GSEB 2013 Chemistry Question Paper with Answer and Solution

2 QuestionsEnglishWith Solutions

ChemistryQ12 of 2 questions

Page 1 of 1 · English

1
ChemistryEasyMCQGSEB · 2013
Electrolysis of a concentrated aqueous solution of $NaCl$ with graphite electrodes leads to what results at the anode and cathode respectively?
A
$Cl_2$ and $H_2$
B
$O_2$ and $Na$
C
$O_2$ and $H_2$
D
$Cl_2$ and $Na$

Solution

(A) In the electrolysis of a concentrated aqueous solution of $NaCl$ (brine),the ions present are $Na^+$,$Cl^-$,$H^+$,and $OH^-$.
At the anode,$Cl^-$ ions are preferentially oxidized over $OH^-$ ions due to their higher concentration,producing $Cl_2$ gas: $2Cl^- \rightarrow Cl_2 + 2e^-$.
At the cathode,$H^+$ ions are preferentially reduced over $Na^+$ ions because the reduction potential of $H^+$ is higher than that of $Na^+$,producing $H_2$ gas: $2H^+ + 2e^- \rightarrow H_2$.
Therefore,$Cl_2$ is produced at the anode and $H_2$ is produced at the cathode.
2
ChemistryEasyMCQGSEB · 2013
In a mixture of camphor in nitrogen gas,the physical states of the solute and the solvent are,respectively:
A
$gas, solid$
B
$solid, gas$
C
$solid, solid$
D
$gas, gas$

Solution

(B) solution is a homogeneous mixture of two or more components.
In this mixture,camphor is the solute (the substance being dissolved) and nitrogen gas is the solvent (the substance in which the solute is dissolved).
Camphor is a $solid$ at room temperature,and nitrogen is a $gas$.
Therefore,the physical state of the solute is $solid$ and the solvent is $gas$.

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