The general value of theta in the equation 2 | vedclass

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Question

(c) $2\sqrt 3 {\cos ^2}	heta = \sin 	heta $

==> $2\sqrt 3 {\sin ^2}	heta + \sin 	heta - 2\sqrt 3 = 0$

==> $\sin 	heta = \frac{{ - 1 \

Vedclass · Accepted Answer

$n\pi + {( - 1)^n}\frac{\pi }{3}$

Vedclass · Answer

(c) $2\sqrt 3 {\cos ^2}	heta = \sin 	heta $

==> $2\sqrt 3 {\sin ^2}	heta + \sin 	heta - 2\sqrt 3 = 0$

==> $\sin 	heta = \frac{{ - 1 \pm 7}}{{4\sqrt 3 }}$

$\Rightarrow \sin 	heta = \frac{{ - 8}}{{4\sqrt 3 }}{m{,}}$ (Impossible)

and $\sin 	heta = \frac{6}{{4\sqrt 3 }} = \frac{{\sqrt 3 }}{2}$

==> $	heta = n\pi + {( - 1)^n}\frac{\pi }{3}$.

The general value of $\theta $ in the equation $2\sqrt 3 \cos \theta = \tan \theta $, is

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