$(p \to q) \leftrightarrow (q\ \vee \sim p)$ is
Equivalent to $p \wedge q$
Tautology
Fallacy
Neither tautology nor fallacy
Let,$p$ : Ramesh listens to music.
$q :$ Ramesh is out of his village
$r :$ It is Sunday
$s :$ It is Saturday
Then the statement "Ramesh listens to music only if he is in his village and it is Sunday or Saturday"can be expressed as.
The Boolean expression $\left(\sim\left(p^{\wedge} q\right)\right) \vee q$ is equivalent to
The statement $p \to ( q \to p)$ is equivalent to
The statement $(p \wedge(\sim q) \vee((\sim p) \wedge q) \vee((\sim p) \wedge(\sim q))$ is equivalent to
Statement $\quad(P \Rightarrow Q) \wedge(R \Rightarrow Q)$ is logically equivalent to