If $\cos A\sin \left( {A - \frac{\pi }{6}} \right)$ is maximum, then the value of $A$ is equal to
$\frac{\pi }{3}$
$\frac{\pi }{4}$
$\frac{\pi }{2}$
None of these
Solve $\sin 2 x-\sin 4 x+\sin 6 x=0$
The number of solutions of the equation $2 \theta-\cos ^{2} \theta+\sqrt{2}=0$ is $R$ is equal to
The general value of $\theta $ satisfying ${\sin ^2}\theta + \sin \theta = 2$ is
If $2{\cos ^2}x + 3\sin x - 3 = 0,\,\,0 \le x \le {180^o}$, then $x =$
The equation, $sin^2 \theta - \frac{4}{{{{\sin }^3}\,\,\theta \,\, - \,\,1}} = 1$$ -\frac{4}{{{{\sin }^3}\,\,\theta \,\, - \,\,1}}$ has :