing the flow of electricity. In contrast,distilled water is pure and does not contain any dissolved salts or ions,making it an insulator that does not conduct electricity.
137
Easy
Dry hydrogen chloride gas does not turn blue litmus red whereas hydrochloric acid does. Give one reason.

Solution

(N/A) Dry hydrogen chloride gas does not contain $H^{+}$ ions. Acids exhibit acidic properties only in the presence of water because they dissociate to produce hydrogen ions $H^{+}(aq)$. Since dry $HCl$ gas lacks water,it cannot release $H^{+}$ ions,and therefore,it does not show acidic behavior or change the color of blue litmus paper.
138
Medium
Give reasons for the following:
$(i)$ Why is it recommended that acid should be added to water and not water to acid?
$(ii)$ Why do compounds like alcohol and glucose not show acidic behavior even though they contain hydrogen?

Solution

(N/A) $(i)$ The process of diluting a concentrated acid is a highly exothermic reaction. If water is added to a concentrated acid,the large amount of heat generated can cause the mixture to splash out,potentially leading to severe acid burns.
$(ii)$ Compounds like alcohol and glucose contain hydrogen,but they do not dissociate to release hydrogen ions $(H^+)$ when dissolved in water. Since acidic behavior is defined by the presence of $H^+$ ions in an aqueous solution,these compounds do not exhibit acidic properties.
139
Medium
Answer the following:
$(i)$ Why is Plaster of Paris written as $CaSO_{4} \cdot 1/2 H_{2}O$? How is it possible to have half a water molecule attached to $CaSO_{4}$?
$(ii)$ Why is sodium hydrogen carbonate an essential ingredient in antacids?
$(iii)$ When electricity is passed through an aqueous solution of sodium chloride,three products are obtained. Why is the process called chlor-alkali?

Solution

(N/A) $(i)$ Plaster of Paris is written as $CaSO_{4} \cdot 1/2 H_{2}O$ because two formula units of $CaSO_{4}$ share one molecule of water of crystallization. This means that one water molecule is associated with two $CaSO_{4}$ units,effectively resulting in $1/2 H_{2}O$ per unit.
$(ii)$ Sodium hydrogen carbonate $(NaHCO_{3})$ is a mild,non-corrosive basic salt. It acts as an antacid by neutralizing the excess hydrochloric acid $(HCl)$ produced in the stomach,thereby providing relief from acidity.
$(iii)$ The electrolysis of an aqueous solution of sodium chloride (brine) produces chlorine gas $(Cl_{2})$ at the anode and sodium hydroxide $(NaOH)$,which is an alkali,at the cathode. Due to the formation of these two specific products,the process is termed the chlor-alkali process.
140
MediumMCQ
With the increase in the concentration of hydrogen ions,the $pH$ value will
A
Increase
B
Remain fluctuating
C
Remain constant
D
Decrease

Solution

(D) The $pH$ value is defined as the negative logarithm of the hydrogen ion concentration,represented by the formula: $pH = -\log[H^+]$.
As the concentration of hydrogen ions $[H^+]$ increases,the value of $\log[H^+]$ also increases.
Since the $pH$ is the negative of this value,an increase in $[H^+]$ leads to a decrease in the $pH$ value.
Therefore,a higher concentration of hydrogen ions indicates a more acidic solution,which corresponds to a lower $pH$ value.
141
MediumMCQ
The colour of $pH$ paper strip at the $pH$ values of $1, 7,$ and $14$ will be:
A
Red,green and blue
B
Green,red and blue
C
Blue,green and red
D
Green,blue and red

Solution

(A) The $pH$ scale is used to measure the acidity or alkalinity of a solution.
- $A$ $pH$ value of $1$ indicates a strong acid,which turns the $pH$ paper red.
- $A$ $pH$ value of $7$ indicates a neutral solution,which turns the $pH$ paper green.
- $A$ $pH$ value of $14$ indicates a strong base,which turns the $pH$ paper blue.
Therefore,the colours corresponding to $pH$ values $1, 7,$ and $14$ are red,green,and blue,respectively.
142
EasyMCQ
Which of the following is a strong acid?
A
Ethanoic acid
B
Sulphuric acid
C
Tartaric acid
D
Citric acid

Solution

(B) strong acid is an acid that completely dissociates into its ions in an aqueous solution.
$H_2SO_4$ (Sulphuric acid) is a mineral acid and is considered a strong acid because it ionizes completely in water.
Ethanoic acid $(CH_3COOH)$,Tartaric acid,and Citric acid are organic acids,which are generally weak acids as they only partially dissociate in water.
143
EasyMCQ
Which of the following is a weak acid?
A
Sulphuric acid
B
Nitric acid
C
Ethanoic acid
D
Hydrochloric acid

Solution

(C) weak acid is an acid that partially dissociates into its ions in an aqueous solution.
$H_2SO_4$ (Sulphuric acid),$HNO_3$ (Nitric acid),and $HCl$ (Hydrochloric acid) are strong acids because they dissociate completely in water.
$CH_3COOH$ (Ethanoic acid or Acetic acid) is a weak acid because it only partially dissociates in water,resulting in a lower concentration of $H^+$ ions.
144
EasyMCQ
Which of the following is a mineral acid?
A
Citric acid
B
Lactic acid
C
Oxalic acid
D
Nitric acid

