${{3\sqrt 2 } \over {\sqrt 6 + \sqrt 3 }} - {{4\sqrt 3 } \over {\sqrt 6 + \sqrt 2 }} + {{\sqrt 6 } \over {\sqrt 3 + \sqrt 2 }} = $

  • A

    $5\sqrt 2 $

  • B

    $3\sqrt 2 $

  • C

    $2\sqrt 3 $

  • D

    $0$

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