x=.......... | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(a) $x^{\frac{12}{7}} 	imes x^{\frac{5}{7}} 
eq x$

(b) $\sqrt[12]{\left(x^{4}ight)^{\frac{1}{3}}}=\sqrt[12]{x^{4 x \frac{1}{3}}}=\left(x^{\frac

Vedclass · Accepted Answer

$\left(\sqrt{x^{3}}\right)^{\frac{2}{3}}$

Vedclass · Answer

(a) $x^{\frac{12}{7}} 	imes x^{\frac{5}{7}} 
eq x$

(b) $\sqrt[12]{\left(x^{4}ight)^{\frac{1}{3}}}=\sqrt[12]{x^{4 x \frac{1}{3}}}=\left(x^{\frac{4}{3}}ight)^{\frac{1}{12}}=x^{\frac{4}{3} 	imes \frac{1}{12}}=x^{\frac{1}{9}} 
eq x$

(c) $\left(\left(x^{3}ight)^{\frac{1}{2}}ight)^{\frac{2}{3}}=(x)^{\frac{3}{2} 	imes \frac{2}{3}}=x^{1}=x$

(d) $x^{\frac{12}{7}} 	imes x^{\frac{7}{12}}=x^{\frac{12}{7}+\frac{7}{12}}=x^{\frac{193}{84}} 
eq x$

Hence, (B) is the correct answer.

$x=..........$

Similar Questions

સરવાળો કરો $: 0 . \overline{3}+0.4 \overline{7}$

$p$ પૂર્ણાક હોય, $q$ શૂન્યેતર પૂર્ણાક હોય તેવા $p/q$ સ્વરૂપમાં નીચેની સંખ્યાને દર્શાવો

$0.00323232 \ldots$

નીચેનામાંથી કયું $\left[\left(\frac{5}{6}\right)^{\frac{1}{5}}\right]^{-\frac{1}{6}} $ ને સમાન નથી ?

સાદું રૂપ આપો :

$\frac{8^{\frac{1}{3}} \times 16^{\frac{1}{3}}}{32^{-\frac{1}{3}}}$