The solution of the equation $4\cos^2 x + 6\sin^2 x = 5$ is:
- A$x = n\pi \pm \frac{\pi}{2}$
- B$x = n\pi \pm \frac{\pi}{4}$
- C$x = n\pi \pm \frac{3\pi}{2}$
- DNone of these
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MediumIIT 1981
View SolutionThe number of distinct solutions of the equation $\frac{5}{4} \cos ^2 2x + \cos ^4 x + \sin ^4 x + \cos ^6 x + \sin ^6 x = 2$ in the interval $[0, 2\pi]$ is
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