Without actually calculating the cubes,find t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) We use the algebraic identity: If $x + y + z = 0$,then $x^3 + y^3 + z^3 = 3xyz$.Given expression: $(31)^3 + (-16)^3 + (-15)^3$.Let $x = 31$,$y = -

Vedclass · Accepted Answer

$22320$

Vedclass · Answer

(D) We use the algebraic identity: If $x + y + z = 0$,then $x^3 + y^3 + z^3 = 3xyz$.Given expression: $(31)^3 + (-16)^3 + (-15)^3$.Let $x = 31$,$y = -16$,and $z = -15$.Check the sum: $x + y + z = 31 + (-16) + (-15) = 31 - 31 = 0$.Since the sum is $0$,the value of the expression is $3xyz$.Value $= 3 	imes (31) 	imes (-16) 	imes (-15)$.Value $= 3 	imes 31 	imes 240$.Value $= 93 	imes 240 = 22320$.

Without actually calculating the cubes,find the value of each of the following:
$(31)^{3} - (16)^{3} - (15)^{3}$

Similar Questions

$x+1$ is a factor of which of the following polynomials?

Which of the following expressions is a polynomial? State the reason. If an expression is a polynomial,state whether it is a polynomial in one variable or not: $x^{2}-15x+50$

Classify the following as linear,quadratic,or cubic polynomial: $4y + 11$.

Factorise the following:
$16 x^{2}+4 y^{2}+9 z^{2}-16 x y-12 y z+24 x z$

Evaluate the following using suitable identities: $(105)^{3}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Without actually calculating the cubes,find the value of each of the following:$(31)^{3} - (16)^{3} - (15)^{3}$