The square root of $\sqrt {(50)} + \sqrt {(48)} $ is
The square root of $\sqrt {(50)} + \sqrt {(48)} $ is
- A
${2^{1/4}}(3 + \sqrt 2 )$
- B
${2^{1/4}}(\sqrt 3 + 2)$
- C
${2^{1/4}}(2 + \sqrt 2 )$
- D
${2^{1/4}}(\sqrt 3 + \sqrt 2 )$
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If $x = \sqrt 7 + \sqrt 3 $ and $xy = 4,$then ${x^4} + {y^4}=$
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$\root 4 \of {(17 + 12\sqrt 2 )} = $
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