The value of $\sqrt {[12 - \sqrt {(68 + 48\sqrt 2 )} ]} = $
The value of $\sqrt {[12 - \sqrt {(68 + 48\sqrt 2 )} ]} = $
- A
$2 + \sqrt 2 $
- B
$2 - \sqrt 2 $
- C
$\sqrt 2 - 1$
- D
None of these
Similar Questions
${{{{[4 + \sqrt {(15)} ]}^{3/2}} + {{[4 - \sqrt {(15)} ]}^{3/2}}} \over {{{[6 + \sqrt {(35)} ]}^{3/2}} - {{[6 - \sqrt {(35)} ]}^{3/2}}}} = $
${{{{[4 + \sqrt {(15)} ]}^{3/2}} + {{[4 - \sqrt {(15)} ]}^{3/2}}} \over {{{[6 + \sqrt {(35)} ]}^{3/2}} - {{[6 - \sqrt {(35)} ]}^{3/2}}}} = $
The value of the fifth root of $10^{10^{10}}$ is
The value of the fifth root of $10^{10^{10}}$ is
- [KVPY 2021]
${4 \over {1 + \sqrt 2 - \sqrt 3 }} = $
${4 \over {1 + \sqrt 2 - \sqrt 3 }} = $
If ${{{{({2^{n + 1}})}^m}({2^{2n}}){2^n}} \over {{{({2^{m + 1}})}^n}{2^{2m}}}} = 1,$ then $m =$
If ${{{{({2^{n + 1}})}^m}({2^{2n}}){2^n}} \over {{{({2^{m + 1}})}^n}{2^{2m}}}} = 1,$ then $m =$
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The greatest number among $\root 3 \of 9 ,\root 4 \of {11} ,\root 6 \of {17} $ is