Solution

(D) Mineral acids are acids derived from inorganic compounds,typically non-living sources.
Citric acid,Lactic acid,and Oxalic acid are organic acids found in plants and animals.
Nitric acid $(HNO_3)$ is a mineral acid prepared from inorganic minerals.
Therefore,the correct option is $D$.
145
EasyMCQ
Which of the following contains oxalic acid?
A
Tomato
B
Orange
C
Sour milk
D
Tamarind

Solution

(A) Oxalic acid is a dicarboxylic acid found in various plants.
Among the given options,tomato contains oxalic acid.
Orange contains citric acid,sour milk contains lactic acid,and tamarind contains tartaric acid.
146
EasyMCQ
The compound which is used in glass, soap, and paper industries is:
A
Baking soda
B
Washing soda
C
Lime water
D
Bleaching powder

Solution

(B) The chemical compound used in glass, soap, and paper industries is sodium carbonate, commonly known as washing soda $(Na_2CO_3 \cdot 10H_2O)$.
It is widely used in the glass, soap, and paper industries because it acts as a strong base and a cleaning agent.
Baking soda $(NaHCO_3)$ is primarily used for cooking and as an antacid.
Lime water $(Ca(OH)_2)$ is used in the laboratory and for whitewashing.
Bleaching powder $(CaOCl_2)$ is used for disinfecting water and bleaching fabrics.
147
EasyMCQ
The chemical formulas for Gypsum and Plaster of Paris are,respectively:
A
$CaSO_4 \cdot 2H_2O$ and $CaSO_4 \cdot 1\frac{1}{2}H_2O$
B
$CaSO_4$ and $CaSO_4 \cdot \frac{1}{2}H_2O$
C
$CaSO_4 \cdot 2H_2O$ and $CaSO_4 \cdot \frac{1}{2}H_2O$
D
$CaSO_4 \cdot 2H_2O$ and $CaSO_4 \cdot 3H_2O$

Solution

(C) Gypsum is a naturally occurring mineral with the chemical formula $CaSO_4 \cdot 2H_2O$ (calcium sulfate dihydrate).
Plaster of Paris is produced by heating gypsum at $373 \ K$ $(100^{\circ}C)$,which causes it to lose water molecules and become calcium sulfate hemihydrate,with the formula $CaSO_4 \cdot \frac{1}{2}H_2O$.
148
EasyMCQ
The compound which is used as an oxidising agent in many chemical industries is:
A
Quicklime
B
Washing powder
C
Baking powder
D
Bleaching powder

Solution

(D) Bleaching powder,chemically known as calcium oxychloride $(CaOCl_2)$,is widely used as an oxidising agent in many chemical industries.
It acts as a strong oxidising agent because it releases nascent oxygen when it reacts with water or dilute acids.
This property makes it useful for bleaching cotton and linen in the textile industry,bleaching wood pulp in paper factories,and for disinfecting drinking water.
149
EasyMCQ
The compound which is used for removing permanent hardness of water is:
A
$Na_{2}CO_{3} \cdot 10H_{2}O$
B
$CuSO_{4} \cdot 5H_{2}O$
C
$Na_{2}CO_{3}$
D
$NaHCO_{3}$

Solution

(C) Permanent hardness of water is caused by the presence of dissolved chlorides and sulfates of calcium and magnesium.
Sodium carbonate $(Na_{2}CO_{3})$,commonly known as washing soda,is used to remove this permanent hardness.
It reacts with the calcium and magnesium ions to form insoluble carbonates,which can then be filtered out.
The chemical reaction is: $Ca^{2+} + CO_{3}^{2-} \rightarrow CaCO_{3} \downarrow$ and $Mg^{2+} + CO_{3}^{2-} \rightarrow MgCO_{3} \downarrow$.
Therefore,$Na_{2}CO_{3}$ is the correct compound.
150
MediumMCQ
Common salt, besides being used in the kitchen, can also be used as the raw material for making:
$(i)$ Washing soda
$(ii)$ Bleaching powder
$(iii)$ Baking soda
$(iv)$ Slaked lime
A
$(i)$ and $(ii)$
B
$(i), (ii)$ and $(iii)$
C
$(i), (ii)$ and $(iv)$
D
$(i), (iii)$ and $(iv)$

Solution

(B) Common salt $(NaCl)$ is a crucial raw material for various chemicals used in daily life and industry.
$1$. Washing soda $(Na_2CO_3 \cdot 10H_2O)$ is produced from $NaCl$ via the Solvay process.
$2$. Bleaching powder $(CaOCl_2)$ is produced by the action of chlorine gas (obtained from the electrolysis of brine, i.e., $NaCl$ solution) on dry slaked lime.
$3$. Baking soda $(NaHCO_3)$ is produced using $NaCl, NH_3, CO_2,$ and $H_2O$.
Slaked lime $(Ca(OH)_2)$ is produced by adding water to quicklime $(CaO)$, not from common salt.
Therefore, $(i), (ii),$ and $(iii)$ are correct.

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