4x^{2} - 20x + 25 = (ldots ldots ldots)^{2} | vedclass

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Question

(C) To factorize the quadratic expression $4x^{2} - 20x + 25$,we observe that it follows the algebraic identity $(a - b)^{2} = a^{2} - 2ab + b^{2}$.He

Vedclass · Accepted Answer

$2x - 5$

Vedclass · Answer

(C) To factorize the quadratic expression $4x^{2} - 20x + 25$,we observe that it follows the algebraic identity $(a - b)^{2} = a^{2} - 2ab + b^{2}$.Here,$a^{2} = 4x^{2} \implies a = 2x$.Also,$b^{2} = 25 \implies b = 5$.Checking the middle term: $-2ab = -2(2x)(5) = -20x$,which matches the given expression.Therefore,$4x^{2} - 20x + 25 = (2x - 5)^{2}$.

$4x^{2} - 20x + 25 = (\ldots \ldots \ldots)^{2}$

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