Obtain the scalar product of two mutually perpendicular vectors.
Obtain the scalar product of two mutually perpendicular vectors.
$\text { If } \vec{A} \perp \vec{B}, \text { then } \theta=90^{\circ}$
$\therefore \quad \vec{A} \cdot \vec{B}=\mathrm{ABcos} 90^{\circ}$
$=0$
$\because \cos 90^{\circ}=0$
This is the condition for mutually perpendicular of two non-zero vectors.
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