The solution of the equation sqrt{x + 10} + s | vedclass

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(B) Given equation: $\sqrt{x + 10} + \sqrt{x - 2} = 6$Rearranging the terms: $\sqrt{x + 10} = 6 - \sqrt{x - 2}$Squaring both sides: $x + 10 = (6 - \sq

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$6$

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(B) Given equation: $\sqrt{x + 10} + \sqrt{x - 2} = 6$Rearranging the terms: $\sqrt{x + 10} = 6 - \sqrt{x - 2}$Squaring both sides: $x + 10 = (6 - \sqrt{x - 2})^2$$x + 10 = 36 + (x - 2) - 12\sqrt{x - 2}$$x + 10 = 34 + x - 12\sqrt{x - 2}$Subtracting $x$ from both sides: $10 = 34 - 12\sqrt{x - 2}$$-24 = -12\sqrt{x - 2}$Dividing by $-12$: $2 = \sqrt{x - 2}$Squaring both sides again: $4 = x - 2$$x = 6$Verification: $\sqrt{6 + 10} + \sqrt{6 - 2} = \sqrt{16} + \sqrt{4} = 4 + 2 = 6$. This satisfies the equation.

The solution of the equation $\sqrt{x + 10} + \sqrt{x - 2} = 6$ is

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