({x^5})^{1/3} (16{x^3})^{2/3} (frac{1}{4} x^{ | vedclass

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(D) Given expression: $E = (x^5)^{1/3} (16x^3)^{2/3} (\frac{1}{4} x^{4/9})^{-3/2}$Step $1$: Simplify each term:$(x^5)^{1/3} = x^{5/3}$$(16x^3)^{2/3} =

Vedclass · Accepted Answer

None of these

Vedclass · Answer

(D) Given expression: $E = (x^5)^{1/3} (16x^3)^{2/3} (\frac{1}{4} x^{4/9})^{-3/2}$Step $1$: Simplify each term:$(x^5)^{1/3} = x^{5/3}$$(16x^3)^{2/3} = (2^4)^{2/3} (x^3)^{2/3} = 2^{8/3} x^2$$(\frac{1}{4} x^{4/9})^{-3/2} = (2^{-2})^{-3/2} (x^{4/9})^{-3/2} = 2^3 x^{-6/9} = 2^3 x^{-2/3}$Step $2$: Combine the terms:$E = x^{5/3} 	imes 2^{8/3} x^2 	imes 2^3 x^{-2/3}$$E = 2^{(8/3 + 3)} 	imes x^{(5/3 + 2 - 2/3)}$$E = 2^{17/3} 	imes x^{(3/3 + 2)} = 2^{17/3} x^3$Since $2^{17/3} x^3 
eq 8x^3$ or other options,the correct answer is None of these.

$({x^5})^{1/3} (16{x^3})^{2/3} (\frac{1}{4} x^{4/9})^{-3/2} = $

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