The value of (overrightarrow A + overrightarr | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(d)$(\vec A + \vec B) 	imes (\vec A - \vec B)$

$ = \vec A 	imes \vec A - \vec A 	imes \vec B + \vec B 	imes \vec A - \vec B 	imes \vec B$

$

Vedclass · Accepted Answer

$2(\overrightarrow B 	imes \overrightarrow A )$

Vedclass · Answer

(d)$(\vec A + \vec B) 	imes (\vec A - \vec B)$

$ = \vec A 	imes \vec A - \vec A 	imes \vec B + \vec B 	imes \vec A - \vec B 	imes \vec B$

$ = 0 - \vec A 	imes \vec B + \vec B 	imes \vec A - 0$

$ = \vec B 	imes \vec A + \vec B 	imes \vec A = 2(\vec B 	imes \vec A)$

colum $I$	colum $II$
$(A)$ $\|A+B\|$	$(p)$ $\frac{\sqrt{3}}{2} x$
$(B)$ $\|A-B\|$	$(q)$ $x$
$(C)$ $A \cdot B$	$(r)$ $\sqrt{3} x$
$(D)$ $\|A \times B\|$	$(s)$ None

The value of $(\overrightarrow A + \overrightarrow B )\, \times (\overrightarrow A - \overrightarrow B )$ is

Similar Questions

Obtain the scalar product of unit vectors in Cartesian co-ordinate system.

Two vectors $A$ and $B$ have equal magnitude $x$. Angle between them is $60^{\circ}$. Then, match the following two columns.

colum $I$ colum $II$

$(A)$ $|A+B|$ $(p)$ $\frac{\sqrt{3}}{2} x$

$(B)$ $|A-B|$ $(q)$ $x$

$(C)$ $A \cdot B$ $(r)$ $\sqrt{3} x$

$(D)$ $|A \times B|$ $(s)$ None

The resultant of $\vec{A} \times 0$ will be equal to

If $\overrightarrow A \times \overrightarrow B = \overrightarrow C + \overrightarrow D,$ then select the correct alternative-

$\overrightarrow A $ and $\overrightarrow B $ are two vectors given by $\overrightarrow A = 2\widehat i + 3\widehat j$ and $\overrightarrow B = \widehat i + \widehat j$. The magnitude of the component (projection) of $\overrightarrow A$ on $\overrightarrow B$ is