${A_2} + {B_2} \to 2AB;R.O.R = k{[{A_2}]^a}{[{B_2}]^b}$
Initial $[A_2]$ | Initial $[B_2]$ | $R.O.R.\,(r)\,Ms^{-1}$ |
$0.2$ | $0.2$ | $0.04$ |
$0.1$ | $0.4$ | $0.04$ |
$0.2$ | $0.4$ | $0.08$ |
Order of reaction with respect to $A_2$ and $B_2$ are respectively
$a = 1, b = 1$
$a = 2, b = 0$
$a = 2, b = 1$
None
Write about elementary and complex reactions.
Reaction rate between two substance $A$ and $B$ is expressed as following $:$ rate $= k[A ]^n[B]^m$ If the concentration of $A$ is doubled and concentration of $B$ is made half of initial concentration, the ratio of the new rate to the earlier rate will be
The order of a reaction is said to be $ 2 $ with respect to a reactant $X, $ when
The rate of disappearance of $S{O_2}$ in the reaction $2S{O_2} + {O_2} \to 2S{O_3}$ is $1.28 \times {10^{ - 3}}g/sec$ then the rate of formation of $S{O_3}$ is
Consider the kinetic data given in the following table for the reaction $A + B + C \rightarrow$ Product.
Experiment No. | $\begin{array}{c}{[ A ]} \\ \left( mol dm ^{-3}\right)\end{array}$ | $\begin{array}{c}{[ B ]} \\ \left( mol dm ^{-3}\right)\end{array}$ | $\begin{array}{c}{[ C]} \\ \left( mol dm ^{-3}\right)\end{array}$ | Rate of reaction $\left( mol dm ^{-3} s ^{-1}\right)$ |
$1$ | $0.2$ | $0.1$ | $0.1$ | $6.0 \times 10^{-5}$ |
$2$ | $0.2$ | $0.2$ | $0.1$ | $6.0 \times 10^{-5}$ |
$3$ | $0.2$ | $0.1$ | $0.2$ | $1.2 \times 10^{-4}$ |
$4$ | $0.3$ | $0.1$ | $0.1$ | $9.0 \times 10^{-5}$ |
The rate of the reaction for $[ A ]=0.15 mol dm ^{-3},[ B ]=0.25 mol dm ^{-3}$ and $[ C ]=0.15 mol dm ^{-3}$ is found to be $Y \times 10^{-5} mol dm d ^{-3} s ^{-1}$. The value of $Y$ i. . . . . . .