Solution of the equation ${9^x} - {2^{x + {1 \over 2}}} = {2^{x + {3 \over 2}}} - {3^{2x - 1}}$

  • A

    ${\log _9}(9/\sqrt 8 )$

  • B

    ${\log _{\left( {9/2} \right)}}(9/\sqrt 8 )$

  • C

    ${\log _e}(9/\sqrt 8 )$

  • D

    None of these

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