The rate law of the reaction $2{N_2}{O_5} \to 4N{O_2} + {O_2}$ is
$r = K[{N_2}{O_5}]$
$r = K{[{N_2}{O_5}]^2}$
$r = K{[{N_2}{O_5}]^0}$
$r = K{[N{O_2}]^4}[{O_2}]$
Rate constant of reaction is $1.388 \times 10^{-3}\, mole^{-2}\,lit^{-2}\,sec^{-1}$ order of reaction will be
Hydrolysis of methyl acetate in aq. solution has been studied by titrating the liberated acetic acid against solidum hydroxide. The conc. of the ester at different time is given below :
Time $(t)$ $\min$ | $0$ | $30$ | $60$ | $90$ |
Con. of ester $(C)$ |
$0.850$ | $0.800$ | $0.754$ |
$0.710$ |
Show that it follows a pseudo first order reaction as the conc. of $H_2O$ remain nearly constant $(54.2\,mol\,L^{-1})$ during the course of the reaction. What is the value of $k'$ in this reaction ?
For the following rate law determine the unit of rate constant. Rate $=-\frac{d[ R ]}{d t}=k[ A ]^{\frac{1}{2}}[ B ]^{2}$
In the reaction $2A + B \to {A_2}B$, if the concentration of $A$ is doubled and of $B$ is halved, then the rate of the reaction will
For a certain reaction $A \to P$ , the half life for different initial concentration of $A$ is mentioned below
$[A_0]$ $||$ $0.1$ $||$ $0.025$
$t_{1/2}(s)$ $||$ $100$ $||$ $50$
Which of the following option $(s)$ is / are correct