The converse of the statement $((\sim p) \wedge q) \Rightarrow r$ is
- A$(\sim r) \Rightarrow ((\sim p) \wedge q)$
- B$r \Rightarrow ((\sim p) \wedge q)$
- C$r \Rightarrow (p \vee (\sim q))$
- D$(p \vee (\sim q)) \Rightarrow (\sim r)$
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The expression $(p \wedge \sim q) \vee q \vee (\sim p \wedge q)$ is equivalent to
Let $S$ be a non-empty subset of $R$. Consider the statement $p : x \in S$ is a rational number such that $x > 0$. Which of the following is the negation of $p$?
Medium
View SolutionThe contrapositive of the statement,"If two lines do not intersect in the same plane,then they are parallel," is:
The correct simplified circuit diagram for the logical statement $[\{q \wedge (\sim q \vee r)\} \wedge \{\sim p \vee (p \wedge \sim r)\}] \vee (p \wedge r)$ where $p, q, r$ represent switches $S_1, S_2, S_3$ respectively.
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View SolutionIf the truth value of the expression $[(p \vee q) \wedge (q$ $\rightarrow r) \wedge (\sim r)]$ $\rightarrow (p \wedge q)$ is False,then the truth values of $p, q, r$ are respectively:
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