{{sqrt 2 } over {sqrt {(2 + sqrt 3 )} - sqrt | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(b) ${{\sqrt 2 } \over {\sqrt {2 + \sqrt 3 } - \sqrt {2 - \sqrt 3 } }} = {{\sqrt 2 \,\left( {\sqrt {2 + \sqrt 3 } + \sqrt {2 - \sqrt 3 } } \right)} \o

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(b) ${{\sqrt 2 } \over {\sqrt {2 + \sqrt 3 } - \sqrt {2 - \sqrt 3 } }} = {{\sqrt 2 \,\left( {\sqrt {2 + \sqrt 3 } + \sqrt {2 - \sqrt 3 } } \right)} \over {(2 + \sqrt 3 ) - (2 - \sqrt 3 )}}$

$ = {{\sqrt {4 + 2\sqrt 3 } + \sqrt {4 - 2\sqrt 3 } } \over {2\sqrt 3 }} = {{(\sqrt 3 + 1)\, + \,(\sqrt 3 - 1)} \over {2\sqrt 3 }} = 1$.

${{\sqrt 2 } \over {\sqrt {(2 + \sqrt 3 )} - \sqrt {(2 - \sqrt 3 } )}} = $

Similar Questions

If $a = \sqrt {(21)} - \sqrt {(20)} $ and $b = \sqrt {(18)} - \sqrt {(17),} $ then

The value of ${{15} \over {\sqrt {10} + \sqrt {20} + \sqrt {40} - \sqrt 5 - \sqrt {80} }}$ is

${a^{m{{\log }_a}n}} = $

Number of value/s of $x$ satisfy given eqution ${5^{x - 1}} + 5.{(0.2)^{x - 2}} = 26$.

If ${a^x} = bc,{b^y} = ca,\,{c^z} = ab,$ then $xyz$=