The reaction $2 NO + Br _2 \rightarrow 2 NOBr$
takes places through the mechanism given below :
$NO + Br _2 \Leftrightarrow NOBr _2 \text { (fast) }$
$NOBr _2+ NO \rightarrow 2 NOBr \text { (slow) }$
The overall order of the reaction is $.....$.
$4$
$3$
$5$
$6$
The three experimental data for determine the differential rate of reaction $Cl _{2( g )} + 2NO _{( g )} \rightarrow 2 NOCl_{( g )}$ at $310\, K$ temperature.
$(a)$ Derive differential rate of reaction.
$(b)$ Calculate order of reaction.
$(c)$ Calculate value of rate constant.
The rate law of the reaction $2{N_2}{O_5} \to 4N{O_2} + {O_2}$ is
The reaction $CH _{3} COF + H _{2} O \quad \rightleftharpoons CH _{3} COOH + HF$
Condition $I$ $:$ $\left[ H _{2} O \right]_{0}=1.00 \,M$
$\left[ CH _{3} COF \right]_{0}=0.01 \,M$
Condition $II$ $:$ $\left[ H _{2} O \right]_{0}=0.02 \,M$
$\left[ CH _{3} COF \right]_{0}=0.80 \,M$
Condition - $I$ | Condition - $II$ | ||
Time $min$ |
$\left[ CH _{3} COF \right]$ $M$ |
Time $min$ |
$\left[ H _{2} O \right] \,M$ |
$0$ | $0.01000$ | $0$ | $0.0200$ |
$10$ | $0.00867$ | $10$ | $0.0176$ |
$20$ | $0.00735$ | $20$ | $0.0156$ |
$40$ | $0.00540$ | $40$ | $0.0122$ |
Determine the order of reaction and calculate rate constant.
${A_2} + {B_2} \to 2AB;R.O.R = k{[{A_2}]^a}{[{B_2}]^b}$
Initial $[A_2]$ | Initial $[B_2]$ | $R.O.R.\,(r)\,Ms^{-1}$ |
$0.2$ | $0.2$ | $0.04$ |
$0.1$ | $0.4$ | $0.04$ |
$0.2$ | $0.4$ | $0.08$ |
Order of reaction with respect to $A_2$ and $B_2$ are respectively
The dimension of rate constant of a second order reaction involves