The smallest positive root of the equation ta | vedclass

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Question

Let $f(x)=	an x-x$

For $0<x<\frac{\pi}{2}$

$	an x>x$

$	herefore f(x)=	an x-x$ has no roots in $\left(0, \frac{\pi}{2}ight)$

Vedclass · Accepted Answer

$\left( {\pi,\frac{3\pi }{2}} \right)$

Vedclass · Answer

Let $f(x)= an x-x$ For $0x$ $ herefore f(x)= an x-x$ has no roots in $\left(0, \frac{\pi}{2} ight)$ For $\frac{\pi}{2}0$ $ herefore f(x)=0$ has atleast one root between $\pi$ and $\frac{3 \pi}{2}$

The smallest positive root of the equation $tanx\, -\, x = 0$ lies on

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